/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Write out the ground-state elect... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write out the ground-state electron configurations of (a) \(\mathrm{Ti}^{3+},(\mathbf{b}) \mathrm{Ru}^{2+},(\mathbf{c}) \mathrm{Au}^{3+},(\mathbf{d}) \mathrm{Mn}^{4+} .\)

Short Answer

Expert verified
The ground-state electron configurations of the ions are: a) \(\mathrm{Ti}^{3+}\): \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^1\) b) \(\mathrm{Ru}^{2+}\): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^6\) c) \(\mathrm{Au}^{3+}\): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 4f^{14} 5d^8\) d) \(\mathrm{Mn}^{4+}\): \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^3\)

Step by step solution

01

(a) Titanium ion (\(\mathrm{Ti}^{3+}\)) electron configuration

1. Find the atomic number of Titanium (Ti). In the periodic table, it is 22. 2. Determine the electron configuration of the neutral atom: \[\mathrm{Ti}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2\] 3. Remove three electrons from the atom to form the ion \(\mathrm{Ti}^{3+}\), starting from the outermost shell: \[\mathrm{Ti}^{3+}: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^1\]
02

(b) Ruthenium ion (\(\mathrm{Ru}^{2+}\)) electron configuration

1. Find the atomic number of Ruthenium (Ru). In the periodic table, it is 44. 2. Determine the electron configuration of the neutral atom: \[\mathrm{Ru}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^6\] 3. Remove two electrons from the atom to form the ion \(\mathrm{Ru}^{2+}\), starting from the outermost shell: \[\mathrm{Ru}^{2+}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^6\]
03

(c) Gold ion (\(\mathrm{Au}^{3+}\)) electron configuration

1. Find the atomic number of Gold (Au). In the periodic table, it is 79. 2. Determine the electron configuration of the neutral atom: \[\mathrm{Au}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 4f^{14} 5d^{10} 6s^1\] 3. Remove three electrons from the atom to form the ion \(\mathrm{Au}^{3+}\), starting from the outermost shell: \[\mathrm{Au}^{3+}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 4f^{14} 5d^8\]
04

(d) Manganese ion (\(\mathrm{Mn}^{4+}\)) electron configuration

1. Find the atomic number of Manganese (Mn). In the periodic table, it is 25. 2. Determine the electron configuration of the neutral atom: \[\mathrm{Mn}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5\] 3. Remove four electrons from the atom to form the ion \(\mathrm{Mn}^{4+}\), starting from the outermost shell: \[\mathrm{Mn}^{4+}: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^3\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Oxidation states, also known as oxidation numbers, are a way to keep track of the electrons in atoms as they form compounds or ions. In essence, they describe how many electrons an atom gains or loses when it forms an ion or compound. For example, Titanium (Ti), with an oxidation state of +3, indicates the loss of three electrons to become \(\mathrm{Ti}^{3+}\). This is essential because understanding oxidation states helps you predict how different elements will react with each other in chemical reactions.
  • Positive oxidation states, like \(\mathrm{Fe}^{3+}\), suggest lost electrons.
  • Negative oxidation states indicate gained electrons.
Grasping oxidation states is critical in electron configurations because the oxidation state tells us how many electrons are removed from or added to the element's neutral atom configuration. Remember, electrons are removed first from the outermost shell, which is why Titanium as \(\mathrm{Ti}^{3+}\) loses electrons from the 4s orbital in its electron configuration, leading to the configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^1\). This step-by-step removal is vital in predicting the chemical behavior of ions in compounds.
Transition Metals
Transition metals are elements found in the d-block of the periodic table. They are characterized by having d orbitals that are being filled with electrons. These metals, such as Titanium (Ti), Ruthenium (Ru), and Gold (Au), often have multiple oxidation states. This flexibility arises because electrons in the d orbital can be lost or shared in chemical reactions, allowing for a variety of cations. Some key features of transition metals:
  • They often form colored compounds.
  • They can have multiple stable oxidation states.
  • They are typically good conductors of electricity.
The diversity in possible oxidation states makes the chemical behavior of transition metals complex but fascinating. For example, Mn (Manganese) can exist in oxidation states from +2 to +7. This versatility is crucial in many biological and industrial processes, such as the role of iron in hemoglobin or the use of noble metals in catalysts. Understanding this concept will help you not only with writing electron configurations but also with predicting how these metals interact in various chemical environments.
Atomic Number
The atomic number is fundamental in understanding elements. It represents the number of protons in an atom's nucleus and determines the chemical identity of the element. For instance, Titanium has an atomic number of 22, meaning every titanium atom contains 22 protons. This number also equals the number of electrons in a neutral atom. Knowing the atomic number allows you to:
  • Identify an element on the periodic table.
  • Determine the standard electron configuration for neutral atoms.
  • Understand the charge and behavior of an element in ions and compounds.
In electron configuration notations, the atomic number guides how electrons are disposed across various orbitals. When writing electron configurations for ions, like Gold which has the atomic number 79, one removes electrons starting from the highest energy level based on the atomic arrangement. Thus, understanding the atomic number is crucial for predicting how elements transition between different states and form compounds or ions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A compound with formula \(\mathrm{RuCl}_{3}\) \(\cdot 5 \mathrm{H}_{2} \mathrm{O}\) is dissolved in water, forming a solution that is approximately the same color as the solid. Immediately after forming the solution, the addition of excess AgNO \(_{3}(a q)\) forms 2 mol of solid AgCl per mole of complex. Write the formula for the compound, showing which ligands are likely to be present in the coordination sphere. (b) After a solution of \(\mathrm{RuCl}_{3}\) \(\cdot 5 \mathrm{H}_{2} \mathrm{O}\) has stood for about a year, addition of \(\mathrm{AgNO}_{3}(a q)\) precipitates 3 mol of AgCl per mole of complex. What has happened in the ensuing time?

Give the number of (valence) \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right (\mathbf{b})\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left(\mathrm{NO}_{3}\right)_{2},(\mathbf{c}) \mathrm{Na}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]\) (d) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{ClO}_{4},(\mathbf{e})[\operatorname{Sr}(\mathrm{EDTA})]^{2-}\)

The square-planar complex \(\left[\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2}\right]\) only forms in one of two possible geometric isomers. Which isomer is not observed: cis or trans?

In 2001 , chemists at SUNY-Stony Brook succeeded in synthesizing the complex trans-\(\left[\mathrm{Fe}(\mathrm{CN})_{4}(\mathrm{CO})_{2}\right]^{2-}\), which could be a model of complexes that may have played a role in the origin of life. (a) Sketch the structure of the complex. (b) The complex is isolated as a sodium salt. Write the complete name of this salt. (c) What is the oxidation state of Fein this complex? How many d electrons are associated with the Fe in this complex? (d) Would you expect this complex to be high spin or low spin? Explain.

Which type of magnetic material cannot be used to make permanent magnets, a ferromagnetic substance, an anti-ferromagnetic substance, or a ferrimagnetic substance?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.