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Explain why the \(d_{x y}, d_{x z}\) and \(d_{y z}\) orbitals lie lower in energy than the \(d_{z^{2}}\) and \(d_{x^{2}-y^{2}}\) orbit als in the presence of an octahedral arrangement of ligands about the central metalion.

Short Answer

Expert verified
In an octahedral arrangement of ligands, the \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals experience lower repulsion with the ligands due to their lobes pointing between the ligands, resulting in a decrease in energy levels. Conversely, the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals have higher energy levels, as their lobes point directly towards the ligands, increasing electrostatic repulsion. This difference in energy levels is a consequence of crystal field theory.

Step by step solution

01

Introduction of crystal field theory

Crystal field theory (CFT) is a simple model that helps us understand the electronic structure and properties of transition metal complexes. The theory is based on the assumption that the interaction between the central metal ion and the surrounding negatively charged ligands (ions or molecules) can be described as a purely electrostatic effect. This electrostatic interaction causes the degenerate d-orbitals of metal ions to split into different energy levels in the presence of ligands.
02

Understanding the octahedral arrangement of ligands

In an octahedral arrangement, six ligands are located at equal distances from the central metal ion along the x, y, and z axes. The ligands are placed at both the positive and negative ends of each axis, resulting in a symmetrical arrangement around the metal ion.
03

Identifying the geometric layout of the d-orbitals

All five d-orbitals have distinct geometric shapes and orientations in three-dimensional space. For our analysis, it is essential to understand the orientation of the lobes of each d-orbital: 1. \(d_{xy}\): lobes lie between x and y axes 2. \(d_{xz}\): lobes lie between x and z axes 3. \(d_{yz}\): lobes lie between y and z axes 4. \(d_{x^2-y^2}\): lobes lie on x and y axes 5. \(d_{z^2}\): one lobe lies on the z-axis, and the other two lobes form a doughnut-shaped structure in the xy plane.
04

Analyzing the interaction between d-orbitals and the octahedral field

In an octahedral field, the lobes of the first three d-orbitals (\(d_{xy}, d_{xz}\), and \(d_{yz}\)) point between the ligands, and thus they experience a smaller electrostatic repulsion. As a result, these orbtials will be stabilized, and their energy will be lowered. On the other hand, the lobes of \(d_{x^2-y^2}\) and \(d_{z^2}\) point directly towards the ligands on x, y, and z axes, which leads to a higher electrostatic repulsion and, therefore, a higher energy.
05

Conclusion

In the presence of an octahedral arrangement of ligands about the central metal ion, the \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals lie lower in energy due to their lowered repulsion with the ligands, since their lobes point between the ligands. On the other hand, the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals lie higher in energy because their lobes point directly towards the ligands along the axes, increasing electrostatic repulsion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octahedral Ligand Arrangement
In chemistry, particularly in the study of transition metal complexes, the octahedral ligand arrangement plays a pivotal role. It refers to a common molecular geometry where six ligands symmetrically surround a central metal ion, positioned along the axes of an imaginary Cartesian coordinate system. This configuration is highly symmetrical and geometrically resembles an octahedron, hence the name.

Imagine placing six ligands at the ends of three imaginary axes passing through the central metal atom. This arrangement is not random; it is energetically favorable due to the even spacing of the ligands, which minimizes the repulsion between them. It is also critical to understand the implications of this arrangement on the electronic structure of the metal ion, which directly influences the color, magnetism, and reactivity of the complex.
D-Orbital Energy Splitting
When it comes to understanding transition metal complexes, grasping the concept of d-orbital energy splitting is essential. In an isolated metal ion, the five d-orbitals have the same energy level, making them degenerate. However, when ligands approach and create an electrostatic field around the metal ion, particularly in an octahedral arrangement, this degeneracy is broken. The spatial orientation of the d-orbitals relative to the ligands dictates how the energy levels will split.

As the ligands approach along the axes in an octahedral complex, the \(d_{z^{2}}\) and \(d_{x^{2}-y^{2}}\) orbitals, which have lobes pointing towards the ligands, experience more electrostatic repulsion and thus increase in energy. Conversely, the three \(d_{xy}\), \(d_{xz}\), and \(d_{yz}\) orbitals are oriented between the axes, so they feel less repulsion and remain at a lower energy level. The difference in energy levels between these two sets of orbitals is a fundamental aspect of crystal field theory, impacting the properties and behaviors of the transition metal complex.
Transition Metal Complexes
Transition metal complexes are compounds that consist of a central transition metal ion surrounded by molecules or ions known as ligands. These complexes are pivotal in many areas of chemistry – including catalysis, material science, and bioinorganic systems – because they can exhibit diverse coordination geometries, oxidation states, and reactivities.

