/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 (a) Most commercial heterogeneou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

Short Answer

Expert verified
(a) Particle size is important in commercial heterogeneous catalysts because smaller particles provide a larger surface area per unit mass, leading to a greater number of active sites for catalytic reactions. Consequently, this results in higher catalytic activity and efficiency. (b) Adsorption plays a crucial role in heterogeneous catalysis by increasing reactant concentrations on the catalyst surface and promoting more effective collisions between reactants, thus enhancing the overall reaction rate. It consists of three steps: adsorption of reactants, reaction on the catalyst surface, and desorption of products.

Step by step solution

01

(a) Importance of particle size in heterogeneous catalysts

Particle size plays a major role in heterogeneous catalysts because it directly affects the surface area. When the particle size is smaller, the surface area of the catalyst per unit mass increases, leading to a larger number of active sites available for catalytic reactions. This increased surface area results in a higher catalytic activity for reactions occurring on the surface of the catalyst. Therefore, commercial heterogeneous catalysts are designed to have small, finely divided particles to maximize their activity, effectiveness, and overall efficiency.
02

(b) Role of adsorption in heterogeneous catalysis

Adsorption is the process where a substance, in this case, the reactants, form a thin layer on the surface of a solid or a liquid, such as the heterogeneous catalyst. In heterogeneous catalysis, the catalyst is typically a solid, while the reactants are in a gas or liquid phase. The role of adsorption in heterogeneous catalysis can be divided into the following steps: 1. Adsorption of reactants: Reactant molecules are adsorbed onto the surface of the catalyst, which increases their concentration on the catalyst's surface. This causes the probability of effective collisions between the reactants to increase, thus increasing the reaction rate. 2. Reaction on the catalyst surface: Within the adsorbed layer, the reactant molecules are brought closer together, allowing them to form bonds more easily. The energy required for the reaction to proceed is often lower due to the orientation and proximity of the reactants, which enhances the reaction rate. 3. Desorption of products: After the reaction occurs, the product molecules no longer need to remain on the catalyst's surface, so they desorb and are released into the surrounding medium. Overall, adsorption plays a vital role in the action of a heterogeneous catalyst by increasing reactant concentrations on the catalyst surface and promoting more effective collisions between the reactants, which in turn enhances the overall reaction rate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) For a generic second-order reaction \(\mathrm{A} \longrightarrow \mathrm{B}\) , what quantity, when graphed versus time, will yield a straight line? (b) What is the slope of the straight line from part line? (b) What is the slope of the straight line from part (a)? (c) Does the half-life of a second-order reaction increase, decrease, or remain the same as the reaction proceeds?

(a) What are the units usually used to express the rates of reactions occurring in solution? (b) As the temperature increases, does the reaction rate increase or decrease? (c) As a reaction proceeds, does the instantaneous reaction rate increase or decrease?

The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at \(30.0 \mathrm{~min}\). Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product: \(\begin{array}{l}{\text { (a) } \mathrm{H}_{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)} \\ {\text { (b) } 2 \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)} \\ {\text { (c) } \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)} \\ {\text { (d) } \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{NH}_{3}(g)}\end{array}\)

The reaction \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2}\) has the rate constant \(k=0.63 M^{-1} \mathrm{s}^{-1}\) . (a) Based on the units for \(k,\) is the reaction first or second order in \(\mathrm{NO}_{2} ?\) ? (b) If the initial concentration of \(\mathrm{NO}_{2}\) is \(0.100 \mathrm{M},\) how would you determine how long it would take for the concentration to decrease to 0.025 \(\mathrm{M}\) ?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.