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The half-life for the process \(^{238} \mathrm{U} \longrightarrow^{206} \mathrm{Pb}\) is \(4.5 \times 10^{9} \mathrm{yr}.\) A mineral sample contains 75.0 \(\mathrm{mg}\) of \(^{238} \mathrm{U}\) and 18.0 \(\mathrm{mg}\) of \(^{206} \mathrm{pb} .\) What is the age of the minineral?

Short Answer

Expert verified
The age of the mineral sample containing ^238U and ^206Pb is approximately \(1.959 \times 10^9\ \text{years}\).

Step by step solution

01

Understand the Half-Life Formula

The formula to calculate the number of half-lives that have occurred for a radioactive process is: \[N(t) = N_{0} \times (1/2)^{t/T}\] Where: - \(N(t)\) is the remaining amount of the substance at time \(t\) - \(N_{0}\) is the initial amount of the substance - \(t\) is the time elapsed - \(T\) is the half-life of the process
02

Calculate the Amount of Original ^238U

We know that at time t, the remaining ^238U in the sample is 75.0 mg, and the amount of ^206Pb is 18.0 mg. Since ^238U decays into ^206Pb, we can find the original amount of ^238U by summing the remaining ^238U and the amount of ^206Pb produced. \[N_0 = 75.0 + 18.0 = 93.0\ \text{mg}\]
03

Rewrite the Half-Life Formula for Time

Now we need to solve for the time \(t\), so we must rearrange the half-life formula to isolate \(t\). \[\frac{N(t)}{N_0} = (1/2)^{t/T}\] Taking the logarithm of both sides will eliminate the exponent and give us the age of the mineral sample: \[t = T \times \frac{\log(\frac{N(t)}{N_0})}{\log(1/2)}\]
04

Substitute Known Values and Calculate Time

Now, substitute the known values into the equation: \[t = 4.5 \times 10^{9}\ \text{yr} \times \frac{\log(\frac{75}{93})}{\log(1/2)}\] Using a calculator, we can find the age of the mineral: \[t \approx 1.959 \times 10^9\ \text{yr}\]
05

Present the Answer

The age of the mineral sample containing ^238U and ^206Pb is approximately \(1.959 \times 10^9\ \text{years}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life Calculation
The concept of half-life is fundamental in understanding radioactive decay. It refers to the time required for half of a given quantity of a radioactive substance to undergo decay. This process follows an exponential decay function.
The half-life formula is expressed as \( N(t) = N_0 \times (1/2)^{t/T} \), where:
  • \( N(t) \) is the remaining quantity of the substance at time \( t \).
  • \( N_0 \) is the initial quantity.
  • \( T \) is the half-life duration.
This equation helps us calculate how much of a substance remains after any number of half-lives by utilizing logarithmic manipulation to solve for time \( t \), giving insight into the age or remaining amount of the substance. Understanding these calculations allows us to determine the progression and timeline of decay processes, which are imperative in fields like archaeology and geology.
Radioisotope Dating
Radioisotope dating is an essential tool used to determine the age of objects by measuring radioactive isotopes within them.
This method utilizes the known decay rate of isotopes, such as the decay of \( ^{238}\text{U} \) to \( ^{206}\text{Pb} \), to calculate the time elapsed since the mineral sample formed. By knowing the half-life and measuring the ratio of the parent isotope to the daughter isotope (product of decay), we can precisely calculate the age of geological samples.
Through the example of \( ^{238}\text{U} \longrightarrow ^{206}\text{Pb} \), we assume the sample originally contained only \( ^{238}\text{U} \). Over time, some of this uranium decayed into \( ^{206}\text{Pb} \), allowing scientists to establish the age of the sample by evaluating the amounts of each element present.
This robust dating method offers a reliable way to age-date rocks, fossils, and other ancient materials, heavily aiding in fields like paleontology and earth sciences.
Nuclear Chemistry
Nuclear chemistry is the study of reactions and processes that involve changes in atomic nuclei. This fascinating branch of chemistry touches on topics such as radioactive decay, nuclear reactions, and fission and fusion processes.
Radioactive decay itself includes mechanisms like alpha decay, where an atom emits an alpha particle, and beta decay, where an atom ejects electrons or positrons. These processes exemplify how elements transmutate into different forms.
In radioisotope dating and decay, as seen with \( ^{238}\text{U} \to ^{206}\text{Pb} \), an understanding of nuclear reactions plays a crucial role. It is through these reactions that we can understand the stability of nucleus variations and the energy changes accompanying them.
Nuclear chemistry is instrumental in diverse applications such as medical imaging, cancer treatment through radiotherapy, and providing a framework for understanding cosmic processes. As we delve deeper into the core of atoms, nuclear chemistry continues to expand our understanding of the universe and the fundamental laws that govern it.

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Most popular questions from this chapter

Write balanced nuclear equations for the following transformations: \((\mathbf{a})\) bismuth-213 undergoes alpha decay; \((\mathbf{b})\) nitrogen-13 undergoes electron capture; \((\mathbf{c})\) technicium-98 undergoes electron capture; \((\mathbf{d})\) gold-188 decays by positron emission.

Chlorine has two stable nuclides, \(^{35} \mathrm{Cl}\) and \(^{37} \mathrm{Cl} .\) In contrast, \(^{36} \mathrm{Cl}\) is a radioactive nuclide that decays by beta emission. (a) What is the product of decay of \(^{36} \mathrm{Cl} ?\) (b) Based on the empirical rules about nuclear stability, explain why the nucleus of \(^{36} \mathrm{C}\) is less stable than either \(^{35}\mathrm{Cl}\) or \(^{37} \mathrm{Cl}\).

When two protons fuse in a star, the product is \(^{2} \mathrm{H}\) plus a positron. Write the nuclear equation for this process.

The thermite reaction, \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Al}(s) \longrightarrow 2 \mathrm{Fe}(s)+\) \(\mathrm{Al}_{2} \mathrm{O}_{3}(s), \Delta H^{\circ}=-851.5 \mathrm{kJ} / \mathrm{mol},\) is one of the most exothermic reactions known. Because the heat released is sufficient to melt the iron product, the reaction is used to weld metal under the ocean. How much heat is released per mole of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) produced? How does this amount of thermal energy compare with the energy released when 2 mol of protons and 2 mol of neutrons combine to form 1 mol of alpha particles?

Radium-226, which undergoes alpha decay, has a half-life of 1600 yr. (a) How many alpha particles are emitted in 5.0 min by a 10.0 -mg sample of \(^{226} \mathrm{Ra}\) ? (b) What is the activity of the sample in mCi?

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