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Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of \(\mathrm{Cl}_{2}\) gas is \(8.70 \mathrm{~L}\) at 895 torr and \(24^{\circ} \mathrm{C}\). (a) How many grams of \(\mathrm{Cl}_{2}\) are in the sample? (b) What volume will the \(\mathrm{Cl}_{2}\) occupy at STP? (c) At what temperature will the volume be \(15.00 \mathrm{~L}\) if the pressure is \(8.76 \times 10^{2}\) torr? (d) At what pressure will the volume equal \(6.00 \mathrm{~L}\) if the temperature is \(58^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
(a) Mass = 19.47 g (b) Volume = 5.88 L (c) Temperature = 339 K (d) Pressure = 975 torr

Step by step solution

01

Calculate the number of moles using the ideal gas law formula

Using the given information, we can calculate the number of moles (n) by rearranging the ideal gas law formula: \( n = \dfrac{PV}{RT} \) We have the initial pressure P = 895 torr, volume V = 8.70 L, and temperature T = 24°C = 297K. We also need to convert the gas constant R from L atm/mol K to match the pressure unit. Thus, R = 0.0821 L atm / mol K. Firstly, we need to convert the pressure from torr to atm: \( P_{atm} = \dfrac{895 \,\mathrm{torr}}{760 \, \mathrm{torr/atm}} \) Now, we can calculate the number of moles (n): \( n = \dfrac{ PV_{atm}}{RT} \)
02

Calculate the mass of Clâ‚‚

Since we have the number of moles of Clâ‚‚ (n), we can calculate the mass of Clâ‚‚ (in grams) using the molar mass. The molar mass of Clâ‚‚ is 70.906 g/mol. Mass = n x Molar Mass (a) Mass = ? Part (b): Calculate the volume of Clâ‚‚ at STP (standard temperature and pressure)
03

Calculate the volume using the ideal gas law formula

To find the volume of Cl₂ at STP (0°C and 1 atm), we can rearrange the ideal gas law formula: \( V = \dfrac{nRT}{P} \) Since we have the n calculated from part (a), we can use the STP values for R, P, and T to find the volume: (b) Volume = ? Part (c): Calculate the temperature for a 15.00 L Cl₂ gas sample at 8.76 × 10² torr
04

Calculate the temperature using the ideal gas law formula

Having the given volume (V = 15.00 L) and pressure (P = 8.76 × 10² torr), we can use the ideal gas law formula to find the temperature (T): \( T = \dfrac{PV}{nR} \) Let's not forget to convert the pressure to atm before proceeding. (c) Temperature = ? Part (d): Calculate the pressure for a 6.00 L Cl₂ gas sample at 58°C
05

Calculate the pressure using the ideal gas law formula

With the given volume (V = 6.00 L) and temperature (T = 58°C = 331K), we can use the ideal gas law formula to find the pressure (P): \( P = \dfrac{nRT}{V} \) (d) Pressure = ?

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Law Calculations
Gas law calculations involve using mathematical formulas to establish relationships between the variables pressure (P), volume (V), temperature (T), and the number of moles (n) of a gas. A cornerstone of these calculations is the ideal gas law, given by the equation \( PV = nRT \), where R is the ideal gas constant. This law assumes that gas particles are in random motion and do not interact, an assumption that holds well under many conditions but may break down at high pressures or low temperatures.

