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(a) What are the mole fractions of each component in a mixture of \(15.08 \mathrm{~g}\) of \(\mathrm{O}_{2}, 8.17 \mathrm{~g}\) of \(\mathrm{N}_{2},\) and \(2.64 \mathrm{~g}\) of \(\mathrm{H}_{2} ?\) (b) What is the partial pressure in atm of each component of this mixture if it is held in a 15.50-L vessel at \(15^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
Mole fractions: \(x_{O_2} = 0.2277\), \(x_{N_2} = 0.1409\), \(x_{H_2} = 0.6314\). Partial pressures: \(P_{O_2} = 0.718 \text{ atm}\), \(P_{N_2} = 0.444 \text{ atm}\), \(P_{H_2} = 1.992 \text{ atm}\).

Step by step solution

01

Calculate Moles of Each Gas

To find the moles, use the formula: \( n = \frac{m}{M} \), where \( m \) is the mass and \( M \) is the molar mass of the gas. The molar masses are: \( O_2 = 32.00 \text{ g/mol} \), \( N_2 = 28.02 \text{ g/mol} \), \( H_2 = 2.02 \text{ g/mol} \). \( n_{O_2} = \frac{15.08 \text{ g}}{32.00 \text{ g/mol}} = 0.47125 \text{ mol} \), \( n_{N_2} = \frac{8.17 \text{ g}}{28.02 \text{ g/mol}} = 0.2916 \text{ mol} \), \( n_{H_2} = \frac{2.64 \text{ g}}{2.02 \text{ g/mol}} = 1.30693 \text{ mol} \).
02

Total Moles in the Mixture

Add the moles of each gas: \( n_{\text{total}} = n_{O_2} + n_{N_2} + n_{H_2} = 0.47125 + 0.2916 + 1.30693 = 2.06978 \text{ mol} \).
03

Calculate Mole Fractions

Mole fraction \( x_i \) is calculated as \( x_i = \frac{n_i}{n_{\text{total}}} \). For \( O_2: x_{O_2} = \frac{0.47125}{2.06978} = 0.2277 \). For \( N_2: x_{N_2} = \frac{0.2916}{2.06978} = 0.1409 \). For \( H_2: x_{H_2} = \frac{1.30693}{2.06978} = 0.6314 \).
04

Calculate Total Pressure using Ideal Gas Law

First, convert temperature to Kelvin: \( 15^\circ C = 273.15 + 15 = 288.15 K \). Then use the Ideal Gas Law: \( PV = nRT \). Rearrange to find \( P: P = \frac{nRT}{V} \), using \( R = 0.0821 \text{ L atm K}^{-1} \text{mol}^{-1} \). Thus, \( P = \frac{2.06978 \times 0.0821 \times 288.15}{15.50} = 3.154 \text{ atm} \).
05

