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Using the value of \(K_{s p}\) for \(\mathrm{Ag}_{2} \mathrm{S}, K_{a 1}\) and \(K_{a 2}\) for \(\mathrm{H}_{2} \mathrm{S},\) and \(K_{f}=1.1 \times 10^{5}\) for \(\mathrm{AgCl}_{2}^{-}\) , calculate the equilibrium constant for the following reaction: \(\mathrm{Ag}_{2} \mathrm{S}(s)+4 \mathrm{Cl}^{-}(a q)+2 \mathrm{H}^{+}(a q) \rightleftharpoons 2 \mathrm{AgCl}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{S}(a q)\)

Short Answer

Expert verified
To find the equilibrium constant for the overall reaction, multiply the individual equilibrium constants: \(K = K_{sp} \times K_{a1} \times K_{a2} \times K_{f}^{2}\).

Step by step solution

01

Determine the initial reaction equations and their respective equilibrium constants.

We have the following reactions and their equilibrium constants: 1. \(\mathrm{Ag}_{2} \mathrm{S}(s) \rightleftharpoons 2\mathrm{Ag}^{+}(a q)+\mathrm{S}^{2-}(a q)\) with \(K_{sp}\) 2. \(\mathrm{H}_{2} \mathrm{S}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{HS}^{-}(a q)\) with \(K_{a1}\) 3. \(\mathrm{HS}^{-}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{S}^{2-}(a q)\) with \(K_{a2}\) 4. 2 \(\mathrm{Ag}^{+}(a q) + 2 \mathrm{Cl}^{-}(a q) \rightleftharpoons \mathrm{AgCl}_{2}^{-}(a q)\) with \(K_{f}\)
02

Determine the overall reaction.

Now we'll combine the given reactions in such a way that they add up to the desired reaction without changing the \(K_{sp}, K_{a1}, K_{a2}\), and \(K_{f}\) constants nor the stoichiometric coefficients. The overall reaction is: $\mathrm{Ag}_{2} \mathrm{S}(s)+4 \mathrm{Cl}^{-}(a q)+2 \mathrm{H}^{+}(a q) \rightleftharpoons 2 \mathrm{AgCl}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{S}(a q)$
03

Calculate the equilibrium constant for the overall reaction.

When we multiply or divide the reactions, we can simply do the same with the equilibrium constants (multiply, divide, raise to powers). In this case, we need to combine reaction 1, reaction 2, reaction 3, and reaction 4 (multiplied by 2) such that: 1 * 2 * 3 * (4^2) = overall reaction Hence, the equilibrium constant for the given reaction can be calculated by multiplying the individual equilibrium constants: \(K = K_{sp} \times K_{a1} \times K_{a2} \times K_{f}^{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Product (Ksp)
The solubility product constant, often abbreviated as \( K_{sp} \), is crucial in predicting the solubility of ionic compounds in water. It specifically applies to sparingly soluble salts, such as \( \text{Ag}_2\text{S} \) in the given exercise.

The formula for the solubility product of a salt \( ext{A} ext{B} ightleftharpoons ext{A}^{+} + ext{B}^{-} \) is given by: \[ K_{sp} = [A^+]^a[B^-]^b \] where \([A^+]\) and \([B^-]\) are the molar concentrations of the ions in the solution at equilibrium and \(a\) and \(b\) are the stoichiometric coefficients.

For \( \text{Ag}_2\text{S} \), which dissociates in water according to: \[ \text{Ag}_2\text{S}(s) \rightleftharpoons 2\text{Ag}^{+}(aq) + \text{S}^{2-}(aq) \] The \( K_{sp} \) expression will be: \[ K_{sp} = [Ag^+]^2[S^{2-}] \] Understanding \( K_{sp} \) helps us determine the extent to which this salt will dissolve in a solution under specified conditions.
Acid Dissociation Constant (Ka)
The acid dissociation constant, represented as \( K_{a} \), measures the strength of an acid in terms of its ability to donate protons (\( H^+ \)) in an aqueous solution.

