Chapter 13: Problem 41
Calculate the molality of each of the following solutions: (a) \(8.66 \mathrm{~g}\) benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) dissolved in \(23.6 \mathrm{~g}\) carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right)\), (b) \(4.80 \mathrm{~g} \mathrm{NaCl}\) dissolved in \(0.350 \mathrm{~L}\) of water.
Short Answer
Step by step solution
Calculate the number of moles of solute for each solution.
Convert the mass of solvent to kilograms and calculate molality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
Solute
- Benzene, C\(_6\)H\(_6\), is the solute in carbon tetrachloride.
- Sodium chloride is the solute when dissolved in water.
Solvent
- Carbon tetrachloride acts as the solvent with benzene as the solute.
- Water is the solvent for sodium chloride, a common combination in many household and laboratory scenarios.
Moles
- Benzene: With a given mass of 8.66 g, and a molar mass of 72.12 g/mol, the moles of benzene is calculated by dividing the mass by the molar mass, which equals 0.120 mol.
- Sodium Chloride: For a mass of 4.80 g and a molar mass of 58.44 g/mol, the moles of sodium chloride is calculated as 0.0822 mol.
Mass Conversion
- Converting g to kg: To convert grams to kilograms, simply divide the mass in grams by 1000. This is necessary as a prerequisite to calculate molality.
- In the exercise, for benzene, converting 23.6 g of carbon tetrachloride results in 0.0236 kg.
- Similarly, the 350 g of water becomes 0.350 kg.