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Silver and rubidium both form \(+1\) ions, but silver is far less reactive. Suggest an explanation, taking into account the ground-state electron configurations of these elements and their atomic radii.

Short Answer

Expert verified
Silver (Ag) is far less reactive than rubidium (Rb) because, although they both form +1 ions and have one valence electron in the 5s orbital, the atomic radius of rubidium is larger than that of silver. This means the valence electron in rubidium is easier to remove compared to silver, and hence, rubidium is more chemically reactive than silver.

Step by step solution

01

Determine the electron configurations of silver and rubidium atoms

In order to determine the electron configurations of silver and rubidium, we can refer to the periodic table where their atomic numbers are given. Silver (Ag) has an atomic number of 47, while rubidium (Rb) has an atomic number of 37. Using the atomic numbers, we can write the electron configurations for both elements as follows: Silver (Ag): \( 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 5s^1 \) Rubidium (Rb): \( 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1 \) It is important to analyze the outermost electrons, also known as valence electrons. Silver has one valence electron in the 5s orbital, while rubidium has one valence electron in the 5s orbital as well.
02

Analyze the atomic radii of silver and rubidium atoms

The other factor that can be taken into account is the atomic radii. In the periodic table, atoms increase in size as you move down a group (vertical column) and decrease in size as you move across a period (horizontal row). Rubidium is located in the alkali metals group and found in period 5. Silver is located in the transition metals group and found in period 5 as well. Since rubidium is on the far left of the period and silver is several elements to the right, we can conclude that rubidium has a larger atomic radius compared to silver.
03

Discuss the reactivity of silver and rubidium

The reactivity of an element is mainly determined by the ease with which it loses or gains electrons. Since both silver and rubidium have one valence electron in the 5s orbital, forming +1 ions, the atomic radius becomes an important factor to consider. Rubidium, with a larger atomic radius, means that its 5s valence electron is located farther from its nucleus and is less tightly bound, making it easier to be removed. On the other hand, silver's valence electron is closer to the nucleus due to its smaller atomic radius, resulting in a stronger attraction making it harder to be removed.
04

Conclusion

Silver (Ag) is far less reactive than rubidium (Rb) because, although they both form +1 ions and have one valence electron in the 5s orbital, the atomic radius of rubidium is larger than that of silver. This means the valence electron in rubidium is easier to remove compared to silver, and hence, rubidium is more chemically reactive than silver.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
The electron configuration of an atom describes the distribution of electrons in its orbitals. For the elements in question, silver (Ag) and rubidium (Rb), understanding their electron configurations helps explain differences in their chemical reactivity.

- **Silver (Ag)** has an atomic number of 47. Its configuration is: \( 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 5s^1 \). The outermost electron, or valence electron, is found in the 5s orbital. - **Rubidium (Rb)** has an atomic number of 37, with a configuration of: \( 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1 \). Similarly, its valence electron is also in the 5s orbital.

Although both elements have a single electron in the 5s orbital, their placement in different groups on the periodic table affects their electron configuration at the deeper levels, influencing their chemical properties and reactivity.
Atomic Radii
Atomic radius refers to the size of an atom, more specifically, the distance from the nucleus to the outermost electron shell. As a rule of thumb, the atomic radius increases down a group and decreases across a period in the periodic table.

Rubidium has a larger atomic radius than silver. In the periodic table, rubidium is situated in the alkali metal group, while silver is a transition metal. Both are located in period 5, but since rubidium lies to the far left and silver towards the center, rubidium's atoms are larger.

- **Bigger Radius & Easier Reactivity**: In rubidium, the increased size means its valence electron is farther from the nucleus, held with less energy, and therefore more easily lost. - **Smaller Radius & Harder Reactivity**: Conversely, in silver, the closer proximity of the valence electron to the nucleus due to a smaller radius creates a stronger attraction, making it harder to remove this electron, thus reducing its reactivity.
Valence Electrons
Valence electrons are the electrons in the outermost shell of an atom. These are the ones primarily involved in bonding and chemical reactions.

