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The value of \(\Delta\) for the \(\left[\mathrm{CrF}_{6}\right]^{3-}\) complex is \(182 \mathrm{~kJ} / \mathrm{mol}\). Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy \(d\) -orbital set in this complex. Should the complex absorb in the visible range? (You may need to review Sample Exercise 6.3; remember to divide by Avogadro's number.)

Short Answer

Expert verified
The expected wavelength of absorption for the \(\left[\mathrm{CrF}_{6}\right]^{3-}\) complex is 658 nm, which falls within the visible range (400-700 nm). Therefore, the complex should absorb in the visible range.

Step by step solution

01

Convert energy into Joules per mole

First, we need to convert the given crystal field splitting energy in kJ/mol into Joules per mole. We can do this by multiplying the given value by 1000 J/kJ: 鈭 = 182 kJ/mol 脳 (1000 J/kJ) = 182,000 J/mol
02

Convert energy per mole to energy per photon

We need to convert the energy per mole to energy per photon. We can do this by dividing the energy per mole by Avogadro's number (6.022 脳 10^23 mol^-1): Energy per photon = (182,000 J/mol) 梅 (6.022 脳 10^23 mol^-1) 鈮 3.02 脳 10^-19 J
03

Calculate the frequency

Next, we need to calculate the frequency corresponding to the energy per photon. We can use the formula 饾湀 = E/h where 饾湀 is the frequency, E is the energy per photon, and h is Planck's constant (6.626 脳 10^-34 Js): Frequency (饾湀) = (3.02 脳 10^-19 J) 梅 (6.626 脳 10^-34 Js) 鈮 4.56 脳 10^14 Hz
04

Calculate the wavelength

Now, we need to relate the frequency to wavelength using the speed of light (c) which is 3.00 脳 10^8 m/s. The formula 位 = c/饾湀 can be used for this purpose: Wavelength (位) = (3.00 脳 10^8 m/s) 梅 (4.56 脳 10^14 Hz) 鈮 6.58 脳 10^-7 m = 658 nm
05

Determine if the complex absorbs in the visible range

The visible range of light corresponds to wavelengths between 400 and 700 nm. Since our calculated wavelength is 658 nm, it falls within the visible range. Therefore, the complex will absorb in the visible range. In conclusion, the expected wavelength of absorption corresponding to promotion of an electron in the CrF6 complex ion is 658 nm, and the complex should absorb in the visible range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Transition
Electron transitions are fundamental processes in the crystal field theory. When electrons absorb energy, they jump from lower-energy orbitals to higher-energy ones. This phenomenon is pivotal in understanding the colors exhibited by certain metal complexes.
In an octahedral field, such as in the \([\mathrm{CrF}_{6}]^{3-}\) complex, the presence of ligands causes the splitting of the degenerate \(d\)-orbitals. This results in two sets of orbitals: \(t_{2g}\) (lower energy) and \(e_g\) (higher energy).
  • Energy absorbed during an electron transition is equal to the crystal field splitting energy \(\Delta\).
  • The absorbed energy promotes an electron from the \(t_{2g}\) to the \(e_g\) orbitals.
This transition gives rise to absorption in the visible spectrum, hence explaining the color of the complex.
Wavelength Calculation
Understanding how to calculate the wavelength corresponding to an electron transition requires knowledge of both frequency and energy relationships.
First, convert the energy given for the transition into energy per photon. Divide the energy per mole by Avogadro's number, yielding the energy of a single photon.
Next, determine the frequency \(u\) using Planck鈥檚 equation \(u = \frac{E}{h}\), where \(E\) is the energy per photon and \(h = 6.626 \times 10^{-34} \, \text{Js}\) is Planck's constant.
Finally, use the frequency to calculate the wavelength \(\lambda\) with the formula \(\lambda = \frac{c}{u}\), where \(c = 3.00 \times 10^8 \, \text{m/s}\) is the speed of light. The calculated wavelength provides insight into the light absorption characteristics of the molecule.
Visible Spectrum
The visible spectrum is the portion of the electromagnetic spectrum that human eyes can detect. It ranges from approximately 400 to 700 nanometers (nm) in wavelength.
Each color corresponds to a specific range of wavelengths:
  • Violet: 400-450 nm
  • Blue: 450-495 nm
  • Green: 495-570 nm
  • Yellow: 570-590 nm
  • Orange: 590-620 nm
  • Red: 620-700 nm
In the case of the \([\mathrm{CrF}_{6}]^{3-}\) complex, the calculated absorption wavelength of 658 nm falls within the red spectrum. This absorption affects the color the complex appears to our eyes, often complementing the absorbed color on the pigment wheel.
Planck's Constant
Planck's constant is a critical factor in quantum mechanics, serving as the bridge between the energy and frequency of a photon. Its value \(6.626 \times 10^{-34} \, \text{Js}\) plays a standard role across calculations involving photons and light waves.
Using Planck's constant, the energy of a single photon can be directly related to its frequency by the equation \(E = hu\).
This relationship not only aids in determining the characteristic wavelength of energy absorbed through electron transitions but also in understanding fundamental physical principles governing atomic and subatomic processes such as:
  • Quantum leap of electrons to higher energy states
  • Emission and absorption spectra of materials
As students learn to solve wavelength calculations, they delve deeper into the world of quantum mechanics, exploring how tiny constants like Planck's shape our understanding of the universe.