Calculate Partial Pressures

Multiply the mole fraction of each gas by the total pressure to find partial pressure. For \( O_2: P_{O_2} = x_{O_2} \times P_{\text{total}} = 0.2277 \times 3.154 = 0.718 \text{ atm} \). For \( N_2: P_{N_2} = 0.1409 \times 3.154 = 0.444 \text{ atm} \). For \( H_2: P_{H_2} = 0.6314 \times 3.154 = 1.992 \text{ atm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
Partial pressure is a critical concept in understanding mixtures of gases. It describes the contribution each gas exerts on the total pressure of a mixture. When you have several gases sharing a container, each gas behaves as if it occupies the space alone, even though they are actually mixed. This pressure exerted by an individual gas in a mixture is known as partial pressure.
To calculate the partial pressure of a specific gas, you can use the formula:
  • \( P_i = x_i \times P_{\text{total}} \)
where \( P_i \) is the partial pressure of gas \( i \), \( x_i \) is its mole fraction, and \( P_{\text{total}} \) is the total pressure of the gas mixture.
In this exercise, you multiplied each gas's mole fraction by the calculated total pressure, demonstrating how each component contributes to the mixture's overall pressure. This helps to illustrate the behavior of gases according to Dalton's Law of Partial Pressures.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry that relates the pressure, volume, temperature, and number of moles of an ideal gas. It is expressed as:
  • \( PV = nRT \)
In this equation, \( P \) stands for pressure, \( V \) for volume, \( n \) for the number of moles, \( R \) is the ideal gas constant \((0.0821 \ \text{L atm K}^{-1} \text{mol}^{-1})\), and \( T \) is the temperature in Kelvin.
When analyzing gas mixtures, the Ideal Gas Law comes in handy to determine the total pressure of the gases within a set volume. We used this equation to find the total pressure in the vessel by plugging in the total moles of gases, temperature in Kelvin, and the volume of the container. This application helps us understand how gases behave under different conditions of temperature and volume.
Molar Mass
Molar mass is the mass of one mole of a substance, typically measured in grams per mole (g/mol). It is a crucial factor in converting between the mass of a substance and the amount of substance present in moles. This conversion is essential because gases are often measured in moles rather than grams when using equations like the Ideal Gas Law.
For example, in this exercise, we began by calculating the number of moles for each gas using their respective masses and molar masses. The formula for this conversion is:
  • \( n = \frac{m}{M} \)
where \( n \) represents the number of moles, \( m \) is the mass in grams, and \( M \) is the molar mass. This step is vital as it allows us to work with amounts of gases quantitatively in subsequent calculations, like determining mole fractions or total pressure.
Mixture of Gases
A mixture of gases refers to a collection of several gases sharing the same physical space but not chemically reacting with each other. Each gas retains its own properties and influences the overall behavior of the mixture.When you deal with gas mixtures, it's crucial to calculate specific properties like mole fractions and partial pressures. The mole fraction \((x_i)\) of each gas is calculated as the ratio of the number of moles of that gas to the total moles of all gases present:
  • \( x_i = \frac{n_i}{n_{\text{total}}} \)
This fractional representation helps understand the composition of gases in the mixture.
In the exercise, after calculating the moles of \( O_2, N_2, \) and \( H_2 \), their individual influences on the total mixture were understood through their mole fractions. These fractions are crucial for calculating individual partial pressures, illustrating how each gas's presence impacts total pressure within a shared volume.

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Most popular questions from this chapter

You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. Measuring the pressure at constant temperature over time, you are surprised to see it slowly dropping. You measure the mass of the gas-filled container and find that the mass is what it should be-gas plus container-and the mass does not change over time, so you do not have a leak. Suggest an explanation for your observations.

You have a sample of gas at \(0^{\circ} \mathrm{C}\). You wish to increase the rms speed by a factor of 3 . To what temperature should the gas be heated?

Ammonia and hydrogen chloride react to form solid ammonium chloride: $$ \mathrm{NH}_{3}(g)+\mathrm{HCl}(g) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(s) $$ Two 2.00-L flasks at \(25^{\circ} \mathrm{C}\) are connected by a valve, as shown in the drawing. One flask contains \(5.00 \mathrm{~g}\) of \(\mathrm{NH}_{3}(g)\), and the other contains \(5.00 \mathrm{~g}\) of \(\mathrm{HCl}(g)\). When the valve is opened, the gases react until one is completely consumed. (a) Which gas will remain in the system after the reaction is complete? (b) What will be the final pressure of the system after the reaction is complete? (Neglect the volume of the ammonium chloride formed.) (c) What mass of ammonium chloride will be formed?

In an experiment reported in the scientific literature, male cockroaches were made to run at different speeds on a miniature treadmill while their oxygen consumption was measured. In 30 minutes the average cockroach (running at \(0.08 \mathrm{~km} / \mathrm{h})\) consumed \(1.0 \mathrm{~mL}\) of \(\mathrm{O}_{2}\) at \(101.33 \mathrm{kPa}\) pressure and \(20^{\circ} \mathrm{C}\) per gram of insect mass. (a) How many moles of \(\mathrm{O}_{2}\) would be consumed in 1 day by a 6.3 -g cockroach moving at this speed? (b) This same cockroach is caught by a child and placed in a 2.0-L fruit jar with a tight lid. Assuming the same level of continuous activity as in the research, how much of the available \(\mathrm{O}_{2}\) will the cockroach consume in 1 day? (Air is \(21 \mathrm{~mol} \% \mathrm{O}_{2}\).)

A fixed quantity of gas at \(25^{\circ} \mathrm{C}\) exhibits a pressure of \(99 \mathrm{kPa}\) and occupies a volume of \(4.00 \mathrm{~L}\). (a) Calculate the volume the gas will occupy if the pressure is increased to \(202.6 \mathrm{kPa}\) whilethe temperature is held constant. (b) Calculate the volume the gas will occupy if the temperature is increased to \(100^{\circ} \mathrm{C}\) while the pressure is held constant.

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