/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Which of the following complexes... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 24: Problem 5

Which of the following complexes are chiral? Explain. [Section 24.4]

Short Answer

Expert verified
The chiral complexes among the given options are \(\text{[Co(en)}_{3}]\), \(\text{[CoCl(NH}_{3})_{5}]\), and \(\text{[CoBr(NH}_{3})_{5}]\). This is because they have unique 3D arrangements that create non-superimposable mirror images. The complex \(\text{[Co(NH}_{3})_{6}]\) is not chiral, as all its ligands are identical and cannot form any non-superimposable mirror images.

Step by step solution

01

Identify the complexes

The given complexes are: 1. \(\text{[Co(en)}_{3}]\) 2. \(\text{[Co(NH}_{3})_{6}]\) 3. \(\text{[CoCl(NH}_{3})_{5}]\) 4. \(\text{[CoBr(NH}_{3})_{5}]\)
02

Analyze each complex and determine chirality

1. \(\text{[Co(en)}_{3}]\): The complex has three bidentate en (ethylenediamine) ligands. Since there are three bidentate ligands, they can create different 3D arrangements around the central Co atom. The complex will have a non-superimposable mirror image, so it is chiral. 2. \(\text{[Co(NH}_{3})_{6}]\): This complex has six monodentate NH3 ligands. The ligands are all identical and arranged octahedrally around the central Co atom. As all the ligands are the same, there can't be any non-superimposable mirror images. Therefore, this complex is not chiral. 3. \(\text{[CoCl(NH}_{3})_{5}]\): This complex has one Cl and five NH3 ligands. The five NH3 ligands are indistinguishable, but the Cl ligand is different. In the octahedral arrangement of this complex, there will be a non-superimposable mirror image. Thus, this complex is chiral. 4. \(\text{[CoBr(NH}_{3})_{5}]\): Similar to the previous complex, this complex has one Br and five NH3 ligands. As with the [CoCl(NH3)5] complex, this complex will have a non-superimposable mirror image, so it is chiral.
03

Summarize the results

Analyzing the given complexes, we find that the following complexes are chiral: 1. \(\text{[Co(en)}_{3}]\) 2. \(\text{[CoCl(NH}_{3})_{5}]\) 3. \(\text{[CoBr(NH}_{3})_{5}]\) The complex \(\text{[Co(NH}_{3})_{6}]\) is not chiral.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chirality in Coordination Compounds
Chirality is a fascinating concept commonly encountered in coordination chemistry. A chiral molecule is one that is not superimposable on its mirror image. Imagine your left and right hands; they are mirror images but cannot perfectly align when superimposed.

In coordination compounds, chirality arises when the spatial arrangement of the ligands around the central metal atom leads to non-superimposable mirror images. This often occurs in complexes with an arrangement like octahedral, where different orientations of ligands can create "left-handed" or "right-handed" forms, known as enantiomers.

To determine if a coordination compound is chiral, consider the following:
  • Check if the central metal is symmetrically surrounded by identical ligands. If they are all the same, as in \[\text{[Co(NH}_{3})_{6}]\], it's symmetric, hence achiral.
  • See whether the ligands can create non-superimposable arrangements due to different positions or identities, like in \[\text{[CoCl(NH}_{3})_{5}]\].
  • Keep in mind the presence of bidentate ligands, which can significantly influence chirality due to their ability to "clasp" the central atom forming specific 3D orientations.
Bidentate Ligands
Bidentate ligands are a specific type of complexing agent in coordination chemistry that can clasp onto a central metal ion with two donor atoms. This kind of attachment creates more stable and often more interesting coordination compounds.

Consider ethylenediamine (en), a classic example of a bidentate ligand used in the complex \[\text{[Co(en)}_{3}]\]. With three en ligands coordinating to a cobalt center, it showcases an elaborate structure where each en ligand contributes to bonding through its two nitrogen atoms.

The involvement of bidentate ligands can enhance the potential for chirality because they create specific orientations around the metal center. Since these ligands occupy more "space" compared to monodentate ligands, they can lead to unique geometric configurations that result in non-superimposable mirror images.

When studying coordination compounds, remember:
  • Bidentate ligands bind more strongly due to the "chelate effect," stabilizing the compound.
  • They influence the spatial arrangement of the ligand, potentially causing chirality if three-dimensional asymmetry is introduced.
  • These ligands are excellent at promoting ligand exchange reactions, further diversifying compound properties.
Octahedral Complexes
In coordination chemistry, octahedral complexes represent one of the most common structural types. These complexes have six ligands symmetrically arranged around a central metal ion, forming an octahedral geometry.

This arrangement is highly versatile and can encompass both simple symmetrical structures and more complex asymmetrical configurations.

Octahedral complexes, like \[\text{[Co(NH}_{3})_{6}]\], show their beauty and simplicity, being symmetric and hence achiral. However, introducing different ligands or combinations of bidentate ligands, such as in \[\text{[Co(en)}_{3}]\], can create fascinating asymmetrical structures that are chiral.

Key points about octahedral complexes include:
  • They can accommodate a variety of ligands, enabling a range of chemical behaviors.
  • Their geometry can lead to different types of isomerism, including geometric (cis/trans) and optical isomerism, which is directly related to chirality.
  • Understanding these complexes is crucial for exploring coordination chemistry's depth, as they are found throughout transition metals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Generally speaking, for a given metal and ligand, the stability of a coordination compound is greater for the metal in the \(3+\) rather than in the \(2+\) oxidation state. Furthermore, for a given ligand the complexes of the bivalent metal ions of the first transition series tend to increase in stability in the order \(\mathrm{Mn}(\mathrm{II})<\mathrm{Fe}(\mathrm{II})<\mathrm{Co}(\mathrm{II})<\) Ni(II) < Cu(II). Explain how these two observations are consistent with one another and also consistent with a crystal-field picture of coordination compounds.

The complex \(\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) contains five unpaired electrons. Sketch the energy-level diagram for the \(d\) orbitals, and indicate the placement of electrons for this complex ion. Is the ion a high-spin or a low-spin complex?

(a) What is the difference between a monodentate ligand and a bidentate ligand? (b) How many bidentate ligands are necessary to fill the coordination sphere of a six-coordinate complex? (c) You are told that a certain molecule can serve as a tridentate ligand. Based on this statement, what do you know about the molecule?

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaamminechromium(III) nitrate (b) tetraamminecarbonatocobalt(III) sulfate (c) dichlorobis(ethylenediamine)platinum(IV) bromide (d) potassium diaquatetrabromovanadate(III) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

Sketch the structure of the complex in each of the following compounds: (a) \(c i s-\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (b) \(\mathrm{Na}_{2}\left[\mathrm{Ru}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{5}\right]\) (c) trans- \(\mathrm{NH}_{4}\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\) (d) cis-[Ru(en) \(\left._{2} \mathrm{Cl}_{2}\right]\)
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Organic Chemistry

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.