/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 As shown in Figure \(24.26\), th... [FREE SOLUTION] | 91影视

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As shown in Figure \(24.26\), the \(d-d\) transition of \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) produces an absorption maximum at a wavelength of about \(500 \mathrm{~nm}\). (a) What is the magnitude of \(\Delta\) for \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) in \(\mathrm{kJ} / \mathrm{mol} ?\) (b) What is the spectrochemical series? How would the magnitude of \(\Delta\) change if the \(\mathrm{H}_{2} \mathrm{O}\) ligands in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) were replaced with \(\mathrm{NH}_{3}\) ligands?

Short Answer

Expert verified
(a) The magnitude of 螖 for \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) is approximately 160.37 kJ/mol. (b) The spectrochemical series is an arrangement of ligands in the order of their ability to cause splitting of energy levels of the central metal ion in a complex. If the H鈧侽 ligands in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) are replaced with NH鈧 ligands, the magnitude of 螖 will increase because NH鈧 is a stronger field ligand than H鈧侽, causing larger splitting of energy levels.

Step by step solution

01

Relationship between energy, wavelength, and frequency

The relationship between energy (E), wavelength (位), and frequency (谓) of a photon can be expressed as: \[E = h\nu\] where h is Planck's constant (\(6.626 \times 10^{-34} \mathrm{Js}\)). Since, \( c = \lambda\nu \), where c is the speed of light (\(3.00 \times 10^8 \mathrm{m/s}\)), the equation becomes: \[E = \frac{hc}{\lambda}\]
02

Calculate the energy difference \(\Delta\)

Now, we can calculate the energy difference 螖 using the given 位 value: \[E = \frac{hc}{\lambda}\] \[E = \frac{(6.626 \times 10^{-34} \mathrm{Js})(3.00 \times 10^8 \mathrm{m/s})}{500 \times 10^{-9} \mathrm{m}}\] \[E \approx 3.978 \times 10^{-19} \mathrm{J}\] Now, we convert this energy to kJ/mol. 1 eV = \(1.602 \times 10^{-19} \mathrm{J}\), 1 eV = 96.485 kJ/mol So, \[\Delta (\mathrm{kJ/mol}) = \frac{E (\mathrm{J})}{1.602\times 10^{-19} \mathrm{J/eV}} \times 96.485 \frac{\mathrm{kJ}}{\mathrm{mol\cdot eV}}\] \[\Delta \approx 160.37 \mathrm{kJ/mol}\] (a) The magnitude of 螖 for \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) is approximately 160.37 kJ/mol.
03

Discuss spectrochemical series and the change in 螖

(b) The spectrochemical series is an arrangement of ligands in the order of their ability to cause splitting of energy levels of the central metal ion in a complex. The series is as follows: I鈦 < Br鈦 < Cl鈦 < F鈦 < OH鈦 < H鈧侽 < NCS鈦 < SCN鈦 < NH鈧 < en < bpy < phen < CN鈦 < CO In the given complex, water is the ligand. According to the spectrochemical series, NH鈧 is a stronger field ligand than H鈧侽. Therefore, if the H鈧侽 ligands in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) are replaced with NH鈧 ligands, the magnitude of 螖 will increase. This is because stronger field ligands cause larger splitting of energy levels.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ligand Field Theory
Ligand field theory is an essential part of coordination chemistry that explains the properties of metal complexes, such as their color, magnetism, and reactivity. It is an extension of crystal field theory, which takes the covalent nature of metal-ligand bonds into account. The theory operates on the principle that ligands, which are molecules or ions surrounding a central metal atom, can influence the energy of the d-orbitals of the central atom. When ligands approach the central metal ion, they interact with the d-orbitals and cause a phenomenon known as 'd-orbital splitting' or 'crystal field splitting'.

The degree of orbital splitting has a pivotal role in determining the spectral properties of complexes as it affects the absorption of light. This is critical in the analysis of absorption spectra and the prediction of the color of the complex. In simpler terms, the differences in energy between the split d-orbitals correspond to particular wavelengths of light that the complex can absorb. The non-absorbed light is transmitted or reflected, and this is what we perceive as the color of the complex. Therefore, ligand field theory serves as the foundation to understand why coordination compounds have distinctive colors and how they change with varying ligands.