The interaction between the transition metal and its ligands is often described by the crystal field theory. According to this theory, these interactions can significantly alter the electronic structure of the metal ion, leading to the unique chemical and physical properties mentioned earlier. One must appreciate how the d-orbitals split in energy within the ligand's electrostatic field to understand the absorption of light, color, magnetic properties, and the overall stability of these complexes. As such, transition metal complexes with an octahedral ligand arrangement serve as an excellent example of how coordination chemistry intertwines with physical properties and how small changes in electronic structure can lead to significant differences in behavior.

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Most popular questions from this chapter

Oxyhemoglobin, with an \(\mathrm{O}_{2}\) bound to iron, is a low-spin Fe(II) complex; deoxyhemoglobin, without the \(\mathrm{O}_{2}\) molecule, is a high- spin complex. (a) Assuming that the coordination environment about the metal is octahedral, how many unpaired electrons are centered on the metal ion in each case? (b) What ligand is coordinated to the iron in place of \(\mathrm{O}_{2}\) in deoxyhemoglobin? (c) Explain in a general way why the two forms of hemoglobin have different colors (hemoglobin is red, whereas deoxyhemoglobin has a bluish cast). (d) A 15-minute exposure to air containing 400 ppm of CO causes about \(10 \%\) of the hemoglobin in the blood to be converted into the carbon monoxide complex, called carboxyhemoglobin. What does this suggest about the relative equilibrium constants for binding of carbon monoxide and \(\mathrm{O}_{2}\) to hemoglobin?

Sketch the structure of the complex in each of the following compounds: (a) \(c i s-\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (b) \(\mathrm{Na}_{2}\left[\mathrm{Ru}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{5}\right]\) (c) trans- \(\mathrm{NH}_{4}\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\) (d) cis-[Ru(en) \(\left._{2} \mathrm{Cl}_{2}\right]\)

Suppose that a transition-metal ion was in a lattice in which it was in contact with just two nearby anions, located on opposite sides of the metal. Diagram the splitting of the metal \(d\) orbitals that would result from such a crystal field. Assuming a strong field, how many unpaired electrons would you expect for a metal ion with six \(d\) electrons? (Hint: Consider the linear axis to be the z-axis).

(a) A compound with formula \(\mathrm{RuCl}_{3} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) is dissolved in water, forming a solution that is approximately the same color as the solid. Immediately after forming the solution, the addition of excess \(\mathrm{AgNO}_{3}(a q)\) forms \(2 \mathrm{~mol}\) of solid \(\mathrm{AgCl}\) per mole of complex. Write the formula for the compound, showing which ligands are likely to be present in the coordination sphere. (b) After a solution of \(\mathrm{RuCl}_{3} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) has stood for about a year, addition of \(\mathrm{AgNO}_{3}(a q)\) precipitates \(3 \mathrm{~mol}\) of \(\mathrm{AgCl}\) per mole of complex. What has happened in the ensuing time?

(a) In early studies it was observed that when the complex \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Br}\) was placed in water, the electrical conductivity of a \(0.05 M\) solution changed from an initial value of \(191 \mathrm{ohm}^{-1}\) to a final value of \(374 \mathrm{ohm}^{-1}\) over a period of an hour or so. Suggest an explanation for the observed results. (See Exercise \(24.49\) for relevant comparison data.) (b) Write a balanced chemical equation to describe the reaction. (c) A 500-mL solution is made up by dissolving \(3.87 \mathrm{~g}\) of the complex. As soon as the solution is formed, and before any change in conductivity has occurred, a 25.00-mL portion of the solution is titrated with \(0.0100 \mathrm{M} \mathrm{AgNO}_{3}\) solution. What volume of \(\mathrm{AgNO}_{3}\) solution do you expect to be required to precipitate the free \(\mathrm{Br}^{-}(a q) ?\) (d) Based on the response you gave to part (b), what volume of \(\mathrm{AgNO}_{3}\) solution would be required to titrate a fresh \(25.00-\mathrm{mL}\) sample of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Br}\) after all conductivity changes have occurred?

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