/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Energy is required to remove two... [FREE SOLUTION] | 91影视

91影视

Energy is required to remove two electrons from Ca to form \(\mathrm{Ca}^{2+}\) and is required to add two electrons to \(\mathrm{O}\) to form \(\mathrm{O}^{2-}\). Why, then, is \(\mathrm{CaO}\) stable relative to the free elements?

Short Answer

Expert verified
CaO is stable relative to its free elements, Ca and O, because the overall energy change in its formation is exothermic (negative). Although energy is required for ionization of Ca and electron affinity of O, the lattice energy released when forming the ionic bond in CaO is greater than the energy required for these processes. This results in a net release of energy, making CaO more stable than its constituent elements.

Step by step solution

01

Discuss Ionization Energy

Ionization energy is the energy required to remove an electron from an atom or ion. The first ionization energy is the energy required to remove the first electron, the second ionization energy is the energy required to remove the second electron, and so on. Generally, ionization energy increases as we move across a period from left to right in the periodic table and decreases as we move down a group. In this case, we have to remove two electrons from Ca to form Ca虏鈦.
02

Discuss Electron Affinity

Electron affinity is the energy change when an electron is added to an atom or ion. Ionization energy and electron affinity are related in the sense that when an electron is added to an atom, it may release energy (negative electron affinity), or it may require energy (positive electron affinity). In general, electron affinity becomes more negative (exothermic) as we move across a period from left to right in the periodic table, and it tends to become less negative (less exothermic) as we move down a group. In this case, we have to add two electrons to O to form O虏鈦.
03

Discuss Lattice Energy

Lattice energy is the energy required to separate one mole of an ionic crystal into its gaseous ions. It is a measure of the strength of the ionic bond in the crystal lattice. Lattice energy is always exothermic (negative). The stronger the ionic bond, the more negative the lattice energy, and the more stable the compound is relative to its free elements. Here, the lattice energy plays a key role in stabilizing CaO.
04

Explain the Stability of CaO

In order to form CaO, energy is required to remove two electrons from Ca (ionization energy) and to add two electrons to O (electron affinity). However, when these ions come together and form an ionic bond in the crystal lattice of CaO, a significant amount of lattice energy is released. The overall energy change in the formation of CaO involves the sum of ionization energy, electron affinity, and lattice energy. Although energy is required to remove electrons from Ca and add electrons to O, the lattice energy released when CaO is formed is greater than the energy required for these processes. Hence, the overall energy change in the formation of CaO is exothermic (negative). This makes CaO stable relative to its free elements, Ca and O.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw the Lewis structures for each of the following ions or molecules. Identify those that do not obey the octet rule, and explain why they do not. (a) \(\mathrm{SO}_{3}{ }^{2-}\), (b) \(\mathrm{AlH}_{3}\), (c) \(\mathrm{N}_{3}^{-}\), (d) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\), (e) \(\mathrm{SbF}_{5}\).

Consider the nitryl cation, \(\mathrm{NO}_{2}^{+} .\) (a) Write one or more appropriate Lewis structures for this ion. (b) Are resonance structures needed to describe the structure? (c) With what familiar molecule is it isoelectronic?

(a) Construct a Lewis structure for hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\), in which each atom achieves an octet of electrons. (b) Do you expect the \(\mathrm{O}-\mathrm{O}\) bond in \(\mathrm{H}_{2} \mathrm{O}_{2}\) to be longer or shorter than the \(\mathrm{O}-\mathrm{O}\) bond in \(\mathrm{O}_{2}\) ?

Predict the chemical formula of the ionic compound formed between the following pairs of elements: (a) \(\mathrm{Al}\) and \(\mathrm{F}\), (b) \(\mathrm{K}\) and \(\mathrm{S}\), (c) \(\mathrm{Y}\) and \(\mathrm{O}\), (d) \(\mathrm{Mg}\) and \(\mathrm{N}\).

(a) Determine the formal charge on the chlorine atom in the hypochlorite ion, \(\mathrm{ClO}^{-}\), and the perchlorate ion, \(\mathrm{ClO}_{4}^{-}\), using resonance structures where the \(\mathrm{Cl}\) atom has an octet. (b) What are the oxidation numbers of chlorine in \(\mathrm{ClO}^{-}\) and in \(\mathrm{ClO}_{4}^{-} ?(\mathrm{c})\) Is it uncommon for the formal charge and the oxidation state to be different? Explain. (d) Perchlorate is a much stronger oxidizing agent than hypochlorite. Would you expect there to be any relationship between the oxidizing power of the oxyanion and either the oxidation state or the formal charge of chlorine?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.