For example, in the exercise provided, ligand field theory would explain the observed color in the solution by the specific d-d transitions occurring due to splitting of the d-orbitals in the presence of water ligands surrounding the titanium ion.
Spectrochemical Series
The spectrochemical series refers to a list of common ligands ordered by their ability to split the d-orbitals of a central metal ion. This series is a tool that chemists use to predict the magnitude of the splitting, denoted as \(\Delta\), which in turn affects the color and magnetic properties of the complex. Ligands at the low end of the series, such as iodide (I鈦), cause less splitting, while those at the high end, like cyanide (CN鈦) and carbon monoxide (CO), cause larger splitting.

The series informs us about the 'field strength' of ligands, with 'weak field' ligands causing lesser splitting and 'strong field' ligands causing more significant splitting. In the context of the original exercise, the spectrochemical series indicates that by replacing H2O with NH3, a ligand that appears further down the series and is known as a stronger field ligand, the value of \(\Delta\) would increase. This increase means that the d-d transitions would require more energy, and the complex may absorb light at shorter wavelengths, potentially changing the color observed.
Energy Level Splitting
Energy level splitting is a fundamental concept to understand d-d transitions in coordination compounds. When a metal ion is surrounded by ligands, the degenerate (equally energized) d-orbitals split into two groups - a lower-energy set and a higher-energy set. The energy difference between these sets of d-orbitals is symbolized as \(\Delta\), and it varies depending on the nature of the metal ion and the ligands involved.

This splitting is crucial because it determines the energy required for an electron to 'jump' from a lower-energy d-orbital to a higher-energy d-orbital. When such a d-d transition occurs, the complex absorbs a specific quantum of light, corresponding to the energy difference \(\Delta\). As a result, the absorbed light's wavelength is directly related to the \(\Delta\) value. If the value of \(\Delta\) is small, the complex tends to absorb longer wavelengths (redder light), and if it is large, it absorbs shorter wavelengths (bluer light).

In the exercise, the given wavelength of 500 nm and the calculated \(\Delta\) of approximately 160.37 kJ/mol, are intrinsically connected through the formula \[E = \frac{hc}{\lambda}\]. This formula, which bridges the energy of light with its wavelength, allows for the calculation of the splitting energy that determines the color of the complex seen in the laboratory.

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Most popular questions from this chapter

(a) What is meant by the term chelate effect? (b) What thermodynamic factor is generally responsible for the chelate effect? (c) Why are polydentate ligands often called sequestering agents?

The total concentration of \(\mathrm{Ca}^{2+}\) and \(\mathrm{Mg}^{2+}\) in a sample of hard water was determined by titrating a \(0.100-\mathrm{L}\) sample of the water with a solution of EDTA \(^{4-}\). The EDTA \(^{4-}\) chelates the two cations: $$ \begin{array}{r} \mathrm{Mg}^{2+}+[\mathrm{EDTA}]^{4-}--\rightarrow[\mathrm{Mg}(\mathrm{EDTA})]^{2-} \\\ \mathrm{Ca}^{2+}+[\mathrm{EDTA}]^{--}--\rightarrow[\mathrm{Ca}(\mathrm{EDTA})]^{2-} \end{array} $$ It requires \(31.5 \mathrm{~mL}\) of \(0.0104 M[\mathrm{EDTA}]^{4-}\) solution to reach the end point in the titration. A second \(0.100-\mathrm{L}\) sample was then treated with sulfate ion to precipitate \(\mathrm{Ca}^{2+}\) as calcium sulfate. The \(\mathrm{Mg}^{2+}\) was then titrated with \(18.7 \mathrm{~mL}\) of \(0.0104 \mathrm{M}[\mathrm{EDTA}]^{4-}\). Calculate the concentrations of \(\mathrm{Mg}^{2+}\) and \(\mathrm{Ca}^{2+}\) in the hard water in \(\mathrm{mg} / \mathrm{L}\).

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Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) tetraaquadibromomanganese(III) perchlorate (b) bis(bipyridyl) cadmium(II) chloride (c) potassium tetrabromo(ortho-phenanthroline)cobaltate (III) (d) cesium diamminetetracyanochromate(III) (e) tris(ethylenediammine)rhodium(III) tris(oxalato)cobaltate(III)

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