For a general acid \( HA\) dissociating as: \[ HA(aq) \rightleftharpoons H^+(aq) + A^-(aq) \] The expression for \( K_a \) is: \[ K_{a} = \frac{[H^+][A^-]}{[HA]} \]

In the original problem, \( \text{H}_2\text{S} \) is considered with two dissociation steps and corresponding constants \( K_{a1} \) and \( K_{a2} \):
  • \( \text{H}_2\text{S} \rightleftharpoons H^+ + \text{HS}^- \), described by \( K_{a1} \)
  • \( \text{HS}^- \rightleftharpoons H^+ + \text{S}^{2-} \), described by \( K_{a2} \)

Each \( K_{a} \) value informs us how readily the proton dissociation occurs, with a higher value indicating a stronger acid.
Formation Constant (Kf)
The formation constant, known as \( K_{f} \), describes the stability of complex ions in solution. Specifically, it refers to the equilibrium between the ions that form a complex ion.

For a reaction where a complex ion \( \text{ML}_n \) is formed: \[ M^{+} + nL^{-} \rightleftharpoons ML_n \] the formation constant expression is: \[ K_{f} = \frac{[ML_n]}{[M^+][L^-]^n} \]
In the problem at hand, the reaction involves forming \( \text{AgCl}_2^- \) from \( \text{Ag}^+ \) and \( \text{Cl}^- \). The given \( K_{f} = 1.1 \times 10^5 \) reveals the high stability and likelihood of this complex ion to form in solution.

Stronger complex formation results in larger \( K_{f} \) values, which indicates that even at low reactant concentrations, the complex ion forms readily.

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Most popular questions from this chapter

Baking soda (sodium bicarbonate, \(\mathrm{NaHCO}_{3}\)) reacts with acids in foods to form carbonic acid (\(\mathrm{H}_{2} \mathrm{CO}_{3}\)), which in turn decomposes to water and carbon dioxide gas. In a cake batter, the \(\mathrm{CO}_{2}(g)\) forms bubbles and causes the cake to rise. (a) A rule of thumb in baking is that 1\(/ 2\) teaspoon of baking soda is neutralized by one cup of sour milk. The acid component in sour milk is lactic acid, \(\mathrm{CH}_{3} \mathrm{CH (\mathrm{OH}) \)\mathrm{COOH}\( .Write the chemical equation for this neutralization reaction. (b) The density of baking soda is 2.16 \)\mathrm{g} / \mathrm{cm}^{3} .\( Calculate the concentration of lactic acid in one cup of sour milk(assuming the rule of thumb applies), in units of mol/L. (One cup \)=236.6 \mathrm{mL}=48\( teaspoons). (c) If 1/2 teaspoon of baking soda is indeed completely neutralized by the lactic acid in sour milk, calculate the volume of carbon dioxide gas that would be produced at 1 atm pressure, in an oven set to \)350^{\circ} \mathrm{F}$ .

Aspirin has the structural formula At body temperature \(\left(37^{\circ} \mathrm{C}\right), K_{a}\) for aspirin equals \(3 \times 10^{-5} .\) If two aspirin tablets, each having a mass of \(325 \mathrm{mg},\) are dissolved in a full stomach whose volume is 1 \(\mathrm{L}\) and whose \(\mathrm{pH}\) is \(2,\) what percent of the aspirin is in the form of neutral molecules?

A 1.00 -L. solution saturated at \(25^{\circ} \mathrm{C}\) with lead(lI) iodide contains 0.54 \(\mathrm{g}\) of \(\mathrm{Pbl}_{2}\) . Calculate the solubility- product constant for this salt at \(25^{\circ} \mathrm{C}\) .

Which of the following salts will be substantially more soluble in acidic solution than in pure water: (a) ZnCO \(_{3}\) \(\mathbf{b} ) \mathrm{ZnS},(\mathbf{c}) \mathrm{BiI}_{3},(\mathbf{d}) \mathrm{AgCN},(\mathbf{e}) \mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2} ?\)

How many microliters of 1.000\(M\) NaOH solution must be added to 25.00 \(\mathrm{mL}\) of a 0.1000 \(\mathrm{M}\) solution of lactic acid \(\left[\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\) or \(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right]\) to produce a buffer with \(\mathrm{pH}=3.75 ?\)

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