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The fluorocarbon compound \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) has a normal boiling point of \(47.6^{\circ} \mathrm{C}\). The specific heats of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}(l)\) and \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}(g)\) are \(0.91 \mathrm{~J} / \mathrm{g}-\mathrm{K}\) and \(0.67 \mathrm{~J} / \mathrm{g}-\mathrm{K}\), respectively. The heat of vaporization for the compound is \(27.49 \mathrm{~kJ} / \mathrm{mol}\). Calculate the heat required to convert \(50.0 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) from a liquid at \(10.00{ }^{\circ} \mathrm{C}\) to a gas at \(85.00{ }^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The heat required to convert 50.0g of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) from a liquid at 10.00\(^{\circ}\mathrm{C}\) to a gas at 85.00\(^{\circ}\mathrm{C}\) is 10,270.1 J.

Step by step solution

01

Calculate the heat to raise liquid's temperature to boiling point

First, we need to calculate the amount of heat needed to raise the temperature of the liquid from 10.00°C to the boiling point of 47.6°C. We'll do this by multiplying the mass of the substance (50.0g) by the specific heat of the liquid (\(0.91 \mathrm{~J} / \mathrm{g}-\mathrm{K}\)) and the change in temperature: \(q_1 = mc\Delta T\) where \(q_1\) is the heat required in this step, \(m\) is the mass, \(c\) is the specific heat, and \(\Delta T\) is the change in temperature. Plug in the given values and solve for \(q_1\): \(q_1 = 50.0 \mathrm{g} \times 0.91 \dfrac{\mathrm{J}}{\mathrm{g}\cdot\mathrm{K}} \times (47.6 - 10) \mathrm{K}\) \(q_1 = 50.0 \times 0.91 \times 37.6 \mathrm{J}\) \(q_1 = 1713.16 \mathrm{J}\)
02

Calculate the heat to vaporize the liquid

Now, we'll calculate the heat required to transform the compound from a liquid to a vapor at its boiling point. To do this, we'll multiply the heat of vaporization (\(27.49 \times 10^3 \mathrm{J/mol}\)) by the number of moles of the substance. First, find the molar mass of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\): \(M = 2\times12.01 + 3\times35.45 + 3\times19.00 = 187.83 \mathrm{g/mol}\) Now, find the number of moles of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) in 50.0g: \(n = \dfrac{50.0 \mathrm{g}}{M} = \dfrac{50.0 \mathrm{g}}{187.83 \mathrm{g/mol}} = 0.266 \mathrm{mol}\) Finally, multiply the number of moles by the heat of vaporization to obtain \(q_2\): \(q_2 = n \times \Delta H_\mathrm{vap}\) \(q_2 = 0.266 \mathrm{mol} \times 27.49 \times 10^3 \dfrac{\mathrm{J}}{\mathrm{mol}}\) \(q_2 = 7302.94 \mathrm{J}\)
03

Calculate the heat to raise gas's temperature to 85.00°C

Now we'll calculate the amount of heat required to raise the substance's temperature from the boiling point (47.6°C) to the final temperature (85.00°C). We'll use the same formula as in step 1, but with the specific heat of the gas form: \(q_3 = mc\Delta T\) Plug in the given values and solve for \(q_3\): \(q_3 = 50.0 \mathrm{g} \times 0.67 \dfrac{\mathrm{J}}{\mathrm{g}\cdot\mathrm{K}} \times (85.00 - 47.6) \mathrm{K}\) \(q_3 = 50.0 \times 0.67 \times 37.4 \mathrm{J}\) \(q_3 = 1254.9 \mathrm{J}\)
04

Calculate the total heat required

Finally, sum the heat values calculated in steps 1, 2, and 3 to find the total amount of heat required to convert 50.0g of C₂Cl₃F₃ from a liquid at 10.00°C to a gas at 85.00°C: \(q_\mathrm{total} = q_1 + q_2 + q_3\) \(q_\mathrm{total} = 1713.16 \mathrm{J} + 7302.94 \mathrm{J} + 1254.9 \mathrm{J}\) \(q_\mathrm{total} = 10270.1 \mathrm{J}\) The heat required to convert 50.0g of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) from a liquid at 10.00\(^{\circ}\mathrm{C}\) to a gas at 85.00\(^{\circ}\mathrm{C}\) is 10,270.1 J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
The concept of enthalpy change is central to our understanding of heat transfer during chemical reactions and phase transitions. Enthalpy change, denoted as \( \( \Delta H \) \) for a process, refers to the total heat content change within a system at constant pressure. For a phase transition, such as vaporization, the enthalpy change is known as the heat of vaporization (\( \Delta H_{\text{vap}} \)) and represents the energy required to convert a liquid into a gas without changing its temperature.

