/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 (a) Give the chemical formulas a... [FREE SOLUTION] | 91影视

91影视

(a) Give the chemical formulas and colors of the chromate and dichromate ions. (b) Which of these ions is more stable in acidic solution? (c) What type of reaction is involved in their interconversion in solution?

Short Answer

Expert verified
(a) The chromate ion (CrO鈧劼测伝) has the chemical formula \(CrO_4^{2-}\) and is yellow in color, while the dichromate ion (Cr鈧侽鈧嚶测伝) has the chemical formula \(Cr_2O_7^{2-}\) and is orange in color. (b) In acidic solutions, the dichromate ion (Cr鈧侽鈧嚶测伝) is more stable. (c) The interconversion between chromate and dichromate ions in solution is a redox (reduction-oxidation) reaction, with the balanced equation: \(2CrO_4^{2-} + 2H^+ \rightleftharpoons Cr_2O_7^{2-} + H_2O\).

Step by step solution

01

(a) Chemical formulas and colors of chromate and dichromate ions

Chromate ion (CrO鈧劼测伝) has the chemical formula \(CrO_4^{2-}\) and is yellow in color. Dichromate ion (Cr鈧侽鈧嚶测伝) has the chemical formula \(Cr_2O_7^{2-}\) and is orange in color.
02

(b) Stability of ions in acidic solution

Dichromate ion (Cr鈧侽鈧嚶测伝) is more stable in acidic solutions. In such solutions, chromate ion (CrO鈧劼测伝) tends to convert into the dichromate ion (Cr鈧侽鈧嚶测伝).
03

(c) Type of reaction occurring during interconversion

The interconversion between chromate and dichromate ions in solution is an example of a redox (reduction-oxidation) reaction. In the acidic solution, the chromate ion (CrO鈧劼测伝) gets reduced, while the dichromate ion (Cr鈧侽鈧嚶测伝) gets oxidized. The balanced equation for this reaction is: \(2CrO_4^{2-} + 2H^+ \rightleftharpoons Cr_2O_7^{2-} + H_2O\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formulas of Chromate and Dichromate Ions
When studying chemical formulas, the chromate and dichromate ions offer a great example of how elements combine
  1. The chromate ion has the chemical formula \(CrO_4^{2-}\), which means it consists of one chromium (Cr) atom bonded to four oxygen (O) atoms, carrying a net charge of 2-
  2. The dichromate ion is slightly more complex with the formula \(Cr_2O_7^{2-}\). It has two chromium atoms bonded to seven oxygen atoms, also carrying a 2- charge
Both of these ions are visually distinct:
  • The chromate ion appears yellow
  • The dichromate ion has an orange hue

Bearing this in mind is helpful when identifying these ions in lab work, as their distinct colors make them easy to recognize.
Ion Stability in Acidic Solutions
In chemistry, ion stability in different solutions is essential for understanding reactions and compound behavior. Chromate and dichromate ions exhibit differing stability depending on whether they find themselves in neutral or acidic circumstances. In acidic solutions:
  • The dichromate ion \(Cr_2O_7^{2-}\) is more stable
  • The chromate ion \(CrO_4^{2-}\), on the other hand, tends to convert into the stable dichromate \(Cr_2O_7^{2-}\)

This conversion is driven by the presence of hydrogen ions (\(H^+\)) in the solution. The change from chromate to dichromate is a natural consequence of the solution's increased acidity. This behavior underlines the importance of acid concentration in promoting certain ionic forms over others.
Understanding Redox Reactions
Redox reactions, short for reduction-oxidation reactions, play a crucial role in the chemistry of chromate and dichromate ions. During their interconversion, these reactions demonstrate:
  • Reduction, where a molecule gains electrons
  • Oxidation, where a molecule loses electrons
In acidic solutions, the reaction between chromate and dichromate can be expressed by the balanced equation: \[2CrO_4^{2-} + 2H^+ \rightleftharpoons Cr_2O_7^{2-} + H_2O\]
This equation illustrates how chromate ions (\(CrO_4^{2-}\)) migrate into dichromate ions (\(Cr_2O_7^{2-}\)) using hydrogen ions to facilitate the change. In this redox process, the electron flow ensures that oxidation and reduction occur simultaneously, maintaining the overall balance in the chemical equation. Recognizing these reactions helps in understanding various chemical processes involving transformations and energy transfer.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The heats of atomization, \(\Delta H_{\text {atom }}\), in \(\mathrm{kJ} / \mathrm{mol}\), of the first transition series of elements are as follows: \(\begin{array}{lllllllllll} \text { Element } & \text { Ca } & \text { Sc } & \text { Ti } & \text { V } & \text { Cr } & \text { Mn } & \text { Fe } & \text { Co } & \text { Ni } & \text { Cu } \\ \hline \Delta H_{\text {atom }} & 178 & 378 & 471 & 515 & 397 & 281 & 415 & 426 & 431 & 338 \end{array}\) (a) Write an equation for the process involved in atomization, and describe the electronic and structural changes that occur. (b) \(\Delta H_{\text {atom }}\) varies irregularly in the series following \(\mathrm{V}\). How can this be accounted for, at least in part, using the electronic configurations of the gaseous atoms? (Hint: Recall the discussions of Sections \(6.8\) and \(6.9 .)\)

(a) A charge of \(3.3 \times 10^{6} \mathrm{~kg}\) of material containing \(27 \%\) \(\mathrm{Cu}_{2} \mathrm{~S}\) and \(13 \%\) FeS is added to a converter and oxidized. What mass of \(\mathrm{SO}_{2}(g)\) is formed? (b) What is the molar ratio of \(\mathrm{Cu}\) to \(\mathrm{Fe}\) in the resulting mixture of oxides? (c) What are the likely formulas of the oxides formed in the oxidation reactions, assuming an excess of oxygen? (d) Write balanced equations representing each of the oxidation reactions.

Write balanced chemical equations that correspond to the steps in the following brief account of the metallurgy of molybdenum: Molybdenum occurs primarily as the sulfide, \(\mathrm{MoS}_{2}\). On boiling with concentrated nitric acid, a white residue of \(\mathrm{MoO}_{3}\) is obtained. This is an acidic oxide; when it is dissolved in excess hot concentrated ammonia, ammonium molybdate crystallizes on cooling. On heating ammonium molybdate, white \(\mathrm{MoO}_{3}\) is obtained. On further heating to \(1200^{\circ} \mathrm{C}\) in hydrogen, a gray powder of metallic molybdenum is obtained.

Associated with every ferromagnetic solid is a temperature known as its Curie temperature. When heated above its Curie temperature, the substance no longer exhibits ferromagnetism but rather becomes paramagnetic. Use the kinetic- molecular theory of solids toexplain this observation.

Write balanced chemical equations for the reaction between iron and (a) hydrochloric acid, (b) nitric acid.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.