/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Predict whether each of the foll... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Predict whether each of the following compounds is molecular or ionic: (a) \(\mathrm{B}_{2} \mathrm{H}_{6},(\mathbf{b}) \mathrm{CH}_{3} \mathrm{OH},(\mathbf{c}) \mathrm{LiNO}_{3},(\mathbf{d}) \mathrm{Sc}_{2} \mathrm{O}_{3}\) (e) \(\mathrm{CsBr},(\mathbf{f}) \mathrm{NOCl},(\mathbf{g}) \mathrm{NF}_{3},(\mathbf{h}) \mathrm{Ag}_{2} \mathrm{SO}_{4}\)

Short Answer

Expert verified
(a) B2H6: molecular, (b) CH3OH: molecular, (c) LiNO3: ionic, (d) Sc2O3: ionic, (e) CsBr: ionic, (f) NOCl: molecular, (g) NF3: molecular, (h) Ag2SO4: ionic.

Step by step solution

01

(a) B2H6 (Boron Hydrogen)

As Boron (B) and Hydrogen (H) are both non-metal elements, the compound B2H6 is molecular.
02

(b) CH3OH (Methanol)

Since Carbon (C), Hydrogen (H), and Oxygen (O) are all non-metal elements, the compound CH3OH is molecular.
03

(c) LiNO3 (Lithium Nitrate)

Because Lithium (Li) is a metal element, and Nitrogen (N) and Oxygen (O) are non-metal elements, the compound LiNO3 is ionic.
04

(d) Sc2O3 (Scandium Oxide)

As Scandium (Sc) is a metal element and Oxygen (O) is a non-metal element, the compound Sc2O3 is ionic.
05

(e) CsBr (Cesium Bromide)

Since Cesium (Cs) is a metal element and Bromine (Br) is a non-metal element, the compound CsBr is ionic.
06

(f) NOCl (Nitrosyl Chloride)

Given that Nitrogen (N), Oxygen (O), and Chlorine (Cl) are all non-metal elements, the compound NOCl is molecular.
07

(g) NF3 (Nitrogen Trifluoride)

As Nitrogen (N) and Fluorine (F) are both non-metal elements, the compound NF3 is molecular.
08

(h) Ag2SO4 (Silver Sulfate)

Because Silver (Ag) is a metal element, and Sulfur (S) and Oxygen (O) are non-metal elements, the compound Ag2SO4 is ionic.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Bonding
Chemical bonding is a fundamental concept in understanding how different atoms connect to form compounds. It primarily involves two types of bonds: ionic and covalent. Ionic bonds occur when there is a transfer of electrons from a metal to a non-metal. This results in oppositely charged ions attracting each other. On the other hand, covalent bonds form when two non-metals share electrons. This sharing allows both atoms to attain a stable electron configuration.

A compound's behavior, including solubility and melting points, can often be attributed to the types of bonds it contains. Understanding whether a compound is ionic or covalent can thus help predict its properties. In short, chemical bonding is crucial as it determines how different substances are held together and interact with each other.
Compound Classification
Based on the types of elements involved and the nature of the chemical bonds, compounds are classified into two main categories: molecular (or covalent) compounds and ionic compounds.

Molecular compounds are formed from non-metal atoms. They are usually present as discrete molecules, like ext{(a) ext{B}_2 ext{H}_6} and ext{(b) ext{CH}_3 ext{OH}} in the exercise. These compounds tend to have lower melting and boiling points due to the relatively weak interactions between the molecules.

Ionic compounds result from metals reacting with non-metals, creating a lattice structure held together by strong ionic bonds. Examples include ext{(c) ext{LiNO}_3} and ext{(d) ext{Sc}_2 ext{O}_3} from the exercise. These compounds generally exhibit high melting and boiling points and often dissolve in water to form electrolytes.
Metal and Non-metal Elements
To identify whether a compound is molecular or ionic, understanding the distinction between metal and non-metal elements is essential. Metals, like lithium ( ext{Li}), scandium ( ext{Sc}), and cesium ( ext{Cs}) in the exercise, are typically found on the left side and center of the periodic table. They tend to lose electrons easily, forming positive ions, which is a key characteristic in ionic compound formation.