Understanding enthalpy is significant when dealing with thermochemical calculations as it helps predict how much heat is exchanged. In the case of the fluorocarbon compound \( \mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3} \) transitioning from liquid to gas, the heat of vaporization is a crucial factor for determining the total heat required for this process.
Specific Heat Capacity
Specific heat capacity, often abbreviated as \( c \), is a quantity that describes how much heat energy is needed to raise the temperature of one gram of a substance by one degree Celsius (or one Kelvin). It's a crucial property because it tells us how resistant a substance is to changing temperature. Substances with high specific heat capacities can absorb a lot of heat without a significant change in temperature, making them effective for thermal management.

In our exercise, specific heat capacities for both the liquid and gas phases of \( \mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3} \) are given, which allows us to calculate the heat needed to change the temperature of the substance in different phases. This ability to calculate the absorbed or released heat during temperature changes is a fundamental aspect of thermochemistry.
Phase Transitions
Phase transitions are transformations from one state of matter to another, such as solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation). During these transitions, the energy of the substance is altered, but its temperature remains constant. Heat of vaporization is an example of the energy involved in a phase transition, specifically when the substance goes from liquid to vapor state.

Understanding phase transitions is crucial when performing heat calculations for substances undergoing these changes. To completely convert the liquid fluorocarbon compound in the exercise into a gas, we need to account for both the heat required to raise the temperature to the boiling point and the heat of vaporization.
Thermochemistry Calculations

Breaking Down Calculations

Thermochemistry calculations often involve several steps, especially when dealing with substances changing phase and temperature. These calculations help us quantify energy changes within a reaction or a physical change, such as the one presented in our exercise.

  • Heat to Raise Temperature: For both liquid and gas, we use the formula \( q = mc\Delta T \), where \( q \) is the heat, \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change.
  • Heat of Phase Change: For the vaporization step, we calculate the heat by multiplying the heat of vaporization per mole by the number of moles of the substance.
  • Total Heat: Finally, we add all the calculated heat values to get the total heat required for the entire process from start to finish.

Each step must be approached methodically, understanding the underlying principles to ensure accurate results. In our exercise, we've sequenced calculations for heating the liquid, vaporizing it, and then heating the gas—combining concepts of specific heat capacity, phase transitions, and enthalpy change for a comprehensive thermochemical analysis.

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Most popular questions from this chapter

True or false: (a) The more polarizable the molecules, the stronger the dispersion forces between them. (b) The boiling points of the noble gases decrease as you go down the column in the periodic table. (c) In general, the smaller the molecule, the stronger the dispersion forces. (d) All other factors being the same, dispersion forces between molecules increase with the number of electrons in the molecules.

As the intermolecular attractive forces between molecules increase in magnitude, do you expect each of the following to increase or decrease in magnitude? (a) vapor pressure, (b) heat of vaporization, (c) boiling point, (d) freezing point, (e) viscosity, (f) surface tension, (g) critical temperature.

For each of the following pairs of substances, predict which will have the higher melting point, and indicate why: (a) HF, \(\mathrm{HCl} ;\) (b) C (graphite), \(\mathrm{CH}_{4}\); (c) \(\mathrm{KCl}, \mathrm{Cl}_{2}\); (d) \(\mathrm{LiF}, \mathrm{MgF}_{2}\).

Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair that has the higher boiling point: (b) \(\mathrm{C}_{3} \mathrm{H}_{8}\) or \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\), (c) \(\mathrm{HOOH}\) or (a) \(\mathrm{C}_{6} \mathrm{H}_{14}\) or \(\mathrm{C}_{8} \mathrm{H}_{18}\) \(\mathrm{HSSH}\), (d) \(\mathrm{NH}_{2} \mathrm{NH}_{2}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{3}\)

The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temperature and pressure. \(\operatorname{In}\) an experiment, \(5.00 \mathrm{~L}\) of \(\mathrm{N}_{2}\) gas is passed through \(7.2146 \mathrm{~g}\) of liquid benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), at \(26.0^{\circ} \mathrm{C}\). The liquid remaining after the experiment weighs \(5.1493 \mathrm{~g}\). Assuming that the gas becomes saturated with benzene vapor and that the total gas volume and temperature remain constant, what is the vapor pressure of the benzene in torr?

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