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The Goodyear blimps, which frequently fly over sporting events, hold approximately \(4955 \mathrm{~m}^{3}\) of helium. If the gas is at \(23^{\circ} \mathrm{C}\) and \(101.33 \mathrm{kPa}\), what mass of helium is in a blimp?

Short Answer

Expert verified
The mass of helium in the blimp is approximately 818.08 kg.

Step by step solution

01

Understand the Given Data and Problem

We are asked to find the mass of helium in a Goodyear blimp. We know the volume of the helium gas is \( 4955 \, \text{m}^3 \), the temperature \( T \) is \( 23^{\circ} \text{C} \), and the pressure \( P \) is \( 101.33 \, \text{kPa} \). We want to use the Ideal Gas Law to find the number of moles of helium first.
02

Convert Temperatures to Kelvin

In ideal gas law calculations, temperatures must be in Kelvin. The conversion from Celsius to Kelvin is given by \( T(K) = T(^{\circ}C) + 273.15 \). So the temperature in Kelvin is \( 23 + 273.15 = 296.15 \text{ K} \).
03

Use the Ideal Gas Law to Find Moles of Helium

The Ideal Gas Law is \( PV = nRT \), where \( R \) is the universal gas constant \( 8.314 \text{ J/mol} \cdot \text{K} \). First, ensure pressure is in pascals: \( 101.33 \times 10^3 \text{ Pa} \). Solving for \( n \) (moles of helium):\[ n = \frac{PV}{RT} = \frac{101.33 \times 10^3 \times 4955}{8.314 \times 296.15} \].
04

Calculate the Number of Moles

Calculate the value:\[ n \approx \frac{101330 \times 4955}{8.314 \times 296.15} \approx 204519.8 \, \text{moles} \]
05

Convert Moles to Mass Using Molar Mass of Helium

The molar mass of helium is \( 4.00 \text{ g/mol} \). Mass \( m \) is given by the equation \( m = n \times \text{molar mass} \). Thus, the mass of helium is:\[ m = 204519.8 \times 4.00 \]
06

Calculate the Mass of Helium

Performing the multiplication:\[ m \approx 204519.8 \times 4.00 = 818079.2 \text{ g} \]Convert grams to kilograms (since 1 kg = 1000 g):\[ 818079.2 \text{ g} = 818.08 \text{ kg} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Molar mass is a fundamental concept in chemistry that relates the mass of a given substance to the amount of substance in moles. It is defined as the mass of one mole of a substance and is typically expressed in grams per mole (g/mol). For helium, the molar mass is quite straightforward: helium, being an inert gas with an atomic number of 2, has a molar mass of 4.00 g/mol. This is because each helium atom consists of a nucleus with 2 protons and typically 2 neutrons, with electrons orbiting this nucleus.

When we calculate the mass of a gas in a given volume under certain conditions (like in the blimp exercise), we first find how many moles of gas we have. We do this by applying the Ideal Gas Law. Once we have the number of moles, converting to mass using the molar mass is simple: just multiply the number of moles by the molar mass of the gas. In our case, after determining there are approximately 204,520 moles of helium in the blimp, we multiply by the molar mass of helium to find the total mass.
Temperature Conversion
Converting temperatures from Celsius to Kelvin is an essential step in many scientific calculations, especially when working with gas laws. Celsius is great for everyday use, but Kelvin is a "scientific temperature scale" that begins at absolute zero, the point at which all molecular motion stops.

The conversion is straightforward: simply add 273.15 to your Celsius temperature to convert it to Kelvin. This is due to the fact that absolute zero on the Celsius scale is -273.15°C. Therefore, 0 K is -273.15°C, and 273.15 K is the equivalent of 0°C. For example, to convert 23°C to Kelvin, you add 273.15, resulting in 296.15 K.

Using Kelvin is crucial because the Ideal Gas Law - involving relationships between temperature, pressure, volume, and moles - relies on absolute temperatures to maintain consistent proportionality between these variables. This uniformity is why temperature conversion is a foundational step in solving gas-related chemistry problems.
Blimp Buoyancy
Blimp buoyancy is a fascinating application of principles in physics and chemistry, specifically relating to gases. The buoyancy of a blimp, such as those used by Goodyear, is achieved through the use of lighter-than-air gases. Helium is a common choice because it's a non-reactive, lighter gas that provides the necessary lift to allow the blimp to float in the air.

The essential principle here relates to the concept of density. The air-filled volume within the blimp must be less dense than the surrounding atmospheric air to create lift. By filling a blimp with a light gas such as helium, its average density is reduced. Thus, buoyancy is achieved according to Archimedes' principle, which states that an object will float if it is less dense than the fluid it displaces.

Understanding both the chemical properties of helium and the physical principles of buoyancy explains why we use these gases. Helium's low molar mass makes it a particularly effective choice, ensuring the blimp maintains its buoyancy while being safe and non-flammable compared to other lighter gases like hydrogen.

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Most popular questions from this chapter

Propane, \(\mathrm{C}_{3} \mathrm{H}_{8}\), liquefies under modest pressure, allowing a large amount to be stored in a container. (a) Calculate the number of moles of propane gas in a 20 -L container at \(709.3 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C} .\) (b) Calculate the number of moles of liquid propane that can be stored in the same volume if the density of the liquid is \(0.590 \mathrm{~g} / \mathrm{mL}\). (c) Calculate the ratio of the number of moles of liquid to moles of gas. Discuss this ratio in light of the kinetic-molecular theory of gases.

A person weighing \(75 \mathrm{~kg}\) is standing on a threelegged stool. The stool momentarily tilts so that the entire weight is on one foot. If the contact area of each foot is \(5.0 \mathrm{~cm}^{2},\) calculate the pressure exerted on the underlying surface in (a) bars, \((\mathbf{b})\) atmospheres, and (c) pounds per square inch.

A quantity of \(\mathrm{N}_{2}\) gas originally held at \(531.96 \mathrm{kPa}\) pressure in a 1.00 -L container at \(26^{\circ} \mathrm{C}\) is transferred to a \(12.5-\mathrm{L}\) container at \(20^{\circ} \mathrm{C}\). A quantity of \(\mathrm{O}_{2}\) gas originally at \(531.96 \mathrm{kPa}\) and \(26^{\circ} \mathrm{C}\) in a \(5.00-\mathrm{L}\) container is transferred to this same container. What is the total pressure in the new container?

A piece of dry ice (solid carbon dioxide) with a mass of \(20.0 \mathrm{~g}\) is placed in a 25.0-L vessel that already contains air at \(50.66 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\). After the carbon dioxide has totally sublimed, what is the partial pressure of the resultant \(\mathrm{CO}_{2}\) gas, and the total pressure in the container at \(25^{\circ} \mathrm{C} ?\)

A glass vessel fitted with a stopcock valve has a mass of \(337.428 \mathrm{~g}\) when evacuated. When filled with \(\mathrm{Ar}\), it has a mass of \(339.854 \mathrm{~g}\). When evacuated and refilled with a mixture of Ne and Ar, under the same conditions of temperature and pressure, it has a mass of \(339.076 \mathrm{~g}\). What is the mole percent of Ne in the gas mixture?

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