/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Using the concept of magic numbe... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 21: Problem 23

Using the concept of magic numbers, explain why alpha emission is relatively common, but proton emission is nonexistent.

Short Answer

Expert verified
In conclusion, alpha emission is relatively common because an alpha particle has a highly stable configuration with magic numbers for both protons and neutrons, making it energetically favorable for unstable nuclei to emit an alpha particle and transition to a more stable state. On the other hand, proton emission is nonexistent mainly because it would result in a less stable nucleus, disrupt the associated magic numbers, and does not overcome the strong force that keeps protons together in the nucleus.

Step by step solution

01

Introduction to Magic Numbers and Nuclear Stability

In nuclear physics, certain specific numbers of protons and/or neutrons in a nucleus are termed "magic numbers," which make the nucleus more stable. A stable nucleus implies lower energy and less probability of decay. These magic numbers are 2, 8, 20, 28, 50, 82, and 126 for both protons and neutrons. When a nucleus has a magic number of protons or neutrons, it tends to be more stable due to the filled energy levels, leading to higher binding energy compared to other nuclei in the same region.
02

Alpha Emission

Alpha emission is relatively common due to several factors. One primary reason is that an alpha particle consists of 2 protons and 2 neutrons, meaning that the nucleus loses 4 nucleons when an alpha particle is emitted. Interestingly, 2 is a magic number for both protons and neutrons. Thus, when an alpha particle is formed, it itself has a highly stable configuration, making it energetically favorable for the unstable nuclei to emit an alpha particle and transition to a more stable state.
03

Proton Emission

Proton emission is nonexistent mainly due to two factors: the formation of a less stable nucleus and the strong force. Protons repel each other due to the strong force, which holds protons and neutrons together in the nucleus. However, neutron emission is observed because it does not experience repulsive force with other neutrons or protons. Hence, proton emission is not feasible because it would require isolating the strong force for a proton, leading to an unstable configuration in the remaining nucleus. Moreover, the proton emission would leave the nucleus with fewer protons, which would disrupt the associated magic numbers and make the nucleus even less stable.
04

Conclusion

In conclusion, the concept of magic numbers in nuclear physics can be used to explain why alpha emission is relatively common while proton emission is nonexistent. Alpha emission leads to more stable nuclei due to the involvement of magic numbers, whereas proton emission would result in a less stable nucleus and does not overcome the strong force that keeps protons together in the nucleus.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain the function of the following components of a nuclear reactor: (a) control rods, (b) moderator.

The synthetic radioisotope technetium-99, which decays by beta emission, is the most widely used isotope in nuclear medicine. The following data were collected on a sample of \({ }^{99} \mathrm{Tc}\) : $$ \begin{array}{ll} \hline \text { Disintegrations per Minute } & \text { Time (h) } \\ \hline 180 & 0 \\ 130 & 2.5 \\ 104 & 5.0 \\ 77 & 7.5 \\ 59 & 10.0 \\ 46 & 12.5 \\ 24 & 17.5 \\ \hline \end{array} $$ Using these data, make an appropriate graph and curve fit to determine the half-life.

Complete and balance the following nuclear equations by supplying the missing particle: (a) \({ }_{98}^{25} \mathrm{Cf}+{ }_{5}^{10} \mathrm{~B} \longrightarrow 3_{0}^{1} \mathrm{n}+?\) (b) \({ }_{1}^{2} \mathrm{H}+{ }_{2}^{3} \mathrm{He} \longrightarrow{ }_{2}^{4} \mathrm{He}+?\)

Why are nuclear transmutations involving neutrons generally easier to accomplish than those involving protons or alpha particles?

When a positron is annihilated by combination with an electron, two photons of equal energy result. What is the wavelength of these photons? Are they gamma ray photons?
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Reactions

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.