/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 (a) Why are fats well suited for... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 80

(a) Why are fats well suited for energy storage in the human body? (b) A particular chip snack food is composed of \(12 \%\) protein, \(14 \%\) fat, and the rest carbohydrate. What percentage of the calorie content of this food is fat? (c) How many grams of protein provide the same fuel value as \(25 \mathrm{~g}\) of fat?

Short Answer

Expert verified
(a) Fats are well suited for energy storage in the human body because they provide a highly concentrated source of energy (9 kcal/g), allowing for efficient energy storage in a smaller space and with less weight. The body can also store fat in adipose tissue without any limit. (b) The percentage of calorie content from fat in the chip snack food is: \( \frac{14 \times 9}{(12 \times 4) + (14 \times 9) + (74 \times 4)}\times 100 \approx 49.66 \% \) (c) The grams of protein equivalent to 25 grams of fat is: \( \frac{25 \times 9}{4} \approx 56.25 \, \text{grams}\)

Step by step solution

01

Understanding the role of fats in energy storage

Fats are a highly concentrated source of energy, containing 9 kcal of energy per gram, which is more than double the energy content of protein and carbohydrates (4 kcal per gram). This allows the body to store more energy in a smaller space and with less weight, making fat an efficient energy storage solution. Moreover, the body can store fat in adipose tissue without any limit, unlike carbohydrates storage.
02

Finding the percentage of calorie content that comes from fat

We are given the composition of a chip snack food, containing 12% protein, 14% fat, and the remaining carbohydrate. Since we know the energy content of each macronutrient, we can calculate the calorie content from each and then find the percentage from fat. Calories from protein (per 100 grams) = 12 (percentage) 脳 4 (kcal/g) Calories from fat (per 100 grams) = 14 (percentage) 脳 9 (kcal/g) Calories from carbohydrates (per 100 grams) = (100 - 12 - 14) (percentage) 脳 4 (kcal/g) Now, we can calculate the total calorie content from each macronutrient: Total calories = Calories from protein + Calories from fat + Calories from carbohydrates The percentage of calorie content from fat is: Percentage of calories from fat = (Calories from fat / Total calories) 脳 100
03

Calculating the grams of protein equivalent to 25 grams of fat

We are given that 25 grams of fat provides a certain fuel value. We need to find out how many grams of protein provide the same fuel value, using the fact that 1 gram of fat provides 9 kcal, and 1 gram of protein provides 4 kcal. Fuel value of 25 grams of fat = 25 (grams) 脳 9 (kcal/g) To find the grams of protein required to provide the same fuel value: Grams of protein = Fuel value of 25 grams of fat / 4 (kcal/g) Now we can calculate the answers for step 2 and step 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When a mole of dry ice, \(\mathrm{CO}_{2}(s)\), is converted to \(\mathrm{CO}_{2}(g)\) at atmospheric pressure and \(-78^{\circ} \mathrm{C}\), the heat absorbed by the system exceeds the increase in internal energy of the \(\mathrm{CO}_{2}\). Why is this so? What happens to the remaining energy?

A sample of a hydrocarbon is combusted completely in \(\mathrm{O}_{2}(g)\) to produce \(21.83 \mathrm{~g} \mathrm{CO}_{2}(g), 4.47 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}(g)\), and \(311 \mathrm{~kJ}\) of heat. (a) What is the mass of the hydrocarbon sample that was combusted? (b) What is the empirical formula of the hydrocarbon? (c) Calculate the value of \(\Delta H_{f}^{\circ}\) per empirical-formula unit of the hydrocarbon. (d) Do you think that the hydrocarbon is one of those listed in Appendix C? Explain your answer.

Imagine a book that is falling from a shelf. At a particular moment during its fall, the book has a kinetic energy of \(13 \mathrm{~J}\) and a potential energy with respect to the floor of \(72 \mathrm{~J}\). How does the book's kinetic energy and its potential energy change as it continues to fall? What is its total kinetic energy at the instant just before it strikes the floor? [Section 5.1]

(a) What is meant by the term standard conditions, with reference to enthalpy changes? (b) What is meant by the term enthalpy of formation? (c) What is meant by the term standard enthalpy of formation?

At \(20^{\circ} \mathrm{C}\) (approximately room temperature) the average velocity of \(\mathrm{N}_{2}\) molecules in air is \(1050 \mathrm{mph}\). (a) What is the averagespeed in \(\mathrm{m} / \mathrm{s}\) ? (b) What is the kinetic energy (in J) of an \(\mathrm{N}_{2}\) molecule moving at this speed? (c) What is the total kinetic energy of 1 mol of \(\mathrm{N}_{2}\) molecules moving at this speed?
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Organic Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.