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Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas. (a) Write a balanced chemical equation for the reaction. (b) How many grams of calcium hydride are needed to form \(8.500 \mathrm{~g}\) of hydrogen?

Short Answer

Expert verified
The balanced chemical equation for the reaction between calcium hydride and water is: CaH₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + 2H₂(g). To produce 8.500 g of hydrogen gas, 88.759 g of calcium hydride are needed.

Step by step solution

01

Write the balanced chemical equation

The first step is to write down the unbalanced chemical equation for the reaction between calcium hydride (CaH₂) and water (H₂O). This will help us understand the stoichiometry of the reaction and find the balanced chemical equation. The unbalanced equation is: CaH₂ + H₂O → Ca(OH)₂ + H₂ To balance the chemical equation, we need to ensure that the number of atoms of each element on the reactant side is equal to the number on the product side. After balancing the equation, we obtain: CaH₂ + 2H₂O → Ca(OH)₂ + 2H₂ So, the balanced chemical equation is: CaH₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + 2H₂(g)
02

Calculate the moles of hydrogen gas produced

We are given that 8.500 grams of hydrogen gas is produced in the reaction. To find out how many moles of hydrogen gas are produced, we need to use the molar mass of hydrogen gas (Hâ‚‚). The molar mass of Hâ‚‚ is 2.016 g/mol (since 1 mole of hydrogen has a mass of 1.008 g, and there are two hydrogen atoms in Hâ‚‚). Now, we can calculate the moles of hydrogen gas produced as follows: moles of Hâ‚‚ = (8.500 g) / (2.016 g/mol) = 4.220 moles of Hâ‚‚
03

Use stoichiometry to find the moles of calcium hydride required

Now that we know the number of moles of hydrogen gas produced, we can use the stoichiometry given in the balanced chemical equation to find the number of moles of calcium hydride required for this reaction. From the balanced equation, we know that 1 mole of CaHâ‚‚ produces 2 moles of Hâ‚‚. Therefore: moles of CaHâ‚‚ = (4.220 moles of Hâ‚‚) / 2 = 2.110 moles of CaHâ‚‚
04

Calculate the mass of calcium hydride required

Finally, we will convert moles of calcium hydride to grams using its molar mass. The molar mass of CaHâ‚‚ is 42.094 g/mol (40.078 g/mol for calcium, 1.008 g/mol for hydrogen, so 40.078 + 2*1.008). mass of CaHâ‚‚ = (2.110 moles of CaHâ‚‚) * (42.094 g/mol) = 88.759 g Therefore, 88.759 grams of calcium hydride are needed to form 8.500 grams of hydrogen gas.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equation
A balanced chemical equation represents a chemical reaction with the same number of atoms for each element on both sides of the equation. This ensures that mass is conserved, following the law of conservation of mass. To balance an equation, we adjust the coefficients (the numbers in front of chemical formulas) until each element has the same number of atoms on both the reactants and products side.

In our example, calcium hydride (\(\text{CaH}_2\)) reacts with water (\(\text{H}_2\text{O}\)) to form calcium hydroxide (\(\text{Ca(OH)}_2\)) and hydrogen gas (\(\text{H}_2\)). The unbalanced equation initially looks like this:
  • \(\text{CaH}_2 + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{H}_2\)
To balance it, we ensure that the number of atoms for each element is equal on both sides:

  • Balanced equation: \(\text{CaH}_2 + 2\text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + 2\text{H}_2\)
This tells us that one molecule of calcium hydride reacts with two molecules of water to produce one molecule of calcium hydroxide and two molecules of hydrogen gas.
Moles and Molar Mass
Moles and molar mass are crucial concepts in chemistry that help us understand the amount of a substance in a given sample. The mole is a unit of measurement used to discuss the amount of substance, where one mole contains exactly \(6.022 \times 10^{23}\) entities, be it atoms, molecules, or ions.

The molar mass is the mass of one mole of a substance. It is expressed in grams per mole (\(g/mol\)). For example, the molar mass of hydrogen gas (\(\text{H}_2\)) is about \(2.016\ g/mol\), calculated by doubling the atomic mass of a hydrogen atom, as each molecule consists of two hydrogen atoms.

To convert grams of a substance to moles, we divide the mass of the substance by its molar mass. Using the example, when given \(8.500\ g\) of \(\text{H}_2\), the number of moles can be calculated using its molar mass:
  • \( \text{Moles of } \text{H}_2 = \frac{8.500 \text{ g}}{2.016 \text{ g/mol}} = 4.220 \text{ moles} \)
This calculation helps us quantify how much of a substance is partaking in or forming in a chemical reaction.
Stoichiometry
Stoichiometry is the branch of chemistry that deals with the relative quantities of reactants and products in chemical reactions. It relies heavily on the balanced chemical equation to provide a quantitative relationship between the different substances involved.