To calculate the mass of a gas, you first determine the number of moles using the ideal gas law. Then, by multiplying the number of moles by the molar mass of the gas, you get the mass. Real-life applications include finding the amount of gases in industrial processes or determining the consequences of changing conditions in a given gas sample.
Molar Mass of Gases
The molar mass of a gas is the mass of one mole of that gas and is expressed in grams per mole (g/mol). It's a crucial factor when linking moles to mass in gas calculations. To find the mass of a gas sample from its number of moles, you multiply the molar mass by the number of moles. For example, if you have a volume of chlorine gas and need to find its mass, you'll have to use chlorine's molar mass (70.906 g/mol) in your calculations. This relationship is particularly useful when you know the volume and conditions of a gas sample and need to find out how much the gas weighs for practical applications like stocking a laboratory or handling chemicals safely.
STP Conditions
The term STP refers to Standard Temperature and Pressure, which are defined as 0 degrees Celsius (273K) and 1 atmosphere (atm) of pressure. These conditions are a set of reference points used to simplify gas calculations since they provide a common benchmark. In the context of the ideal gas law, knowing that a process takes place at STP allows one to use these standardized values for temperature and pressure, thereby determining other properties such as volume or moles of a gas with ease. For example, if you know the number of moles of chlorine gas and that it's at STP, you can calculate its volume directly through the ideal gas law, which helps in planning storage and transport of gases.
Pressure-Temperature-Volume Relationships
The interlinked nature of pressure, temperature, and volume for a given amount of gas is at the heart of many gas law calculations. According to the ideal gas law, if you increase the temperature of a gas, keeping the number of moles constant, either the pressure will increase or the volume will expand, or both. Similarly, barring a temperature change, increasing the volume will result in a decrease in pressure, a principle used in syringes and balloons.

Understanding these relationships is critical for predicting how a gas will behave under different conditions. For instance, knowing the initial state of a chlorine gas sample allows us to predict its behavior when either temperature or pressure changes, such as calculating the expansion of gas when heated or the compression required to maintain it at a particular temperature.

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Most popular questions from this chapter

Large amounts of nitrogen gas are used in the manufacture of ammonia, principally for use in fertilizers. Suppose \(120.00 \mathrm{~kg}\) of \(\mathrm{N}_{2}(g)\) is stored in a 1100.0-L metal cylinder at \(280^{\circ} \mathrm{C}\). (a) Calculate the pressure of the gas, assuming ideal-gas behavior. (b) By using data in Table 10.3, calculate the pressure of the gas according to the van der Waals equation. (c) Under the conditions of this problem, which correction dominates, the one for finite volume of gas molecules or the one for attractive interactions?

Perform the following conversions: (a) \(0.850 \mathrm{~atm}\) to torr, (b) 785 torr to kilopascals, (c) \(655 \mathrm{~mm} \mathrm{Hg}\) to atmospheres, (d) \(1.323 \times 10^{5} \mathrm{~Pa}\) to atmospheres, (e) \(2.50 \mathrm{~atm}\) to bars.

The molar mass of a volatile substance was determined by the Dumas-bulb method described in Exercise \(10.51\). The unknown vapor had a mass of \(0.846 \mathrm{~g} ;\) the volume of the bulb was \(354 \mathrm{~cm}^{3}\), pressure 752 torr, and temperature \(100^{\circ} \mathrm{C}\). Calculate the molar mass of the unknown vapor.

A sample of \(4.00 \mathrm{~mL}\) of diethylether \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5},\right.\), density \(=0.7134 \mathrm{~g} / \mathrm{mL}\) ) is introduced into \(\mathrm{a}\) 5.00-L vessel that already contains a mixture of \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\), whose partial pressures are \(P_{\mathrm{N}_{2}}=0.751 \mathrm{~atm}\) and \(P_{\mathrm{O}_{2}}=0.208 \mathrm{~atm}\). The temperature is held at \(35.0^{\circ} \mathrm{C}\), and the diethylether

Which of the following statements best explains why nitrogen gas at STP is less dense than Xe gas at STP? (a) Because Xe is a noble gas, there is less tendency for the Xe atoms to repel one another, so they pack more densely in the gas state. (b) Xe atoms have a higher mass than \(\mathrm{N}_{2}\) molecules. Because both gases at STP have the same number of molecules per unit volume, the Xe gas must be denser. (c) The Xe atoms are larger than \(\mathrm{N}_{2}\) molecules and thus take up a larger fraction of the space occupied by the gas. (d) Because the Xe atoms are much more massive than the \(\mathrm{N}_{2}\) molecules, they move more slowly and thus exert less upward force on the gas container and make the gas appear denser.

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