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(a) For \(n=4\), what are the possible values of \(l\) (b) For \(I=2\), what are the possible values of \(m_{l} ?(c)\) If \(m_{l}\) is 2 , what are the possible values for \(l ?\)

Short Answer

Expert verified
For n = 4, the possible values of l are 0, 1, 2, and 3. For l = 2, the possible values of m_l are -2, -1, 0, 1, and 2. If m_l = 2, the possible values of l are 2 and 3.

Step by step solution

01

Find the possible values of l for n = 4

The angular momentum quantum number (l) can have integer values from 0 to n-1. Here, n = 4, so to find the possible values of l, we will use this formula: l = 0, 1, 2, ..., n-1 For n = 4: l = 0, 1, 2, 3 So, the possible values of l for n = 4 are 0, 1, 2, and 3.
02

Find the possible values of m_l for l = 2

The magnetic quantum number (m_l) can take integer values from -l to +l, including 0. Here, l = 2, so to find the possible values of m_l, we will use this range: m_l = -l, -(l-1), ..., 0, ..., +(l-1), +l For l = 2: m_l = -2, -1, 0, 1, 2 So, the possible values of m_l for l = 2 are -2, -1, 0, 1, and 2.
03

Find the possible values of l for m_l = 2

As m_l can take integer values from -l to +l, including 0, we are given m_l = 2 and have to find the possible values of l. We will use the range of possible m_l values to determine the possible l values: m_l = -l, -(l-1), ..., 0, ..., +(l-1), +l Since m_l = 2, we can denote it as follows: 2 = -l, -(l-1), ..., 0, ..., +(l-1), +l The only possible values of l that satisfy this condition are: l = 2 (as +2 lies in the range -2, -1, 0, 1, 2) l = 3 (as +2 lies in the range -3, -2, -1, 0, 1, 2, 3) So, the possible values of l for m_l = 2 are 2 and 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum Quantum Number (l)
In quantum mechanics, the angular momentum quantum number, typically denoted as \( l \), plays a crucial role in defining the shape of atomic orbitals. It is one of the four quantum numbers used to describe the unique quantum state of an electron. The value of \( l \) indicates the subshell or sublevel in which an electron resides, which corresponds to the shape of the orbital.
The value of \( l \) can range from 0 to \( n-1 \), where \( n \) is the principal quantum number representing the main energy level or shell. Different values of \( l \) correspond to different types of orbitals:
  • \( l = 0 \): s orbital
  • \( l = 1 \): p orbital
  • \( l = 2 \): d orbital
  • \( l = 3 \): f orbital
For example, if \( n = 4 \), the possible values of \( l \) are 0, 1, 2, and 3. This indicates that in the fourth energy level, there are s, p, d, and f orbitals available for electrons.
Magnetic Quantum Number (m_l)
The magnetic quantum number, denoted by \( m_l \), provides information about the orientation of an atomic orbital within a subshell. It is also one of the four quantum numbers that fully describe the quantum state of an electron.
The range of \( m_l \) values depends on the angular momentum quantum number \( l \). For a given \( l \), \( m_l \) can take on integer values from \(-l\) to \(+l\), inclusive. This means that each type of orbital corresponding to a single \( l \) value can have multiple orientations in space:
  • If \( l = 0 \), \( m_l = 0 \) (only one orientation for an s orbital).
  • If \( l = 1 \), \( m_l = -1, 0, 1 \) (three possible orientations for a p orbital).
  • If \( l = 2 \), \( m_l = -2, -1, 0, 1, 2 \) (five possible orientations for a d orbital).
  • If \( l = 3 \), \( m_l = -3, -2, -1, 0, 1, 2, 3 \) (seven possible orientations for an f orbital).
So, for example, if \( l = 2 \), \( m_l \) can be \(-2, -1, 0, 1, \) or \( 2 \), which signifies that the d orbitals have five possible spatial orientations.
Atomic Orbitals
Atomic orbitals are regions in an atom where there is a high probability of finding electrons. These orbitals are solutions to the Schrödinger equation, which describes how these probabilities are distributed around the nucleus.
The shape and orientation of atomic orbitals depend on the quantum numbers \( n, l, \) and \( m_l \). Each type of orbital (s, p, d, f) has a distinct shape. S orbitals are spherical, p orbitals are dumbbell-shaped, d orbitals have more complex, cloverleaf shapes, and f orbitals are even more intricate.
The angular momentum quantum number \( l \) determines the shape, and the magnetic quantum number \( m_l \) describes the orientation:
  • S orbitals (\( l = 0 \)) are spherical and not directional.
  • P orbitals (\( l = 1 \)) exhibit a directional shape, with three possible orientations along the x, y, or z axes indicated by \( m_l \).
  • D orbitals (\( l = 2 \)) have five orientations, offering more complex shapes.
  • F orbitals (\( l = 3 \)) have seven orientations, being even more intricate.
These orbitals are critical in understanding chemical bonding and electron configurations in atoms. They form the foundation for predicting how atoms will interact and bond with each other.