Silver and rubidium both have one valence electron in the 5s orbital. The way these electrons interact with the surrounding environment plays a vital role in determining the reactivity of the element.
- In **rubidium**, this electron is more loosely bound because of its larger atomic radius. Therefore, rubidium can easily lose its electron to form a +1 ion. This ease of electron removal makes rubidium highly reactive. - In **silver**, the valence electron is more tightly bound due to the relatively smaller atomic radius, meaning more energy is required to remove it. This results in silver being less reactive than rubidium.

The easy loss or retention of the valence electron significantly influences these elements' chemical behavior, contributing to the distinct difference in their reactivity despite having similar valence shell configurations.

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Most popular questions from this chapter

(a) Which ion is smaller, \(\mathrm{Co}^{3+}\) or \(\mathrm{Co}^{4+} ?(\mathbf{b})\) In a lithium-ion battery that is discharging to power a device, for every \(\mathrm{Li}^{+}\) that inserts into the lithium cobalt oxide electrode, a \(\mathrm{Co}^{4+}\) ion must be reduced to a \(\mathrm{Co}^{3+}\) ion to balance charge. Using the CRC Handbook of Chemistry and Physics or other standard reference, find the ionic radii of \(\mathrm{Li}^{+}, \mathrm{Co}^{3+},\) and \(\mathrm{Co}^{4+} .\) Order these ions from smallest to largest. (c) Will the lithium cobalt oxide cathode expand or contract as lithium ions are inserted? (d) Lithium is not nearly as abundant as sodium. If sodium ion batteries were developed that function in the same manner as lithium ion batteries, do you think "sodium cobalt oxide" would still work as the electrode material? Explain. (e) If you don’t think cobalt would work as the redox-active partner ion in the sodium version of the electrode, suggest an alternative metal ion and explain your reasoning.

Elements in group 7A in the periodic table are called the halogens; elements in group 6A are called the chalcogens. (a) What is the most common oxidation state of the chalcogens compared to the halogens? (b) For each of the following periodic properties, state whether the halogens or the chalcogens have larger values: atomic radii, ionic radii of the most common oxidation state, first ionization energy, second ionization energy.

Zincin its \(2+\) oxidation state is an essential metal ion for life. \(\mathrm{Zn}^{2+}\) is found bound to many proteins that are involved in biological processes, but unfortunately \(\mathrm{Zn}^{2+}\) is hard to detect by common chemical methods. Therefore, scientists who are interested in studying \(\mathrm{Zn}^{2+}\) -containing proteins frequently substitute \(\mathrm{Cd}^{2+}\) for \(\mathrm{Zn}^{2+},\) since \(\mathrm{Cd}^{2+}\) is easier to detect. (a) On the basis of the properties of the elements and ions discussed in this chapter and their positions in the periodic table, describe the pros and cons of using \(\mathrm{Cd}^{2+}\) as a \(\mathrm{Zn}^{2+}\) substitute. (b) Proteins that speed up (catalyze) chemical reactions are called enzymes. Many enzymes are required for proper metabolic reactions in the body. One problem with using \(\mathrm{Cd}^{2+}\) to replace \(\mathrm{Zn}^{2+}\) in enzymes is that \(\mathrm{Cd}^{2+}\) substitution can decrease or even eliminate enzymatic activity. Can you suggest a different metal ion that might replace \(Z n^{2+}\) in enzymes instead of \(C d^{2+} ?\) Justify your answer.

Identify each statement as true or false: (a) Ionization energies are always negative quantities. (b) Oxygen has a larger first ionization energy than fluorine. (c) The second ionization energy of an atom is always greater than its first ionization energy. (d) The third ionization energy is the energy needed to ionize three electrons from a neutral atom.

Explain the following variations in atomic or ionic radii: (a) \(\mathrm{I}^{-}>\mathrm{I}>\mathrm{I}^{+}\) (b) \(\mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}>\mathrm{Be}^{2+}\) (c) \(\mathrm{Fe}>\mathrm{Fe}^{2+}>\mathrm{Fe}^{3+}\)

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