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Aluminum hydroxide reacts with sulfuric acid as follows: $$ 2 \mathrm{Al}(\mathrm{OH})_{3}(s)+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) $$ Which reagent is the limiting reactant when \(0.500 \mathrm{~mol}\) \(\mathrm{Al}(\mathrm{OH})_{3}\) and \(0.500 \mathrm{~mol} \mathrm{H}_{2} \mathrm{SO}_{4}\) are allowed to react? How many moles of \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?

Short Answer

Expert verified
The limiting reactant is \(\mathrm{H_2SO_4}\), under these conditions \(0.167\ \mathrm{mol}\) of \(\mathrm{Al_2(SO_4)_3}\) can form, and \(0.250\ \mathrm{mol}\) of the excess reactant \(\mathrm{Al(OH)_3}\) remain after the completion of the reaction.

Step by step solution

01

Identify the balanced chemical equation

The balanced chemical equation for the reaction is: $$ 2 \mathrm{Al}(\mathrm{OH})_{3}(s)+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) $$
02

Calculate the mole ratio

First, find the mole ratio of \(\mathrm{Al(OH)_3}\) to \(\mathrm{H_2SO_4}\) required for the reaction to proceed: $$ \frac{\text{moles of } \mathrm{Al}(\mathrm{OH})_{3}}{\text{moles of } \mathrm{H}_{2} \mathrm{SO}_{4}} = \frac{2}{3} $$
03

Determine the limiting reactant

To determine the limiting reactant, compare the given amounts of reactants and their mole ratio. A ratio less than the required mole ratio will indicate the limiting reactant: $$ \frac{0.500\ \mathrm{mol}\ \mathrm{Al}(\mathrm{OH})_{3}}{0.500\ \mathrm{mol}\ \mathrm{H}_{2} \mathrm{SO}_{4}} = 1 $$ Since the given mole ratio (1) is greater than the required mole ratio (\(\frac{2}{3}\)), \(\mathrm{H_2SO_4}\) is the limiting reactant.
04

Calculate the moles of \(\mathrm{Al_2(SO_4)_3}\) formed

Now, we can find the moles of \(\mathrm{Al_2(SO_4)_3}\) formed using the stoichiometry from the balanced equation and the moles of limiting reactant (\(\mathrm{H_2SO_4}\)): $$ \text{moles of } \mathrm{Al_2(SO_4)_3} = \frac{\text{moles of } \mathrm{H_2SO_4}}{3} \times 1 = \frac{0.500\ \mathrm{mol}}{3} = 0.167\ \mathrm{mol} $$
05

