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Identify the element represented by each of the following symbols and give the number of protons and neutrons in each: (a) \({ }_{33}^{74} \mathrm{X},(\mathrm{b}){ }_{53}^{127} \mathrm{X},(\mathrm{c})_{63}^{152} \mathrm{X},(\mathrm{d})_{83}^{209} \mathrm{X}\)

Short Answer

Expert verified
(a) Arsenic (As) with 33 protons and 41 neutrons, (b) Iodine (I) with 53 protons and 74 neutrons, (c) Europium (Eu) with 63 protons and 89 neutrons, and (d) Bismuth (Bi) with 83 protons and 126 neutrons.

Step by step solution

01

Element (a)

For element (a) \({ }_{33}^{74}\mathrm{X}\), the atomic number (Z) is 33 and mass number (A) is 74. The element with the atomic number 33 is Arsenic (As). To find the number of neutrons (N), use the formula: N = A - Z N = 74 - 33 N = 41 So, for element (a), the number of protons is 33 and the number of neutrons is 41.
02

Element (b)

For element (b) \({ }_{53}^{127}\mathrm{X}\), the atomic number (Z) is 53 and mass number (A) is 127. The element with the atomic number 53 is Iodine (I). To find the number of neutrons (N), use the formula: N = A - Z N = 127 - 53 N = 74 So, for element (b), the number of protons is 53 and the number of neutrons is 74.
03

Element (c)

For element (c) \({ }_{63}^{152}\mathrm{X}\), the atomic number (Z) is 63 and mass number (A) is 152. The element with the atomic number 63 is Europium (Eu). To find the number of neutrons (N), use the formula: N = A - Z N = 152 - 63 N = 89 So, for element (c), the number of protons is 63 and the number of neutrons is 89.
04

Element (d)

For element (d) \({ }_{83}^{209}\mathrm{X}\), the atomic number (Z) is 83 and mass number (A) is 209. The element with the atomic number 83 is Bismuth (Bi). To find the number of neutrons (N), use the formula: N = A - Z N = 209 - 83 N = 126 So, for element (d), the number of protons is 83 and the number of neutrons is 126.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Symbols
Chemical symbols are shorthand ways of representing elements in the periodic table. Each element has a unique one or two-letter abbreviation that is recognized internationally. For instance, hydrogen is represented as 'H', while the symbol for carbon is 'C'. These symbols make it easier for scientists and students alike to quickly understand which elements are being discussed without having to spell out the entire name of the element.

Understanding chemical symbols is fundamental to studying chemistry as they are used to denote elements in chemical equations and to describe the composition of compounds. For example, the symbol H_2O represents water, indicating that each molecule consists of two hydrogen atoms ('H') and one oxygen atom ('O').
Atomic Number
The atomic number, often denoted as 'Z', is a defining trait of each element and represents the number of protons found in the nucleus of an atom. This number is critical as it not only identifies the element but also dictates its properties and position in the periodic table.

Since each element has a unique number of protons, the atomic number serves as a sort of fingerprint for that element. For example, if an atom has an atomic number of 6, it must be carbon, because carbon is the only element with six protons in its nucleus.
Mass Number
The mass number, symbolized by 'A', is the total count of protons and neutrons in an atom's nucleus. Unlike the atomic number, the mass number is not fixed for a given element since an element can have atoms with different numbers of neutrons. These differing forms are known as isotopes.

To calculate the mass number, you sum the quantity of protons (atomic number) and neutrons within the nucleus. It's important to note that the mass number is not the same as the atomic mass listed on the periodic table; the latter is a weighted average taking into account all the isotopes of an element that naturally occur.
Isotopes
Isotopes are variants of a particular chemical element, which means they differ in neutron number, although the number of protons (atomic number) remains the same. Isotopes possess different physical properties but generally have very similar chemical properties because they contain the same number of electrons in their outer shells.

Some isotopes are stable, while others are radioactive and may decay over time, releasing radiation. For instance, carbon-12 (C-12) and carbon-14 (C-14) are both isotopes of carbon. However, while C-12 is stable, C-14 is radioactive and is used in radiocarbon dating.
Neutrons
Neutrons are subatomic particles found in the nucleus of an atom along with protons. They have no electric charge and, therefore, are neutral, a feature that influences how atoms interact with each other. The number of neutrons can vary within atoms of a single element, leading to different isotopes.

The number of neutrons in an atom contributes significantly to its mass, and slight variations in neutron number can greatly affect the stability and properties of an atom. For example, adding or removing neutrons from the nucleus can lead to the creation of isotopes or even turn the atom radioactive if the balance between protons and neutrons is disrupted.

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Most popular questions from this chapter

The element lead (Pb) consists of four naturally occurring isotopes with atomic masses \(203.97302,205.97444\), \(206.97587\), and \(207.97663\) amu. The relative abundances of these four isotopes are \(1.4,24.1,22.1\), and \(52.4 \%\), respectively. From these data, calculate the atomic weight of lead.

Using the periodic table to guide you, predict the chemical formula and name of the compound formed by the following elements: (a) Ga and \(\mathrm{F}\), (b) \(\mathrm{Li}\) and \(\mathrm{H}\), (c) Al and \(\mathrm{I}\), (d) \(\mathrm{K}\) and \(\mathrm{S}\).

Rubidium has two naturally occurring isotopes, rubidium- 85 (atomic mass \(=84.9118\) amu; abundance \(=72.15 \%\) ) and rubidium-87 (atomic mass \(=86.9092\) amu; abundance \(=27.85 \%\) ). Calculate the atomic weight of rubidium.

Mass spectrometry is more often applied to molecules than to atoms. We will see in Chapter 3 that the molecular weight of a molecule is the sum of the atomic weights of the atoms in the molecule. The mass spectrum of \(\mathrm{H}_{2}\) is taken under conditions that prevent decomposition into \(\mathrm{H}\) atoms. The two naturally occurring isotopes of hydrogen are \({ }^{1} \mathrm{H}\) (atomic mass \(=1.00783\) amu; abundance \(99.9885 \%\) ) and \({ }^{2} \mathrm{H}\) (atomic mass \(=2.01410 \mathrm{amu}\); abundance \(0.0115 \%\). (a) How many peaks will the mass spectrum have? (b) Give the relative atomic masses of each of these peaks. (c) Which peak will be the largest, and which the smallest?

How did Rutherford interpret the following observations made during his \(\alpha\) -particle scattering experiments? (a) Most \(\alpha\) particles were not appreciably deflected as they passed through the gold foil. (b) A few \(\alpha\) particles were deflected at very large angles. (c) What differences would you expect if beryllium foil were used instead of gold foil in the \(\alpha\) -particle scattering experiment?

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