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Indicate whether each of the following statements is true or false: (a) If something is reduced, it is formally losing electrons. (b) A reducing agent gets oxidized as it reacts. (c) An oxidizing agent is needed to convert CO into \(\mathrm{CO}_{2}\) .

Short Answer

Expert verified
(a) False - Reduction means a species is gaining electrons, not losing them. (b) True - A reducing agent gets oxidized as it reacts. (c) True - An oxidizing agent is needed to convert CO to \(\mathrm{CO}_{2}\).

Step by step solution

01

(a) Analyzing the statement about reduction and electron loss.

A reduction reaction is one in which a species gains electrons. It's important to remember the mnemonic "LEO says GER" or "Loss of Electrons is Oxidation; Gain of Electrons is Reduction." Thus, the statement is false since a reduction means an electron gain and not loss.
02

(b) Analyzing the statement about reducing agents.

A reducing agent is a substance that reduces other species, meaning it helps other species gain electrons. In doing so, the reducing agent itself loses electrons and gets oxidized. Therefore, the statement is true.
03

(c) Analyzing the statement about converting CO to CO2.

The conversion of CO to \(\mathrm{CO}_{2}\) involves adding an oxygen atom to the CO molecule. This process requires an oxidizing agent, which has the ability to remove electrons from another substance. Specifically, it's needed to transfer an oxygen atom (or a part of it) to CO. Thus, the statement is true. #Summary#: We have determined the truthfulness of the following statements: (a) False - Reduction means a species is gaining electrons, not losing them. (b) True - A reducing agent gets oxidized as it reacts. (c) True - An oxidizing agent is needed to convert CO to \(\mathrm{CO}_{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction Definition
In the world of chemistry, reduction is a fundamental concept that involves the gain of electrons by a molecule, atom, or ion. It might sound a bit technical, but think of it as a way for a species to receive electrons. This means that during a reduction reaction, the charge of the species becomes more negative or, in other words, its oxidation state decreases. A mnemonic to help remember this is "LEO says GER," which stands for "Loss of Electrons is Oxidation; Gain of Electrons is Reduction."

Reduction is often paired with oxidation in what's called a redox reaction, where one species is reduced and another is oxidized. You could visualize it as a give-and-take relationship in the exchange of electrons. Interestingly, in biology, reduction doesn't solely focus on electrons; it can also involve the addition of hydrogen to the reduced molecule or loss of oxygen.
Oxidation Definition
Oxidation is the process opposite to reduction. It involves the loss of electrons from a molecule, atom, or ion. Again, it helps to remember the phrase "LEO says GER." Here, "LEO" stands for "Loss of Electrons is Oxidation." This loss of electrons leads to an increase in the oxidation state, meaning the species becomes more positive.

Oxidation can be visualized in everyday examples, such as the rusting of iron, where iron loses electrons to oxygen in the air. Other times, oxidation involves gaining oxygen atoms or losing hydrogen atoms. Like two sides of a coin, oxidation and reduction always occur together in a redox reaction, contributing to many biological and chemical processes. These reactions are critical in industries and natural phenomena, from energy production to cellular respiration in living organisms.
Reducing and Oxidizing Agents
In every redox reaction, there are agents that drive the respective processes of oxidation and reduction. The reducing agent, sometimes called a reductant, facilitates the reduction of another species by donating electrons to it. Interestingly, as it donates electrons, the reducing agent itself gets oxidized. Paper clips rusting away and batteries running low are practical examples where reducing agents play a role.

Conversely, the oxidizing agent, or oxidant, facilitates oxidation by accepting electrons from another species. This process leads to it becoming reduced. A classic example of an oxidizing agent is bleach, which works by stripping electrons away from stains on clothes or surfaces.
  • A strong reducing agent has a high tendency to lose electrons easily, such as lithium or sodium.
  • A strong oxidizing agent readily accepts electrons, such as fluorine or chlorine, known for their high electronegativity.
Understanding the roles of these agents is crucial, as they are indispensable in various chemical reactions, including combustion, metabolism, and even photography.

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Most popular questions from this chapter

(a) What is electrolysis? (b) Are electrolysis reactions thermodynamically spontaneous? (c) What process occurs at the anode in the electrolysis of molten \(\mathrm{NaCl}\) (d) Why is sodium metal not obtained when an aqueous solution of NaCl undergoes electrolysis?

(a) Calculate the mass of Li formed by electrolysis of molten LiCl by a current of \(7.5 \times 10^{4}\) A flowing for a period of 24 \(\mathrm{h} .\) Assume the electrolytic cell is 85\(\%\) efficient. (b) What is the minimum voltage required to drive the reaction?

Indicate whether each statement is true or false: (a) The anode is the electrode at which oxidation takes place. (b) A voltaic cell always has a positive emf. (c) A salt bridge or permeable barrier is necessary to allow a voltaic cell to operate.

Using standard reduction potentials (Appendix E), calculate the standard emf for each of the following reactions: $$ \begin{array}{l}{\text { (a) } \mathrm{Cl}_{2}(g)+2 \mathrm{I}^{-}(a q) \longrightarrow 2 \mathrm{Cl}^{-}(a q)+\mathrm{I}_{2}(s)} \\ {\text { (b) } \mathrm{Ni}(s)+2 \mathrm{Ce}^{4+}(a q) \longrightarrow \mathrm{Ni}^{2+}(a q)+2 \mathrm{Ce}^{3+}(a q)} \\ {\text { (c) } \mathrm{Fe}(s)+2 \mathrm{Fe}^{3+}(a q) \longrightarrow 3 \mathrm{Fe}^{2+}(a q)} \\ {\text { (d) } 2 \mathrm{NO}_{3}^{-}(a q)+8 \mathrm{H}^{+}(a q)+3 \mathrm{Cu}(s) \longrightarrow 2 \mathrm{NO}(g)+} \\ \quad {4 \mathrm{H}_{2} \mathrm{O}(l)+3 \mathrm{Cu}^{2+}(a q)}\end{array} $$

A common shorthand way to represent a voltaic cell is $$ \text {anode} | \text {anode solution} | | \text {cathode solution} | \text {cathode} $$ A double vertical line represents a salt bridge or a porous barrier. A single vertical line represents a change in phase, such as from solid to solution. (a) Write the half-reactions and overall cell reaction represented by Fel Fe \(^{2+} \| \operatorname{Ag}^{+} | A g;\) calculate the standard cell emf using data in Appendix E. (b) Write the half-reactions and overall cell reaction represented by Zn \(\left|Z \mathrm{n}^{2+}\right| \mathrm{H}^{+} | \mathrm{H}_{2} ;\) calculate the standard cell emf using data in Appendix E and use Pt for the hydrogen electrode. (c) Using the notation just described, represent a cell based on the following reaction: $$ \begin{aligned} \mathrm{ClO}_{3}^{-}(a q)+3 \mathrm{Cu}(s)+6 \mathrm{H}^{+}(a q) & \\ \longrightarrow & \mathrm{Cl}^{-}(a q)+3 \mathrm{Cu}^{2+}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) \end{aligned} $$ Pt is used as an inert electrode in contact with the ClO \(_{3}^{-}\) and \(\mathrm{Cl}^{-} .\) Calculate the standard cell emf given: \(\mathrm{ClO}_{3}^{-}(a q)+\) \(6 \mathrm{H}^{+}(a q)+6 \mathrm{e}^{-} \longrightarrow \mathrm{Cl}^{-}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l); E^{\circ}=1.45 \mathrm{V}\).

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