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In the contact process, sulfur dioxide and oxygen gas react to form sulfur trioxide as follows: $$ 2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g) $$ At a certain temperature and pressure, \(50 \mathrm{~L}\) of \(\mathrm{SO}_{2}\) reacts with \(25 \mathrm{~L}\) of \(\mathrm{O}_{2}\). If all the \(\mathrm{SO}_{2}\) and \(\mathrm{O}_{2}\) are consumed, what volume of \(\mathrm{SO}_{3}\), at the same temperature and pressure, will be produced?

Short Answer

Expert verified
50 liters of \(\mathrm{SO}_{3}\) will be produced.

Step by step solution

01

Identify the Reaction

Examine the chemical reaction given: \[2 \mathrm{SO}_{2}(g) + \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{SO}_{3}(g)\]. This indicates that 2 moles of \(\mathrm{SO}_{2}\) react with 1 mole of \(\mathrm{O}_{2}\) to produce 2 moles of \(\mathrm{SO}_{3}\).
02

Determine the Limiting Reactant

According to the stoichiometry of the reaction, 2 volumes of \(\mathrm{SO}_{2}\) react with 1 volume of \(\mathrm{O}_{2}\). We have 50 L of \(\mathrm{SO}_{2}\) and 25 L of \(\mathrm{O}_{2}\), which perfectly match the stoichiometric ratio: \(\frac{50}{25} = 2\). Thus, there is no excess reactant.
03

Apply Avogadro's Law

Avogadro's Law states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules. Therefore, the volume ratios are equal to mole ratios in a gaseous reaction: \(2:1:2\) for \(\mathrm{SO}_{2}:\mathrm{O}_{2}:\mathrm{SO}_{3}\).
04

Calculate Product Volume

Using the stoichiometry from the balanced equation, 50 L of \(\mathrm{SO}_{2}\) will produce 50 L of \(\mathrm{SO}_{3}\) since the ratio of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) is 1:1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limiting Reactant
In many chemical reactions, one reactant is entirely consumed before the others. This reactant is known as the "limiting reactant" because it limits the amount of product that can be formed. In our example, we have 50 liters of sulfur dioxide (SOâ‚‚) reacting with 25 liters of oxygen (Oâ‚‚). According to the balanced equation, 2 volumes of SOâ‚‚ react with 1 volume of Oâ‚‚:
  • 2 parts SOâ‚‚ + 1 part Oâ‚‚ → 2 parts SO₃
Given the quantities in the reaction, the SOâ‚‚ and Oâ‚‚ are in perfect stoichiometric balance. That means neither reactant is in excess; all the SOâ‚‚ and Oâ‚‚ are used entirely. In real-world reactions, finding the limiting reactant helps predict the amount of product formed, allowing chemists to optimize resources and reduce waste.
Avogadro's Law
Avogadro's Law plays a crucial role in solving problems involving gases. It states that equal volumes of gases, at the same temperature and pressure, contain equal numbers of molecules. For stoichiometric calculations involving gases, this means we can use their volumes directly as their molar quantities. In our reaction:
  • 2 parts SOâ‚‚ + 1 part Oâ‚‚ → 2 parts SO₃
Since gases at the same conditions of temperature and pressure have the same number of molecules per volume, the coefficients in our balanced equation can be read as volumes. Thus, 50 L of SO₂ will require 25 L of O₂ to produce 50 L of SO₃. This simplification is only possible in reactions involving gases, demonstrating how Avogadro's Law facilitates straightforward stoichiometric calculations.
Gas Volume Ratios
Understanding gas volume ratios is key in reactions involving gases, especially under constant temperature and pressure. The balanced chemical equation provides insight into how the volumes of reactants relate to the volumes of products:
  • 2 volumes of SOâ‚‚ + 1 volume of Oâ‚‚ → 2 volumes of SO₃
In this exercise, the ratio of SO₂:O₂:SO₃ is 2:1:2. This means:
  • 50 L of SOâ‚‚ will produce 50 L of SO₃, given 25 L of Oâ‚‚ is completely consumed.
The gas volume ratios make the stoichiometry of gaseous reactions remarkably simple, as the volumes are directly proportional to the number of moles, thanks to Avogadro's Law. Always remember, these ratios and laws apply as long as the conditions of temperature and pressure remain consistent.

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Most popular questions from this chapter

Determine whether each of the following changes will increase, decrease, or not affect the rate with which gas molecules collide with the walls of their container: (a) increasing the volume of the container, \((\mathbf{b})\) increasing the temperature, (c) increasing the molar mass of the gas.

The planet Jupiter has a surface temperature of \(140 \mathrm{~K}\) and a mass 318 times that of Earth. Mercury (the planet) has a surface temperature between \(600 \mathrm{~K}\) and \(700 \mathrm{~K}\) and a mass 0.05 times that of Earth. On which planet is the atmosphere more likely to obey the ideal-gas law? Explain.

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A rigid vessel containing a \(3: 1 \mathrm{~mol}\) ratio of carbon dioxide and water vapor is held at \(200^{\circ} \mathrm{C}\) where it has a total pressure of \(202.7 \mathrm{kPa}\). If the vessel is cooled to \(10^{\circ} \mathrm{C}\) so that all of the water vapor condenses, what is the pressure of carbon dioxide? Neglect the volume of the liquid water that forms on cooling.

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