/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 If you want to dope GaAs to make... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 12: Problem 16

If you want to dope GaAs to make a p-type semiconductor with an element to replace As, which element(s) would you pick?

Short Answer

Expert verified
To dope GaAs (Gallium Arsenide) and make a p-type semiconductor, you should choose Antimony (Sb) as the dopant element. This is because Sb has one more valence electron than As (Arsenic), which will create acceptor sites and increase the conductivity of the material, leading to a p-type semiconductor.

Step by step solution

01

Identify the group and valence electrons of As

The first step is to find As in the periodic table and determine its group and valence electrons. As has 5 valence electrons and belongs to Group 15 (also known as Group VA or Nitrogen Group).
02

Find the elements with one more valence electron than As

Since we need to dope GaAs with an element that has one more valence electron than As, we should look for elements in the same group with one more valence electron. In Group 15, the element with one more valence electron than As is Antimony (Sb), which has 5 valence electrons and is positioned directly below As in the periodic table.
03

Determine if the chosen element is suitable for doping GaAs

Antimony (Sb) is the most suitable candidate for replacing As to make a p-type semiconductor since it has one more valence electron than As. Doping GaAs with Sb will introduce acceptor sites where the extra electrons can move freely, increasing the conductivity and creating a p-type semiconductor. In conclusion, to dope GaAs and make a p-type semiconductor by replacing As atoms, you should choose Antimony (Sb) as the dopant element.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how a cholesteric liquid crystal phase differs from a nematic phase.

An ester is a compound formed by a condensation reaction between a carboxylic acid and an alcohol. Use the index to find the discussion of esters in Chapter 25, and give an example of a reaction forming an ester. How might this kind of reaction be extended to form a polymer (a polyester)?

Draw the structure of the monomer(s) employed to form each of the following polymers shown in Table \(12.5\) (a) polyvinyl chloride, (b) nylon 6,6, (c) polyethylene terephthalate.

One major difference in the behavior of semiconductors and metals is that semiconductors increase their conductivity as you heat them (up to a point), but the conductivity of a metal decreases as you heat it. Suggest an explanation.

Write a chemical equation for formation of a polymer via a condensation reaction from the monomers succinic acid \(\left(\mathrm{HOOCCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\right)\) and ethylenediamine \(\left(\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\right)\).
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Chemical Reactions

Read Explanation

Making Measurements

Read Explanation

Inorganic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.