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A deep-sea diver uses a gas cylinder with a volume of \(10.0 \mathrm{~L}\) and a content of \(51.2 \mathrm{~g}\) of \(\mathrm{O}_{2}\) and \(32.6 \mathrm{~g}\) of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is \(19^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The partial pressure of \(\mathrm{O}_2\) is approximately 3.75 atm, \(\mathrm{He}\) is approximately 19.14 atm, and the total pressure is approximately 22.89 atm.

Step by step solution

01

Convert Temperature to Kelvin

To work with gases, temperature should be in Kelvin. Convert the temperature from Celsius to Kelvin using the formula: \(T(K) = T(C) + 273.15\). So, \(T = 19 + 273.15 = 292.15\, K\).
02

Calculate Moles of Each Gas

Use the molar mass to convert grams to moles. The molar mass of \(\mathrm{O}_2\) is \(32.00\, g/mol\) and for \(\mathrm{He}\) it's \(4.00\, g/mol\). Calculate moles: \[\text{Moles of } \mathrm{O}_2 = \frac{51.2}{32.00} = 1.60\, mol\] \[\text{Moles of He} = \frac{32.6}{4.00} = 8.15\, mol\]
03

Use Ideal Gas Law to Find Total Pressure

The ideal gas law \(PV = nRT\) will help find total pressure. \(n\) is the total moles (sum of moles of \(\mathrm{O}_2\) and \(\mathrm{He}\)), \(R\) is the gas constant \(0.0821\, L\, atm\, mol^{-1}\, K^{-1}\), \(V = 10.0\, L\), \(T = 292.15\, K\). Calculate total pressure: \[P = \frac{(1.60 + 8.15) \times 0.0821 \times 292.15}{10.0} \approx 22.89\, atm\]
04

Calculate Partial Pressure Using Mole Fraction

Partial pressure of a gas can be found using its mole fraction and the total pressure: \(P_{\text{gas}} = X_{\text{gas}} \times P_{\text{total}}\). Calculate mole fractions: \[X_{\mathrm{O}_2} = \frac{1.60}{1.60 + 8.15} = 0.164\] \[X_{\mathrm{He}} = \frac{8.15}{1.60 + 8.15} = 0.836\] Now calculate partial pressures: \[P_{\mathrm{O}_2} = 0.164 \times 22.89 \approx 3.75\, atm\] \[P_{\mathrm{He}} = 0.836 \times 22.89 \approx 19.14\, atm\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
In a mixture of gases, each individual gas contributes to the total pressure. This contribution is known as the partial pressure. To determine the partial pressure of a gas in a mixture, you can use the formula:
  • \( P_{\text{gas}} = X_{\text{gas}} \times P_{\text{total}} \)
where \( P_{\text{gas}} \) is the partial pressure of the gas, \( X_{\text{gas}} \) is the mole fraction, and \( P_{\text{total}} \) is the total pressure of the gas mixture.
Partial pressure is a useful concept in chemistry and physics to predict the behavior of gases in a mixture without considering their identities. It simplifies complex calculations and helps in understanding the contributions each gas makes to the overall pressure.
For example, in our problem, the partial pressures were calculated for oxygen (\( \mathrm{O}_2 \)) and helium (He) using their mole fractions.
Mole Fraction
Mole fraction is a way of expressing the concentration of a component in a mixture of gases. It is defined as the number of moles of a specific gas divided by the total number of moles of all gases present. The formula for mole fraction is:
  • \( X_{\text{gas}} = \frac{n_{\text{gas}}}{n_{\text{total}}} \)
where \( n_{\text{gas}} \) is the moles of the gas of interest, and \( n_{\text{total}} \) is the total moles of all gases in the mixture.
Mole fractions are always dimensionless numbers between 0 and 1. They provide an understanding of how much of each gas is present compared to others in the mixture.
In the diving exercise you'll notice the mole fraction provided important insights about how each gas contributed to the total pressure, allowing the calculation of partial pressures for \( \mathrm{O}_2 \) and He.
Temperature Conversion
Temperature conversion is crucial in gas law equations to ensure that all calculations are consistent and accurate. The ideal gas law and other gas-related equations require temperature to be in Kelvin, an absolute temperature scale.
The conversion from Celsius to Kelvin is straightforward, using the equation:
  • \( T(K) = T(°C) + 273.15 \)
For example, in the exercise, the temperature conversion was necessary to correctly apply the ideal gas law, converting \(19^{\circ} \text{C}\) to \(292.15 \, K\).
This conversion ensures that all scientists and engineers use the same scale, eliminating discrepancies in calculations that could arise if different temperature scales were used.
Molar Mass
Molar mass is a measure of the mass of one mole of a substance, often expressed in grams per mole (g/mol). It plays a key role in converting between the mass of a gas and the amount in moles, which is vital for applying the ideal gas law.
To calculate moles from a given mass:
  • \( n = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \)
In our example, the molar masses of \( \mathrm{O}_2 \) and He were used to determine their respective moles: 1.60 moles for \( \mathrm{O}_2 \) and 8.15 moles for He.
Understanding molar mass allows you to effectively interconvert between the tangible mass of a gas and the abstract concept of moles, aligning with the requirements of the ideal gas law and ensuring accurate pressure calculations.

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Most popular questions from this chapter

When a large evacuated flask is filled with argon gas, its mass increases by \(3.224 \mathrm{~g}\). When the same flask is again evacuated and then filled with a gas of unknown molar mass, the mass increase is \(8.102 \mathrm{~g}\). (a) Based on the molar mass of argon, estimate the molar mass of the unknown gas. (b) What assumptions did you make in arriving at your answer?

The molar mass of a volatile substance was determined by the Dumas-bulb method described in Exercise 10.53 . The unknown vapor had a mass of \(2.55 \mathrm{~g} ;\) the volume of the bulb was \(500 \mathrm{~mL}\), pressure \(101.33 \mathrm{kPa}\), and temperature \(37^{\circ} \mathrm{C} .\) Calculate the molar mass of the unknown vapor.

A 6.0-L tank is filled with helium gas at a pressure of 2 MPa. How many balloons (each \(2.00 \mathrm{~L}\) ) can be inflated to a pressure of \(101.3 \mathrm{kPa}\), assuming that the temperature remains constant and that the tank cannot be emptied below \(101.3 \mathrm{kPa}\) ?

The temperature of a 5.00-L container of \(\mathrm{N}_{2}\) gas is increased from \(20^{\circ} \mathrm{C}\) to \(250^{\circ} \mathrm{C}\). If the volume is held constant, predict qualitatively how this change affects the following: (a) the average kinetic energy of the molecules; \((\mathbf{b})\) the rootmean- square speed of the molecules; (c) the strength of the impact of an average molecule with the container walls; d) the total number of collisions of molecules with walls per second.

A 500 mL incandescent light bulb is filled with \(1.5 \times 10^{-5}\) mol of xenon to minimize the rate of evaporation of the tungsten filament. What is the pressure of xenon in the light bulb at \(25^{\circ} \mathrm{C} ?\)

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