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Predict whether each of the following molecules is polar or nonpolar: (a) IF, (b) \(\mathrm{CS}_{2},(\mathbf{c}) \mathrm{SO}_{3},(\mathbf{d}) \mathrm{PCl}_{3},(\mathbf{e}) \mathrm{SF}_{6},(\mathbf{f}) \mathrm{IF}_{5}\)

Short Answer

Expert verified
(a) IF is polar. (b) CS2 is nonpolar. (c) SO3 is nonpolar. (d) PCl3 is polar. (e) SF6 is nonpolar. (f) IF5 is polar.

Step by step solution

01

(a) IF

IF contains one iodine (I) atom and one fluorine (F) atom. The electronegativity difference between iodine and fluorine is significant, with fluorine being more electronegative. Since the molecule is linear with just two atoms, there is an uneven distribution of electron density, making the molecule polar.
02

(b) CS2

Carbon disulfide (CS2) has one carbon (C) atom and two sulfur (S) atoms with a linear molecular geometry. The electronegativity difference between carbon and sulfur is small, and the linear shape leads to an even distribution of electron density. Therefore, CS2 is a nonpolar molecule.
03

(c) SO3

Sulfur trioxide (SO3) has one sulfur (S) atom and three oxygen (O) atoms. Its molecular geometry is trigonal planar. Each sulfur-oxygen bond is polar due to the electronegativity difference between sulfur and oxygen. However, the three oxygen atoms are symmetrically arranged around the central sulfur atom, canceling out the bond polarities and resulting in a nonpolar molecule.
04

(d) PCl3

Phosphorus trichloride (PCl3) has one phosphorus (P) atom and three chlorine (Cl) atoms. The molecule has a trigonal pyramidal geometry. The electronegativity difference between phosphorus and chlorine results in a polar bond. The molecular geometry does not cancel out these bond polarities, so PCl3 is a polar molecule.
05

(e) SF6

Sulfur hexafluoride (SF6) has one sulfur (S) atom and six fluorine (F) atoms. Its molecular geometry is octahedral. Although each individual sulfur-fluorine bond is polar due to the electronegativity difference, the symmetric arrangement of the fluorine atoms around the sulfur atom leads to an even distribution of electron density. Therefore, SF6 is a nonpolar molecule.
06

(f) IF5

Iodine pentafluoride (IF5) has one iodine (I) atom and five fluorine (F) atoms. The molecular geometry is square pyramidal. The electronegativity difference between iodine and fluorine causes the bonds to be polar. The geometry does not lead to a perfect cancellation of these bond polarities, so IF5 is a polar molecule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity Difference
Electronegativity represents how strongly an atom attracts electrons in a chemical bond. The electronegativity difference between bonded atoms is a critical factor in determining the polarity of the molecule. When two atoms have a substantial difference in their electronegativity, the more electronegative atom will attract the shared electrons more towards itself, resulting in a polar bond.

Consider the molecule IF where iodine (I) and fluorine (F) have significantly different electronegativities; fluorine being much more electronegative than iodine. This difference leads to an unequal sharing of electrons, with the electrons being closer to fluorine, making the IF bond polar. In summary, a large electronegativity difference often points to a polar bond, influencing the overall molecule's polarity.
Molecular Geometry
The shape of a molecule, determined by the positions of its atoms in three-dimensional space, is referred to as its molecular geometry. This geometric arrangement has a direct influence on the molecule's polarity. Even if a molecule contains polar bonds, it might still be nonpolar if its shape is symmetrical.

Take for example carbon disulfide (CS2), which has a linear molecular geometry. Due to this symmetry, any difference in electronegativity between the sulfur atoms and the central carbon atom does not result in an overall dipole moment. In molecular geometry, the shape of a molecule plays just as crucial a role as the differences in electronegativity when determining the overall molecular polarity.
Symmetry and Polarity
When evaluating the polarity of a molecule, symmetry can override individual bond polarities. A symmetrical arrangement of polar bonds can result in a nonpolar molecule because the polarities cancel each other out.

The case of sulfur hexafluoride (SF6) illustrates this concept. Each sulfur-fluorine bond is indeed polar; however, the octahedral geometry of SF6 is perfectly symmetrical, which means the individual dipoles of the bonds exactly cancel out, leaving no net dipole moment across the molecule. This perfect cancellation is what makes SF6 nonpolar, despite its polar bonds. Symmetry is thus a determining factor for molecular polarity.
Chemical Bond Polarity
Chemical bond polarity is the concept that describes how the electrons in a bond are distributed between the two bonded atoms. Bonds can be nonpolar, where electrons are shared equally, or polar, where electrons are shared unequally.

For instance, in phosphorus trichloride (PCl3), the bonds between the phosphorus (P) and chlorine (Cl) atoms are polar because chlorine is more electronegative than phosphorus, thus attracting the shared electrons more. However, in this molecule, the polar bonds do not cancel out due to the trigonal pyramidal geometry, resulting in an overall polar molecule. Chemical bond polarity, combined with molecular geometry, is instrumental in determining the polarity of a molecule.

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Most popular questions from this chapter

Draw a picture that shows all three 2\(p\) orbitals on one atom and all three 2\(p\) orbitals on another atom. (a) Imagine the atoms coming close together to bond. How many \(\sigma\) bonds can the two sets of 2\(p\) orbitals make with each other? (b) How many \(\pi\) bonds can the two sets of 2\(p\) orbitals make with each other? (c) How many antibonding orbitals, and of what type, can be made from the two sets of 2\(p\) orbitals?

Dichloroethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{Cl}_{2}\right)\) has three forms (isomers), each of which is a different substance. (a) Draw Lewis structures of the three isomers, all of which have a carbon-carbon double bond. ( b) Which of these isomers has a zero dipole moment? (c) How many isomeric forms can chloroethylene, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\) have? Would they be expected to have dipole moments?

Indicate whether each statement is true or false. (a) \(s\) orbitals can only make \(\sigma\) or \(\sigma^{*}\) molecular orbitals. (b) The probability is 100\(\%\) for finding an electron at the nucleus in a \(\pi^{*}\) orbital. (c) Antibonding orbitals are higher in energy than bonding orbitals (if all orbitals are created from the same atomic orbitals). (d) Electrons cannot occupy an antibonding orbital.

Consider the \(\mathrm{SCl}_{2}\) molecule. (a) What is the electron configuration of an isolated S atom? (b) What is the electron configuration of an isolated Cl atom? (c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in \(\mathrm{SCl}_{2} ?\) (d) What valence orbitals, if any, remain unhybridized on the S atom in \(\mathrm{SCl}_{2} ?\)

The vertices of a tetrahedron correspond to four alternating corners of a cube. By using analytical geometry, demonstrate that the angle made by connecting two of the vertices to a point at the center of the cube is \(109.5^{\circ},\) the characteristic angle for tetrahedral molecules.

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