/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Which neutral atom is isoelectro... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which neutral atom is isoelectronic with each of the following ions? \(\mathrm{Ga} ^{3+}, \mathrm{Zr}^{4+}, \mathrm{Mn}^{7+}, \mathrm{I}^{-}, \mathrm{Pb}^{2+}.\)

Short Answer

Expert verified
The neutral atoms isoelectronic with the given ions are: - \(\mathrm{Ga} ^{3+}\) is isoelectronic with Nickel (Ni). - \(\mathrm{Zr}^{4+}\) is isoelectronic with Krypton (Kr). - \(\mathrm{Mn}^{7+}\) is isoelectronic with Argon (Ar). - \(\mathrm{I}^{-}\) is isoelectronic with Xenon (Xe). - \(\mathrm{Pb}^{2+}\) is isoelectronic with Mercury (Hg).

Step by step solution

01

Recall the atomic number of the given ions#for an_element_here#

Recall the atomic number of the given elements. The atomic number is equal to the number of protons in the nucleus of an atom and determines the number of electrons a neutral atom possesses. Thus, the number of electrons in each ion can be calculated by subtracting or adding the corresponding charge to the atomic number.
02

Determine the number of electrons in each ion #for_an_element_here#

Subtract or add the charge value to the given atomic number to determine the number of electrons in each of the ions: \(\mathrm{Ga} ^{3+}\): Ga has an atomic number of 31. Since it has a charge of +3, it has lost 3 electrons. Therefore, Ga3+ has 31 - 3 = 28 electrons. \(\mathrm{Zr}^{4+}\): Zr has an atomic number of 40. Since it has a charge of +4, it has lost 4 electrons. Therefore, Zr4+ has 40 - 4 = 36 electrons. \(\mathrm{Mn}^{7+}\): Mn has an atomic number of 25. Since it has a charge of +7, it has lost 7 electrons. Therefore, Mn7+ has 25 - 7 = 18 electrons. \(\mathrm{I}^{-}\): I has an atomic number of 53. Since it has a charge of -1, it has gained 1 electron. Therefore, I- has 53 + 1 = 54 electrons. \(\mathrm{Pb}^{2+}\): Pb has an atomic number of 82. Since it has a charge of +2, it has lost 2 electrons. Therefore, Pb2+ has 82 - 2 = 80 electrons.
03

Identify neutral atoms with the same number of electrons #for_an_element_here#

Now, identify neutral atoms that have the same number of electrons as the given ions: \(\mathrm{Ga} ^{3+}\): A neutral atom with 28 electrons has an atomic number of 28. The element with atomic number 28 is Nickel (Ni). \(\mathrm{Zr}^{4+}\): A neutral atom with 36 electrons has an atomic number of 36. The element with atomic number 36 is Krypton (Kr). \(\mathrm{Mn}^{7+}\): A neutral atom with 18 electrons has an atomic number of 18. The element with atomic number 18 is Argon (Ar). \(\mathrm{I}^{-}\): A neutral atom with 54 electrons has an atomic number of 54. The element with atomic number 54 is Xenon (Xe). \(\mathrm{Pb}^{2+}\): A neutral atom with 80 electrons has an atomic number of 80. The element with atomic number 80 is Mercury (Hg).
04

List the isoelectronic neutral atoms #in_a_list#

The neutral atoms isoelectronic with the given ions are: - \(\mathrm{Ga} ^{3+}\) is isoelectronic with Nickel (Ni). - \(\mathrm{Zr}^{4+}\) is isoelectronic with Krypton (Kr). - \(\mathrm{Mn}^{7+}\) is isoelectronic with Argon (Ar). - \(\mathrm{I}^{-}\) is isoelectronic with Xenon (Xe). - \(\mathrm{Pb}^{2+}\) is isoelectronic with Mercury (Hg).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
When discussing atoms and ions, the concept of electron configuration is key. Electron configuration describes the distribution of electrons around an atom or ion's nucleus into various atomic orbitals. Orbitals are regions around the nucleus where electrons are likely to be found. Each orbital can hold a certain number of electrons. These configurations follow a specific order based on increasing energy levels and obeys the Pauli Exclusion Principle and Hund’s Rule.
The order is often remembered using the sequence:
  • 1s
  • 2s, 2p
  • 3s, 3p
  • 4s, 3d, 4p
  • 5s, 4d, 5p