Non-metals, such as nitrogen ( ext{N}), oxygen ( ext{O}), and chlorine ( ext{Cl}), are located on the right side of the periodic table. These elements usually gain or share electrons in bonds, forming structures like ext{(e) ext{CsBr}} for ionic and ext{(f) ext{NOCl}} for molecular compounds.

The combination of metal and non-metal elements signifies a likelihood of ionic bonding, while compounds solely containing non-metals often point toward molecular bonding. Understanding these differences can simplify predicting compound classifications and their properties.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Because many ions and compounds have very similar names, there is great potential for confusing them. Write the correct chemical formulas to distinguish between \((\mathbf{a})\) calcium sulfide and calcium hydrogen sulfide, \((\mathbf{b})\) hydrobromic acid and bromic acid \((\mathbf{c})\) aluminum nitride and aluminum nitrite,\((\mathbf{d})\)iron(II) oxide and iron(III) oxide,\((\mathbf{e})\)ammonia and ammonium ion, \((\mathbf{f})\)potassium sulfite and potassium bisulfite,\((\mathbf{g})\) mercurous chloride and mercuric chloride, \((\mathbf{h})\) chloric acid and perchloric acid.

The diameter of a rubidium atom is 4.95 A. We will consider two different ways of placing the atoms on a surface. In arrangement \(A,\) all the atoms are lined up with one another to form a square grid. Arrangement B is called a close-packed arrangement because the atoms sit in the "depressions" formed by the previous row of atoms:(a) Using arrangement A, how many Rb atoms could be placed on a square surface that is 1.0 \(\mathrm{cm}\) on a side? ( b) How many Rb atoms could be placed on a square surface that is 1.0 \(\mathrm{cm}\) on a side, using arrangement \(\mathrm{B} ?(\mathbf{c})\) By what factor has the number of atoms on the surface increased in going to arrangement \(\mathrm{B}\) from arrangement A? If extended to three dimensions, which arrangement would lead to a greater density for Rb metal?

A charged particle moves between two electrically charged plates, as shown here.\(\begin{array}{l}{\text { (a) What is the sign of the electrical charge on the particle? }} \\ {\text { (b) As the charge on the plates is increased, would you ex- }} \\ {\text { pect the bending to increase, decrease, or stay the same? }}\end{array}$$\begin{array}{l}{\text { (c) As the mass of the particle is increased while the speed of }} \\ {\text { the particles remains the same, would you expect the bending }} \\ {\text { to increase, decrease, or stay the same? [Section } 2.2 ]}\end{array}\)

Identify the element represented by each of the following symbols and give the number of protons and neutrons in each: \((\mathbf{a})_{33}^{74} X,(\mathbf{b}) \frac{1}{33} X$$(\mathbf{c})_{63}^{152} \mathrm{X},(\mathbf{d}) \frac{209}{83} \mathrm{X}\).

Mass spectrometry is more often applied to molecules than to atoms. We will see in Chapter 3 that the molecular weight of a molecule is the sum of the atomic weights of the atoms in the molecule. The mass spectrum of \(\mathrm{H}_{2}\) is taken under conditions that prevent decomposition into \(\mathrm{H}\) atoms.The two naturally occurring isotopes of hydrogen are \(^{1} \mathrm{H}\) (atomic mass \(=1.00783\) amu; abundance 99.9885\(\% )\) and 2H (atomic mass \(=2.01410\) amu; abundance 0.0115\(\% ) .\) (a) How many peaks will the mass spectrum have? (b) Give the relative atomic masses of each of these peaks. (c) Which peak will be the largest, and which the smallest?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.