Chapter 19: Problem 80
Consider the following reaction: $$ \mathrm{PbCO}_{3}(s) \rightleftharpoons \mathrm{PbO}(s)+\mathrm{CO}_{2}(g) $$ Using data in Appendix \(C\), calculate the equilibrium pressure of \(\mathrm{CO}_{2}\) in the system at (a) \(400^{\circ} \mathrm{C}\) and (b) \(180^{\circ} \mathrm{C}\).
Short Answer
Expert verified
The equilibrium pressure of CO鈧 in the system at \(400^{\circ}\mathrm{C}\) is approximately 1.48 脳 10鈦烩伌 bar, and at \(180^{\circ}\mathrm{C}\), it is approximately 1.53 脳 10鈦宦 bar.
Step by step solution
01
Find the standard Gibbs free energy change of the reaction
To find the standard Gibbs free energy change, 鈭咷掳, of the reaction, we can use the equation:
鈭咷掳 = 鈭咷f掳(products) - 鈭咷f掳(reactants)
Using the data in Appendix C, we find the following values for the standard Gibbs free energy of formation, 鈭咷f掳, at 298 K,
鈭咷f掳(PbCO鈧) = -699.5 kJ/mol
鈭咷f掳(PbO) = -218.4 kJ/mol
鈭咷f掳(CO鈧) = -394.4 kJ/mol
Now, substitute the values into the equation,
鈭咷掳 = (-218.4 - (-394.4)) - (-699.5) = 175.5 kJ/mol
02
Use the van't Hoff equation to find the equilibrium constant, K
The van't Hoff equation relates the equilibrium constant, K, to the standard Gibbs free energy change, 鈭咷掳, and temperature, T:
K = \(\exp\left(\frac{-\Delta G^{\circ}}{RT}\right)\)
Where R is the universal gas constant (8.314 J/mol鈰匥).
We need to find the equilibrium constant, K, at the two given temperatures, (a) 400掳C and (b) 180掳C. Since the given 鈭咷f掳 values are at 298 K, we will use the same value of 鈭咷掳 for both cases as an approximation.
(a) For 400掳C:
T = 400 + 273.15 = 673.15 K
K = \(\exp\left(\frac{-175500}{8.314\times673.15}\right)\)
K 鈮 1.48 脳 10鈦烩伌
(b) For 180掳C:
T = 180 + 273.15 = 453.15 K
K = \(\exp\left(\frac{-175500}{8.314\times453.15}\right)\)
K 鈮 1.53 脳 10鈦宦
03
Find the equilibrium pressure of CO鈧 using the expression for K
The reaction involves one mole of a gaseous product (CO鈧) and no gaseous reactants. Therefore, the expression for the equilibrium constant, K, is:
K = (P_CO鈧)/P掳
Where P_CO鈧 is the equilibrium pressure of CO鈧, and P掳 is the standard pressure (1 bar).
Now, we can solve for the equilibrium pressure of CO鈧 at the given temperatures.
(a) For 400掳C:
1.48 脳 10鈦烩伌 = (P_CO鈧)/1 bar
P_CO鈧 = 1.48 脳 10鈦烩伌 bar
(b) For 180掳C:
1.53 脳 10鈦宦 = (P_CO鈧)/1 bar
P_CO鈧 = 1.53 脳 10鈦宦 bar
Thus, the equilibrium pressure of CO鈧 in the system at 400掳C is about 1.48 脳 10鈦烩伌 bar, and at 180掳C, it is about 1.53 脳 10鈦宦 bar.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gibbs Free Energy
Gibbs Free Energy, indicated by \( \Delta G \), is a key concept in determining the feasibility of a chemical reaction and its tendency to reach equilibrium. In simple terms, it embodies the balance between the energy released by forming products and the energy needed to break down reactants. It's represented by the equation:\[ \Delta G^{\circ} = \Delta G^{\circ}_f(\text{products}) - \Delta G^{\circ}_f(\text{reactants}) \]Here's why Gibbs Free Energy is crucial:
- **A negative \( \Delta G \):** Suggests that a reaction is spontaneous and is likely to proceed in the forward direction towards products.
- **A positive \( \Delta G \):** Indicates a non-spontaneous reaction under standard conditions, tending not to occur without external input.
- **Zero \( \Delta G \):** Implies that the system is at equilibrium, the point where neither the reactants nor products are favored.
Equilibrium Constant
The Equilibrium Constant, denoted \( K \), is a vital parameter to describe the status of a chemical system at equilibrium. It connects the concentrations or pressures of reactants and products to provide a snapshot of where equilibrium lies. In simpler terms, it's a mathematical expression that quantifies the balance of materials.For reactions involving gases, the equilibrium constant can often be expressed using partial pressures, specifically like this:\[ K = \frac{(P_{\text{CO}_2})}{P^{\circ}} \]Here鈥檚 how the value of \( K \) works:
- **\( K > 1 \):** Indicates that the products are favored at equilibrium, meaning the reaction tends to go forward.
- **\( K < 1 \):** Signals that the reactants are favored, so the reaction does not proceed much past its initial state.
- **\( K = 1 \):** Suggests that neither reactants nor products are favored significantly, achieving a perfect balance.
Van't Hoff Equation
The Van't Hoff Equation is a powerful tool in understanding how temperature affects the equilibrium constant \( K \). By relating \( K \) to the standard Gibbs free energy change \( \Delta G^{\circ} \), it allows chemists to predict how reactions respond to changes in temperature. The equation is:\[ K = \exp\left(\frac{-\Delta G^{\circ}}{RT}\right) \]Where:
- \( R \) is the universal gas constant, valued at 8.314 J/mol鈰匥.
- \( T \) stands for temperature in Kelvin.
- **Predicts behavior under different temperatures:** A rise in temperature can shift \( K \), indicating alternate equilibrium positions.
- **Temperature-dependent equilibrium constant:** By computing the effect of temperature on \( \Delta G^{\circ} \), it lets us calculate new equilibrium constants for conditions other than standard temperature.