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(a) How does one determine the number of electron domains in a molecule or ion? (b) What is the difference between a bonding electron domain and a nonbonding electron domain?

Short Answer

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To determine the number of electron domains in a molecule or ion, draw its Lewis structure and count the bonding electron domains (single, double, or triple bonds) and nonbonding electron domains (lone pairs) around the central atom. The total number of electron domains helps predict the molecular geometry using the valence shell electron pair repulsion (VSEPR) theory. Bonding electron domains are associated with chemical bonds (single, double, or triple) between atoms and involve electron pairs holding the atoms together. Nonbonding electron domains correspond to lone pairs of electrons that are not involved in bonding. Both types of electron domains influence the molecular geometry in the VSEPR model.

Step by step solution

01

Answer to the question (a) - Determining the number of electron domains in a molecule or ion

To determine the number of electron domains in a molecule or ion, follow these steps: 1. Draw the Lewis structure of the molecule or ion. 2. Count the number of bonding electron domains (single, double, or triple bonds) around the central atom. 3. Count the number of nonbonding electron domains, which are lone pairs, around the central atom. 4. Add the number of bonding electron domains and nonbonding electron domains together to find the total number of electron domains in the molecule or ion. The total number of electron domains helps in predicting the molecular geometry using the valence shell electron pair repulsion (VSEPR) theory.
02

Answer to the question (b) - Difference between a bonding electron domain and a nonbonding electron domain

Bonding electron domain and nonbonding electron domain are two types of electron domains present around the central atom in a molecule or ion: 1. Bonding electron domain: These are electron domains associated with chemical bonds (single, double, or triple) formed between two atoms. They are occupied by bonding electron pairs, which are involved in holding the atoms together in a molecule or ion. In the context of VSEPR theory, each type of bond (single, double, or triple) counts as one electron domain regardless of the number of shared electrons. 2. Nonbonding electron domain: These are electron domains associated with lone pairs of electrons that are not involved in forming chemical bonds. These electron pairs exist around the central atom and are not shared with other atoms. In the context of VSEPR theory, each lone pair of electrons represents one nonbonding electron domain. The main difference between the two is that bonding electron domains involve electrons shared between atoms to form chemical bonds, whereas nonbonding electron domains correspond to lone pairs of electrons that are not involved in bonding. Both types of electron domains contribute to the overall electron domain geometry and influence the molecular geometry in the VSEPR model.

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Most popular questions from this chapter

What are the electron-domain and molecular geometries of a molecule that has the following electron domains on its central atom? (a) three bonding domains and no nonbonding domains, (b) three bonding domains and one nonbonding domain, (c) two bonding domains and two nonbonding domains.

(a) Write a single Lewis structure for \(\mathrm{SO}_{3}\), and determine the hybridization at the \(\mathrm{S}\) atom. (b) Are there other equivalent Lewis structures for the molecule? (c) Would you expect \(\mathrm{SO}_{3}\) to exhibit delocalized \(\pi\) bonding? Explain.

Sulfur tetrafluoride (SF \(_{4}\) ) reacts slowly with \(\mathrm{O}_{2}\) to form sulfur tetrafluoride monoxide \(\left(\mathrm{OSF}_{4}\right)\) according to the following unbalanced reaction: $$ \mathrm{SF}_{4}(g)+\mathrm{O}_{2}(g) \longrightarrow \operatorname{OSF}_{4}(g) $$ The \(\mathrm{O}\) atom and the four \(\mathrm{F}\) atoms in \(\mathrm{OSF}_{4}\) are bonded to a central \(S\) atom. (a) Balance the equation. (b) Write a Lewis structure of \(\mathrm{OSF}_{4}\) in which the formal charges of all atoms are zero. (c) Use average bond enthalpies (Table 8.4) to estimate the enthalpy of the reaction. Is it endothermic or exothermic? (d) Determine the electrondomain geometry of \(\mathrm{OSF}_{4}\), and write two possible molecular geometries for the molecule based on this electron-domain geometry. (e) Which of the molecular geometries in part (d) is more likely to be observed for the molecule? Explain.

A compound composed of \(2.1 \% \mathrm{H}, 29.8 \% \mathrm{~N}\), and \(68.1 \% \mathrm{O}\) has a molar mass of approximately \(50 \mathrm{~g} / \mathrm{mol}\). (a) What is the molecular formula of the compound? (b) What is its Lewis structure if \(\mathrm{H}\) is bonded to \(\mathrm{O}\) ? (c) What is the geometry of the molecule? (d) What is the hybridization of the orbitals around the \(\mathrm{N}\) atom? (e) How many \(\sigma\) and how many \(\pi\) bonds are there in the molecule?

The three species \(\mathrm{NH}_{2}^{-} \mathrm{NH}_{3}\), and \(\mathrm{NH}_{4}{ }^{+}\) have \(\mathrm{H}-\mathrm{N}-\mathrm{H}\) bond angles of \(105^{\circ}, 107^{\circ}\), and \(109^{\circ}\), respec- tively. Explain this variation in bond angles.

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