Chapter 11: Problem 21
Which member in each pair has the greater dispersion forces? (a) \(\mathrm{CH}_{3} \mathrm{OH}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},(\mathbf{b}) \mathrm{NH}_{3}\) or \(\mathrm{N}\left(\mathrm{CH}_{3}\right)_{3},\) (c) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) or \(\mathrm{CH}_{2} \mathrm{Br}_{2}\).
Short Answer
Step by step solution
Define Dispersion Forces
Compare Dispersion Forces in (a)
Compare Dispersion Forces in (b)
Compare Dispersion Forces in (c)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intermolecular Forces
- London Dispersion Forces
- Dipole-Dipole Interactions
- Hydrogen Bonds
London Dispersion Forces
- Size of the Molecule: Larger molecules with higher electron counts exhibit stronger dispersion forces. This is because more electrons mean a larger dispersion in electron clouds, leading to more significant temporary dipole interactions.
- Shape of the Molecule: Molecules with greater surface area can exhibit stronger dispersion forces due to potential for more contact between molecules.