/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Describe the intermolecular forc... [FREE SOLUTION] | 91Ó°ÊÓ

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Describe the intermolecular forces that must be overcome to convert these substances from a liquid to a gas: (a) \(\mathrm{CF}_{4}\) (b) \(\mathrm{NH}_{3}\), (c) \(\mathrm{BCl}_{3}\)

Short Answer

Expert verified
(a) London dispersion forces; (b) hydrogen bonding and dipole-dipole forces; (c) London dispersion forces.

Step by step solution

01

Identify the Type of Intermolecular Forces in Each Substance

For (a) \( \mathrm{CF}_{4} \) is a non-polar molecule due to its symmetrical tetrahedral shape, so the intermolecular forces are primarily London dispersion forces. For (b) \( \mathrm{NH}_{3} \), which is a polar molecule with a significant electronegativity difference between N and H, hydrogen bonds and dipole-dipole interactions are present. Finally, for (c) \( \mathrm{BCl}_{3} \) is a non-polar molecule because of its trigonal planar geometry, so it primarily experiences London dispersion forces.
02

Analyze the Strength of the Intermolecular Forces

London dispersion forces, present in \( \mathrm{CF}_{4} \) and \( \mathrm{BCl}_{3} \), are relatively weak forces that occur between non-polar molecules. Hydrogen bonds, present in \( \mathrm{NH}_{3} \), are the strongest type of van der Waals forces and considerably stronger than London dispersion forces. Dipole-dipole interactions also contribute to \( \mathrm{NH}_{3} \)'s boiling point, albeit weaker than hydrogen bonds.
03

Identify the Intermolecular Forces to Overcome for Phase Change

To convert a substance from liquid to gas, the intermolecular forces between the molecules must be overcome. For \( \mathrm{CF}_{4} \) and \( \mathrm{BCl}_{3} \), London dispersion forces must be overcome. For \( \mathrm{NH}_{3} \), both hydrogen bonding and dipole-dipole forces must be overcome due to its polar nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phase Change
When a substance undergoes a phase change from liquid to gas, it involves a fascinating process of energy transformation. During this change of phase, the molecules within the liquid need to gain enough energy to overcome the intermolecular forces keeping them in the liquid state.
The degree and type of these forces dictate how much energy is required for this transition. For example, when \( \mathrm{NH}_{3} \) changes to a gas, hydrogen bonds, which are strong intermolecular forces, need to be disrupted. Both hydrogen bonds and dipole-dipole interactions are at play here.
Understanding these energy requirements is crucial because it informs us about the boiling or vaporization point of the liquid. In general, liquids with strong intermolecular forces have higher boiling points because more energy is required to separate the molecules.
London Dispersion Forces
London dispersion forces are the weakest type of intermolecular forces. They exist between all atoms and molecules, regardless of their polarity. However, they are the only intermolecular forces acting between non-polar molecules, like \( \mathrm{CF}_{4} \) and \( \mathrm{BCl}_{3} \).
These forces arise due to the momentary fluctuations in electron distribution within atoms or molecules, leading to temporary dipoles. These temporary dipoles, although brief, influence neighboring molecules and induce dipoles in them, creating an attractive force.
Despite their relative weakness, London dispersion forces are significant when dealing with large, heavy molecules where the electron clouds are more easily polarizable, hence increasing the strength of the forces. This means that even these weak forces can affect the boiling and melting points of a substance.
Hydrogen Bonding
Hydrogen bonding represents one of the strongest types of intermolecular forces, but they only occur under specific circumstances. These forces form when hydrogen is covalently bonded to highly electronegative atoms like nitrogen, oxygen, or fluorine.
In the case of \( \mathrm{NH}_{3} \), hydrogen bonds result from hydrogen atoms bonding to nitrogen atoms within different \( \mathrm{NH}_{3} \) molecules. These strong attractions lead to a significant elevation in the boiling point of \( \mathrm{NH}_{3} \) compared to compounds with only London dispersion or dipole-dipole interactions.
Hydrogen bonds are essential in various biological molecules as well, playing a critical role in the structures of proteins and DNA. Their strength explains why \( \mathrm{NH}_{3} \), despite being a light molecule, has remarkably high boiling points for its molecular weight.
Dipole-Dipole Interactions
Dipole-dipole interactions are a type of intermolecular force that occurs between polar molecules, where there is a permanent separation of charge. In these molecules, one end is slightly negative, and the other end is slightly positive, leading to an attraction between the opposite charges of different molecules.
These interactions contribute to the overall intermolecular forces in substances like \( \mathrm{NH}_{3} \), where polarization occurs due to a significant electronegativity difference. Although weaker than hydrogen bonds, they still play a role in determining the physical properties of polar substances.
The sum of hydrogen bonding and dipole-dipole interactions in \( \mathrm{NH}_{3} \) leads to its higher boiling point when compared to non-polar substances. These polar interactions are indispensable in moderate molecular association, playing a key role in the behavior and properties of complex compounds.

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