In the given reaction, the stoichiometry from the balanced equation indicates that 1 mole of calcium hydride generates 2 moles of hydrogen gas. Thus, if we know the number of moles of hydrogen gas produced, we can determine the number of moles of calcium hydride required.

For instance:
  • We calculated that \(4.220\) moles of \(\text{H}_2\) are produced.
  • According to stoichiometry, \(1\) mole of \(\text{CaH}_2\) forms \(2\) moles of \(\text{H}_2\).
  • Thus, the required moles of \(\text{CaH}_2\) are \(\frac{4.220}{2} = 2.110\ moles\).
Stoichiometry helps in predicting the amounts of products formed in a reaction and the amounts of reactants needed.
Chemical Reactions
Chemical reactions describe how substances transform into new substances with different properties. These reactions involve the breaking and forming of chemical bonds. In this exercise, calcium hydride reacts with water, resulting in the formation of calcium hydroxide and hydrogen gas.

To understand chemical reactions, it is important to know the reactants (starting materials) and the products (resulting substances). In our case:
  • Reactants: Calcium hydride (\(\text{CaH}_2\)) and water (\(\text{H}_2\text{O}\))
  • Products: Calcium hydroxide (\(\text{Ca(OH)}_2\)) and hydrogen gas (\(\text{H}_2\))
Such reactions are characterized by changes in energy, typically in the form of heat, and are due to the reorganization of electrons in chemical bonds.

This example also illustrates a basic type of chemical reaction — a displacement reaction, where an element in one compound is replaced by another element, forming a new compound as a result.

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Most popular questions from this chapter

(a) Diamond is a natural form of pure carbon. How many moles of carbon are in a 1.25-carat diamond (1 carat \(=0.200 \mathrm{~g}\) )? How many atoms are in this diamond? (b) The molecular formula of acetylsalicylic acid (aspirin), one of the most common pain relievers, is \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\). How many moles of \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\) are in a \(0.500-\mathrm{g}\) tablet of aspirin? How many molecules of \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\) are in this tablet?

Very small crystals composed of 1000 to 100,000 atoms, called quantum dots, are being investigated for use in electronic devices. (a) A quantum dot was made of solid silicon in the shape of a sphere, with a diameter of \(4 \mathrm{~nm}\). Calculate the mass of the quantum dot, using the density of silicon \(\left(2.3 \mathrm{~g} / \mathrm{cm}^{3}\right)\) (b) How many silicon atoms are in the quantum dot? (c) The density of germanium is \(5.325 \mathrm{~g} / \mathrm{cm}^{3} .\) If you made a \(4 \mathrm{~nm}\) quantum dot of germanium, how many Ge atoms would it contain? Assume the dot is spherical.

Calculate the percentage by mass of oxygen in the following compounds: (a) morphine, \(\mathrm{C}_{17} \mathrm{H}_{19} \mathrm{NO}_{3} ;\) (b) codeine, \(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\) (c) cocaine, \(\mathrm{C}_{17} \mathrm{H}_{21} \mathrm{NO}_{4}\) (d) tetracycline, \(\mathrm{C}_{22} \mathrm{H}_{24} \mathrm{~N}_{2} \mathrm{O}_{8} ;\) (e) digitoxin, \(\mathrm{C}_{4} \mathrm{H}_{64} \mathrm{O}_{13} ;\) (f) vancomycin, \(\mathrm{C}_{66} \mathrm{H}_{75} \mathrm{Cl}_{2} \mathrm{~N}_{9} \mathrm{O}_{24}\)

Sodium hydroxide reacts with carbon dioxide as follows: $$ 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) $$ Which reagent is the limiting reactant when \(1.85 \mathrm{~mol}\) \(\mathrm{NaOH}\) and \(1.00 \mathrm{~mol} \mathrm{CO}_{2}\) are allowed to react? How many moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) can be produced? How many moles of the excess reactant remain after the completion of the reaction?

Determine the empirical formulas of the compounds with the following compositions by mass: (a) \(10.4 \% \mathrm{C}, 27.8 \% \mathrm{~S}\), and \(61.7 \% \mathrm{Cl}\) (b) \(21.7 \%\) C, \(9.6 \% \mathrm{O}\), and \(68.7 \% \mathrm{~F}\) (c) \(32.79 \% \mathrm{Na}, 13.02 \% \mathrm{Al}\), and \(54.19 \% \mathrm{~F}\)

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