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Most popular questions from this chapter

Write balanced chemical equations to represent the following observations. (In some instances the complex involved has been discussed previously in the text.) (a) Solid silver chloride dissolves in an excess of aqueous ammonia. (b) The green complex \(\left[\mathrm{Cr}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\), on treatment with water over a long time, converts to a brown-orange complex. Reaction of \(\mathrm{AgNO}_{3}\) with a solution of the product precipitates \(3 \mathrm{~mol}\) of \(\mathrm{AgCl}\) per mole of Cr present. (Write two chemical equations.) (c) When an \(\mathrm{NaOH}\) solution is added to a solution of \(\mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}, \mathrm{a}\) precipitate forms. Addition of excess \(\mathrm{NaOH}\) solution causes the precipitate to dissolve. (Write two chemical equations.) (d) A pink solution of \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\) turns deep blue on addition of concentrated hydrochloric acid.

The complex \(\left[\mathrm{Ru}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}\) undergoes substitution reactions with several ligands, replacing the water molecule with the ligand. \(\left[\mathrm{Ru}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}+\mathrm{L} \longrightarrow[\mathrm{Ru}(\mathrm{EDTA}) \mathrm{L}]^{-}+\mathrm{H}_{2} \mathrm{O}\) The rate constants for several ligands are as follows: $$ \begin{array}{ll} \hline \text { Ligand, } \mathrm{L} & k\left(M^{-1} s^{-1}\right) \\ \hline \text { Pyridine } & 6.3 \times 10^{3} \\ \text { SCN }^{-} & 2.7 \times 10^{2} \\ \mathrm{CH}_{3} \mathrm{CN} & 3.0 \times 10 \\ \hline \end{array} $$ (a) One possible mechanism for this substitution reaction is that the water molecule dissociates from the complex in the rate-determining step, and then the ligand \(\mathrm{L}\) fills the void in a rapid second step. A second possible mechanism is that \(L\) approaches the complex, begins to form a new bond to the metal, and displaces the water molecule, all in a single concerted step. Which of these two mechanisms is more consistent with the data? Explain. (b) What do the results suggest about the relative basicities of the three ligands toward Ru(III)? (c) Assuming that the complexes are all low spin, how many unpaired electrons are in each?

Give the number of \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\), (b) \(\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (c) \(\mathrm{Na}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]\) (d) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{ClO}_{4},(\mathrm{e})[\mathrm{Sr}(\mathrm{EDTA})]^{2-}\)

(a) Draw the two linkage isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\). (b) Draw the two geometric isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\). (c) Two compounds with the formula \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{ClBr}\) can be prepared. Use structural formulas to show how they differ. What kind of isomerism does this illustrate?

For each of the following metals, write the electronic configuration of the atom and its \(3+\) ion: (a) Ru, (b) Mo, (c) Co. Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(3+\) ion, assuming a weak-field complex. How many unpaired electrons are there in each case?

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