Understanding electron configurations helps explain chemical behavior and is crucial for identifying isoelectronic species. Isoelectronic species have the same number of electrons, so their electron configurations match. This is why ions like \( ext{Ga}^{3+}, ext{Zr}^{4+}, ext{Mn}^{7+}, ext{I}^{-}, ext{and Pb}^{2+}\), despite their charges, share electron configurations with certain neutral atoms.
Atomic Number
The atomic number of an element is one of its most fundamental properties. It is denoted by the symbol \(Z\) and signifies the number of protons found in the nucleus of an atom. This number determines the identity of the element and its place in the periodic table. For a neutral atom, the atomic number is also equal to the number of electrons surrounding the nucleus.
The atomic number is essential when working with ions because it helps determine the number of electrons involved when an atom loses or gains electrons to form ions.
  • Neutral atoms: Protons = Electrons
  • Ions: Protons \(eq\) Electrons

Knowing the atomic number allows us to understand how an atom becomes isoelectronic with another species. For instance, if a neutral atom has an atomic number of 28, it means it has 28 electrons, making it isoelectronic with \( ext{Ga}^{3+}\) which also has 28 electrons despite having lost some.
Ions
Ions are atoms or molecules that have gained or lost one or more electrons, resulting in a net charge. They can be classified as cations or anions.
  • Cations: Positively charged ions (e.g., \( ext{Ga}^{3+}\))
  • Anions: Negatively charged ions (e.g., \( ext{I}^{-}\))

These charged species form due to the atoms striving to achieve stability, often by having a full outer shell of electrons, similar to noble gases. Losing electrons results in a positive charge, while gaining electrons results in a negative charge.
Understanding ions is crucial for identifying isoelectric species because the number of electrons in ions can match those of a neutral atom with a similar electron configuration. This similarity directly affects their chemical and physical properties.
Neutral Atoms
Neutral atoms are basic units of elements with an equal number of protons and electrons, leading to no overall charge. They are the starting point for understanding atoms and ions. In a neutral atom, the positively charged protons in the nucleus equal the number of negatively charged electrons surrounding it.
Since the electron configuration in a neutral atom is unchanged by any external charge, it becomes the benchmark for comparing different atomic or ionic species. When determining isoelectronic species, the focus is on finding neutral atoms that share the same number of electrons with charged ions. This equivalency helps in understanding chemical reactivity and stability characteristics. For example, a neutral Krypton (Kr), with 36 electrons, is isoelectronic with \( ext{Zr}^{4+}\), which also has 36 electrons, despite its complete outer shell configuration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Zincin its \(2+\) oxidation state is an essential metal ion for life. \(\mathrm{Zn}^{2+}\) is found bound to many proteins that are involved in biological processes, but unfortunately \(\mathrm{Zn}^{2+}\) is hard to detect by common chemical methods. Therefore, scientists who are interested in studying \(\mathrm{Zn}^{2+}\) -containing proteins frequently substitute \(\mathrm{Cd}^{2+}\) for \(\mathrm{Zn}^{2+},\) since \(\mathrm{Cd}^{2+}\) is easier to detect. (a) On the basis of the properties of the elements and ions discussed in this chapter and their positions in the periodic table, describe the pros and cons of using \(\mathrm{Cd}^{2+}\) as a \(\mathrm{Zn}^{2+}\) substitute. (b) Proteins that speed up (catalyze) chemical reactions are called enzymes. Many enzymes are required for proper metabolic reactions in the body. One problem with using \(\mathrm{Cd}^{2+}\) to replace \(\mathrm{Zn}^{2+}\) in enzymes is that \(\mathrm{Cd}^{2+}\) substitution can decrease or even eliminate enzymatic activity. Can you suggest a different metal ion that might replace \(Z n^{2+}\) in enzymes instead of \(C d^{2+} ?\) Justify your answer.

Arrange the following atoms in order of increasing effective nuclear charge experienced by the electrons in the \(n=3\) electron shell: \(\mathrm{K}, \mathrm{Mg}, \mathrm{P}, \mathrm{Rh} , \mathrm{Ti}.\)

As we move across a period of the periodic table, why do the sizes of the transition elements change more gradually than those of the representative elements?

(a) One of the alkali metals reacts with oxygen to form a solid white substance. When this substance is dissolved in water, the solution gives a positive test for hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}.\) When the solution is tested in a burner flame, a lilac-purple flame is produced. What is the likely identity of the metal? (b) Write a balanced chemical equation for the reaction of the white substance with water.

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.