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Most popular questions from this chapter

For each of the following electronic transitions in the hydrogen atom, calculate the energy, frequency, and wavelength of the associated radiation, and determine whether the radiation is emitted or absorbed during the transition: (a) from \(n=4\) to \(n=1,(b)\) from \(n=5\) to \(n=2,(\mathrm{c})\) from \(n=3\) to \(n=6\). Does any of these transitions emit or absorb visible light?

Write the condensed electron configurations for the following atoms, using the appropriate noble-gas core abbreviations: (a) \(\mathrm{Cs}\), (b) \(\mathrm{Ni}\), (c) Se, (d) Cd, (e) U, (f) \(\mathrm{Pb}\).

(a) What are "valence electrons"? (b) What are "core electrons"?(c) What does each box in an orbital diagram represent? (d) What quantity is represented by the direction (up or down) of the half- arrows in an orbital diagram?

The discovery of hafnium, element number 72, provided a controversial episode in chemistry. G. Urbain, a French chemist, claimed in 1911 to have isolated an element number 72 from a sample of rare earth (elements 58-71) compounds. However, Niels Bohr believed that hafnium was more likely to be found along with zirconium than with the rare earths. D. Coster and \(G\). von Hevesy, working in Bohr's laboratory in Copenhagen, showed in 1922 that element 72 was present in a sample of Norwegian zircon, an ore of zirconium. (The name hafnium comes from the Latin name for Copenhagen, Hafnia). (a) How would you use electron configuration arguments to justify Bohr's prediction? (b) Zirconium, hafnium's neighbor in group \(4 \mathrm{~B}\), can be produced as a metal by reduction of solid \(\mathrm{ZrCl}_{4}\) with molten sodium metal. Write a balanced chemical equation for the reaction. Is this an oxidation- reduction reaction? If yes, what is reduced and what is oxidized? (c) Solid zirconium dioxide, \(\mathrm{ZrO}_{2}\), is reacted with chlorine gas in the presence of carbon. The products of the reaction are \(\mathrm{ZrCl}_{4}\) and two gases, \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) in the ratio \(1: 2 \mathrm{Write}\) a balanced chemical equation for the reaction. Starting with a 55.4-g sample of \(\mathrm{ZrO}_{2}\), calculate the mass of \(\mathrm{ZrCl}_{4}\) formed, assuming that \(\mathrm{ZrO}_{2}\) is the limiting reagent and assuming \(100 \%\) yield. (d) Using their electron configurations, account for the fact that \(\mathrm{Zr}\) and \(\mathrm{Hf}\) form chlorides \(\mathrm{MCl}_{4}\) and oxides \(\mathrm{MO}_{2}\).

Einstein's 1905 paper on the photoelectric effect was the first important application of Planck's quantum hypothesis. Describe Planck's original hypothesis, and explain how Einstein made use of it in his theory of the photoelectric effect.

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