Calculate the moles of excess reactant remaining

To find the moles of excess reactant (\(\mathrm{Al(OH)_3}\)) remaining, we need to find the moles of \(\mathrm{Al(OH)_3}\) that reacted and subtract it from the initial given moles: $$ \text{moles of } \mathrm{Al}(\mathrm{OH})_3\text{ that reacted} = \frac{1}{2} \times \text{moles of } \mathrm{H_2SO_4} = \frac{1}{2} \times 0.500\ \mathrm{mol} = 0.250\ \mathrm{mol} $$ Hence, the moles of excess reactant remaining: $$ \text{moles of remaining } \mathrm{Al}(\mathrm{OH})_{3} = \text{initial moles of }\ \mathrm{Al}(\mathrm{OH})_{3} - \text{moles of } \mathrm{Al}(\mathrm{OH})_{3}\text{ that reacted} = 0.500\ \mathrm{mol} - 0.250\ \mathrm{mol} = 0.250\ \mathrm{mol} $$ In conclusion, the limiting reactant is \(\mathrm{H_2SO_4}\), under these conditions \(0.167\ \mathrm{mol}\) of \(\mathrm{Al_2(SO_4)_3}\) can form, and \(0.250\ \mathrm{mol}\) of the excess reactant \(\mathrm{Al(OH)_3}\) remain after the completion of the reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is a fundamental concept in chemistry that allows us to understand the quantitative relationships in a chemical reaction. It provides a systematic way to calculate the amounts of reactants and products involved. When performing stoichiometric calculations, we rely on the balanced chemical equation, which gives us the mole ratios of the different chemicals involved.
This process involves three primary steps: writing down the balanced chemical equation, determining the mole ratio from this equation, and using these ratios to solve for unknown quantities.
  • First, ensure that your chemical equation is balanced; all the elements on the reactant side are accounted for in the product side.
  • Second, use the balanced equation to determine the mole ratio between the reactants and the products.
  • Finally, use these ratios to calculate any unknown quantity, such as the amount of product formed or the excess reactants remaining.
By understanding and applying stoichiometry, you can predict how much product will form and identify limiting and excess reactants in chemical reactions.
Mole Ratio
The concept of a mole ratio is crucial when interpreting chemical equations. It's derived directly from a balanced chemical equation and indicates the proportional relationship between the reactants and products involved in a reaction.
Given the balanced equation for the reaction: \[ 2 \mathrm{Al} (\mathrm{OH})_{3} + 3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2} \left(\mathrm{SO}_{4}\right)_{3} + 6 \mathrm{H}_{2} \mathrm{O} \]
The mole ratio tells us that every 2 moles of aluminum hydroxide reacts with 3 moles of sulfuric acid. This ratio is vital for determining which reactant will be used up first (the limiting reactant) and how much of the product can be expected.
  • To apply this, compare the initial amounts of your reactants and set up a proportion using their mole ratio.
  • If the proportion of the actual amounts is less than the ratio, the reactant on the numerator is the limiting reactant.
  • Using these mole ratios is key to making predictions about when the reaction will stop, what is leftover, and how much product is formed.
Understanding mole ratios helps in converting between moles and masses of compounds, a vital part of stoichiometry.
Balanced Chemical Equation
A balanced chemical equation is the starting point for any chemical reaction analysis. It clearly represents the conservation of mass, where the number of atoms of each element is the same on both sides of the equation. This essential principle allows chemists to predict the amounts of products formed in a reaction given a specific amount of reactants and is crucial for stoichiometric calculations.
In the given exercise, the balanced equation is: \[ 2 \mathrm{Al} (\mathrm{OH})_{3} + 3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2} \left(\mathrm{SO}_{4}\right)_{3} + 6 \mathrm{H}_{2} \mathrm{O} \]
Here, the coefficients (2, 3, 1, and 6) ensure that the equation is balanced, representing the exact stoichiometry of the reaction.
  • Each coefficient corresponds to the number of moles needed or produced.
  • Balancing an equation involves changing these coefficients, not the chemical formula of the compounds, to ensure atom conservation.
  • The balanced equations provide the framework for calculating how much reactant is needed to produce a desired amount of product.
Ensuring equations are balanced is a fundamental step that must be carried out before performing any further stoichiometric calculations or solving for limiting reactants.

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Most popular questions from this chapter

The koala dines exclusively on eucalyptus leaves. Its digestive system detoxifies the eucalyptus oil, a poison to other animals. The chief constituent in eucalyptus oil is a substance called eucalyptol, which contains \(77.87 \% \mathrm{C}\), \(11.76 \% \mathrm{H}\), and the remainder \(\mathrm{O}\). (a) What is the empirical formula for this substance? (b) A mass spectrum of eucalyptol shows a peak at about 154 amu. What is the molecular formula of the substance?

(a) What is Avogadro's number, and how is it related to the mole? (b) What is the relationship between the formula weight of a substance and its molar mass?

A particular coal contains \(2.5 \%\) sulfur by mass. When this coal is burned at a power plant, the sulfur is converted into sulfur dioxide gas, which is a pollutant. To reduce sulfur dioxide emissions, calcium oxide (lime) is used. The sulfur dioxide reacts with calcium oxide to form solid calcium sulfite. (a) Write the balanced chemical equation for the reaction. (b) If the coal is burned in a power plant that uses 2000 tons of coal per day, what mass of calcium oxide is required daily to eliminate the sulfur dioxide? (c) How many grams of calcium sulfite are produced daily by this power plant?

The allowable concentration level of vinyl chloride, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), in the atmosphere in a chemical plant is \(2.0 \times 10^{-6} \mathrm{~g} / \mathrm{L}\). How many moles of vinyl chloride in each liter does this represent? How many molecules per liter?

Write balanced chemical equations to correspond to each of the following descriptions: (a) When sulfur trioxide gas reacts with water, a solution of sulfuric acid forms. (b) Boron sulfide, \(\mathrm{B}_{2} \mathrm{~S}_{3}(\mathrm{~s})\), reacts violently with water to form dissolved boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3}\), and hydrogen sulfide gas. (c) When an aqueous solution of lead(II) nitrate is mixed with an aqueous solution of sodium iodide, an aqueous solution of sodium nitrate and a yellow solid, lead iodide, are formed. (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen. (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.

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