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Define oxidation and reduction in terms of (a) electron transfer and (b) oxidation numbers.

Short Answer

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(a) In terms of electron transfer: Oxidation is the process in which an element loses electrons and becomes oxidized, while reduction is the process in which an element gains electrons and becomes reduced. For example, when magnesium reacts with oxygen, magnesium loses electrons and is oxidized, and oxygen gains electrons and is reduced. (b) In terms of oxidation numbers: Oxidation is the process in which the oxidation number of an element increases, while reduction is the process in which the oxidation number of an element decreases. In the reaction between hydrogen and chlorine to form hydrogen chloride, hydrogen's oxidation number increases from 0 to +1 (oxidation) and chlorine's oxidation number decreases from 0 to -1 (reduction).

Step by step solution

01

(a) Oxidation and Reduction in terms of Electron Transfer)

Oxidation and reduction reactions are complementary processes that involve the transfer of electrons between chemical species. In a redox (reduction-oxidation) reaction, one substance loses electrons while another gains electrons. - Oxidation is the process in which an element loses one or more electrons. The species that loses electrons is said to be oxidized. - Reduction is the process in which an element gains one or more electrons. The species that gains electrons is said to be reduced. Example: In the reaction between magnesium and oxygen, magnesium loses two electrons to form magnesium ions while oxygen gains two electrons to form oxide ions. \[ \text{Mg} \rightarrow \text{Mg}^{2+} + 2\text{e}^-\] \[ \frac{1}{2}\text{O}_2 + 2\text{e}^- \rightarrow \text{O}^{2-}\] In this reaction, magnesium is oxidized (loses electrons) and oxygen is reduced (gains electrons).
02

(b) Oxidation and Reduction in terms of Oxidation Numbers)

Oxidation numbers (or oxidation states) are assigned to elements or ions to help keep track of the number of electrons gained or lost during redox reactions. - Oxidation is the process in which the oxidation number of an element increases. - Reduction is the process in which the oxidation number of an element decreases. Example: In the reaction between hydrogen gas and chlorine gas to form hydrogen chloride: \[\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}\] Before the reaction, hydrogen has an oxidation state of 0 (in its elemental form), and chlorine also has an oxidation state of 0 (as diatomic Cl2). After the reaction, hydrogen chloride (HCl) is formed, and each hydrogen atom now has an oxidation state of +1, while the oxidation state of each chlorine atom is -1. In this reaction, the oxidation number of hydrogen increases from 0 to +1 (oxidation), while the oxidation number of chlorine decreases from 0 to -1 (reduction).

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Most popular questions from this chapter

In each of the following pairs, indicate which has the higher concentration of \(\mathrm{Cl}^{-}\) ion: (a) \(0.10 \mathrm{M} \mathrm{CaCl}_{2}\) or \(0.15 \mathrm{M} \mathrm{KCl}\) solution, (b) \(100 \mathrm{~mL}\) of \(0.10 \mathrm{M} \mathrm{KCl}\) solution or \(400 \mathrm{~mL}\) of \(0.080 \mathrm{M} \mathrm{LiCl}\) solution, \((\mathrm{c}) 0.050 \mathrm{M} \mathrm{HCl}\) solution or \(0.020 \mathrm{M} \mathrm{CdCl}_{2}\) solution.

A sample of \(5.53 \mathrm{~g}\) of \(\mathrm{Mg}(\mathrm{OH})_{2}\) is added to \(25.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HNO}_{3}\). (a) Write the chemical equation for the reaction that occurs. (b) Which is the limiting reactant in the reaction? (c) How many moles of \(\mathrm{Mg}(\mathrm{OH})_{2}, \mathrm{HNO}_{3}\), and \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) are present after the reaction is complete?

Explain the following observations: (a) \(\mathrm{NH}_{3}\) contains no \(\mathrm{OH}^{-}\) ions, and yet its aqueous solutions are basic; (b) HF is called a weak acid, and yet it is very reactive; (c) although sulfuric acid is a strong electrolyte, an aqueous solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) contains more \(\mathrm{HSO}_{4}^{-}\) ions than \(\mathrm{SO}_{4}^{2-}\) ions.

The commercial production of nitric acid involves the following chemical reactions: $$ \begin{gathered} 4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \\ 3 \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{HNO}_{3}(a q)+\mathrm{NO}(g) \end{gathered} $$ (a) Which of these reactions are redox reactions? (b) In each redox reaction identify the element undergoing oxidation and the element undergoing reduction.

The concentration of hydrogen peroxide in a solution is determined by titrating a \(10.0\) -mL sample of the solution with permanganate ion. $$ \begin{array}{r} 2 \mathrm{MnO}_{4}^{-}(a q)+5 \mathrm{H}_{2} \mathrm{O}_{2}(a q)+6 \mathrm{H}^{+}(a q) \longrightarrow \\ 2 \mathrm{Mn}^{2+}(a q)+5 \mathrm{O}_{2}(g)+8 \mathrm{H}_{2} \mathrm{O}(l) \end{array} $$ If it takes \(14.8 \mathrm{~mL}\) of \(0.134 \mathrm{M} \mathrm{MnO}_{4}^{-}\) solution to reach the equivalence point, what is the molarity of the hydrogen peroxide solution?

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