/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Among the elementary subatomic p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Among the elementary subatomic particles of physics is the muon, which decays within a few nanoseconds after formation. The muon has a rest mass \(206.8\) times that of an electron. Calculate the de Broglie wavelength associated with a muon traveling at a velocity of \(8.85 \times 10^{5} \mathrm{~cm} / \mathrm{s}\).

Short Answer

Expert verified
The de Broglie wavelength associated with a muon traveling at a velocity of \(8.85 \times 10^{5} \mathrm{cm/s}\) is approximately \(4.16 \times 10^{-11} \mathrm{cm}\).

Step by step solution

01

Find the mass of the muon

To find the mass of the muon (m), we'll first need the mass of an electron (me), which is approximately \(9.11 \times 10^{-28} \mathrm{g}\). Since the muon has a rest mass of 206.8 times that of an electron, we can find its mass by multiplying this factor by the mass of an electron: \[m = 206.8 \times m_e = 206.8 \times (9.11 \times 10^{-28} \mathrm{g})\]
02

Calculate the momentum of the muon

Now that we have the mass of the muon, we can find its momentum (p) by multiplying its mass by its given velocity (v): \[p = mv = (206.8 \times (9.11 \times 10^{-28} \mathrm{g})) \times (8.85 \times 10^{5} \mathrm{cm/s})\]
03

Calculate the de Broglie wavelength

Finally, we can use the de Broglie formula to find the wavelength (λ) of the muon. Recall that Planck's constant (h) is approximately \(6.63 \times 10^{-27} \mathrm{erg} \cdot \mathrm{s}\). Now substitute the momentum (p) we found in the formula: \[λ = \frac{h}{p} = \frac{6.63 \times 10^{-27} \mathrm{erg} \cdot \mathrm{s}}{(206.8 \times (9.11 \times 10^{-28} \mathrm{g})) \times (8.85 \times 10^{5} \mathrm{cm/s})}\] Now, calculate the value of λ: \[λ \approx 4.16 \times 10^{-11} \mathrm{cm}\] So, the de Broglie wavelength associated with a muon traveling at a velocity of \(8.85 \times 10^{5} \mathrm{cm/s}\) is approximately \(4.16 \times 10^{-11} \mathrm{cm}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Muon
The muon is a fascinating subatomic particle that shares many similarities with the electron, yet it is much more massive. It is classified as a lepton, one of the fundamental particles in the universe. Unlike electrons, muons are unstable and exist only for a brief period, typically just a few microseconds, before decaying into other particles. As outlined in the exercise, the rest mass of the muon is about 206.8 times that of an electron. Given this characteristic, when calculating properties like the de Broglie wavelength, it's crucial to start with an accurate determination of its mass. Its larger mass compared to an electron significantly impacts calculations that involve its momentum and wavelength.
Subatomic Particles
Subatomic particles are the building blocks of atoms. They include particles like protons, neutrons, and electrons, each with different properties and functions within the atom. Beyond these, other subatomic particles exist, such as muons and neutrinos, which do not contribute directly to atomic structure. These particles are studied under particle physics, which delves into understanding their behavior and interactions. Identifying the properties of subatomic particles like the muon, which is involved in this exercise, helps scientists grasp fundamental forces and matter composition in the universe. They are integral to understanding quantum physics and its numerous applications.
Planck's Constant
Planck's constant, denoted by \(h\), is a pivotal constant in physics, particularly in quantum mechanics. It relates energy to frequency via the equation \(E = h u\), where \(E\) is energy and \(u\) is frequency. Similarly, it is used in the calculation of de Broglie wavelengths, linking it to particle wave properties. In the provided solution, Planck's constant has a value of approximately \(6.63 \times 10^{-27} \mathrm{erg} \cdot \mathrm{s}\). This constant enables the conversion of momentum into a wavelength, offering a bridge between the macroscopic and quantum worlds. Thanks to Planck's constant, physicists can explore dual wave-particle properties of matter.
Momentum
Momentum, in the realm of physics, is defined as the product of an object's mass and its velocity. It is a vector quantity, possessing both magnitude and direction. Calculating momentum is essential for understanding the motion of objects and particles. In quantum mechanics, like the exercise with the muon, momentum is key to determining the de Broglie wavelength. The momentum \(p\) of a particle such as the muon is calculated using \(p = mv\), where \(m\) is mass and \(v\) is velocity. This relationship helps in transitioning from traditional physics to quantum mechanics, highlighting the wavelike behavior of particles.
Mass of Electron
Electrons are subatomic particles with a fundamental role in chemistry and physics, particularly in forming atoms and participating in chemical reactions. The mass of an electron is crucial for many calculations in physics, such as determining other particle masses through comparison. It is approximately \(9.11 \times 10^{-28} \mathrm{g}\), a small figure reflecting the lightness of electrons compared to other subatomic particles. When calculating the mass of a muon, this mass serves as a reference. With the muon being 206.8 times more massive than an electron, it influences properties like speed and wavelength. Understanding electron mass aids in grasping the distinct characteristics and behaviors of other particles.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) State the Pauli exclusion principle in your own words. (b) The Pauli exclusion principle is, in an important sense, the key to understanding the periodic table. Explain why.

The first 25 years of the twentieth century were momentous for the rapid pace of change in scientists' understanding of the nature of matter. (a) How did Rutherford's experiments on the scattering of \(\alpha\) particles by a gold foil set the stage for Bohr's theory of the hydrogen atom? (b) In what ways is de Broglie's hypothesis, as it applies to electrons, consistent with J. J. Thomson's conclusion that the electron has mass? In what sense is it consistent with proposals that preceded Thomson's work, that the cathode rays are a wave phenomenon?

If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing an orange-yellow color. The light is emitted because the sodium ions in the pickle become excited; their return to the ground state results in light emission (see Figure \(6.13 \mathrm{~b}\) and Sample Exercise 6.3). (a) The wavelength of this emitted light is \(589 \mathrm{~nm}\). Calculate its frequency. (b) What is the energy of \(0.10\) mole of these photons? (c) Calculate the energy gap between the excited and ground states for the sodium ion. (d) If you soaked the pickle for a long time in a different salt solution, such as strontium chloride, would you still observe \(589 \mathrm{~nm}\) light emission? Why or why not?

(a) What is the relationship between the wavelength and the frequency of radiant energy? (b) Ozone in the upper atmosphere absorbs energy in the \(210-230-\mathrm{nm}\) range of the spectrum. In what region of the electromagnetic spectrum does this radiation occur?

Scientists have speculated that element 126 might have a moderate stability, allowing it to be synthesized and characterized. Predict what the condensed electron configuration of this element might be.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.