/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 (a) Consider the combustion of e... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Consider the combustion of ethylene, \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+\) \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) .\) If the concentration of \(\mathrm{C}_{2} \mathrm{H}_{4}\) is decreasing at the rate of \(0.036 \mathrm{M} / \mathrm{s},\) what are the rates of change in the concentrations of \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O} ?(\mathbf{b})\) The rate of decrease in \(\mathrm{N}_{2} \mathrm{H}_{4}\) partial pressure in a closed reaction vessel from the reaction \(\mathrm{N}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) is 74 torr per hour. What are the rates of change of \(\mathrm{NH}_{3}\) partial pressure and total pressure in the vessel?

Short Answer

Expert verified
The rates of change in the concentrations of CO₂ and H₂O are both -0.072 M/s. The rate of change of NH₃ partial pressure is -148 torr/h, and the rate of change of total pressure in the vessel is 0 torr/h.

Step by step solution

01

Write down the given rate of change of Câ‚‚Hâ‚„

The rate of decrease in the concentration of ethylene (Câ‚‚Hâ‚„) is given as: \(\frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt} = -0.036 \, \mathrm{M/s}\)
02

Use stoichiometry to find the rates of change of COâ‚‚ and Hâ‚‚O

From the balanced reaction, we can see the stoichiometric ratios of the reactants and products: 1 mol Câ‚‚Hâ‚„ : 3 mol Oâ‚‚ : 2 mol COâ‚‚ : 2 mol Hâ‚‚O Now, we can find the rates of change in the concentrations of COâ‚‚ and Hâ‚‚O: \(\frac{d[\mathrm{CO}_{2}]}{dt} = 2 \times \frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt}\) \(\frac{d[\mathrm{H}_{2} \mathrm{O}]}{dt} = 2 \times \frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt}\)
03

Calculate the rates of change of COâ‚‚ and Hâ‚‚O

Substitute the given rate of decrease in the concentration of ethylene (C₂H₄) into the equations from step 2: \(\frac{d[\mathrm{CO}_{2}]}{dt} = 2 \times (-0.036 \, \mathrm{M/s}) = -0.072 \, \mathrm{M/s}\) \(\frac{d[\mathrm{H}_{2} \mathrm{O}]}{dt} = 2 \times (-0.036 \, \mathrm{M/s}) = -0.072 \, \mathrm{M/s}\) So, the rate of change in the concentrations of CO₂ and H₂O are -0.072 M/s. #b) Finding the rates of change of NH₃ partial pressure and total pressure in the vessel#
04

Write down the given rate of decrease of Nâ‚‚Hâ‚„ partial pressure

The rate of decrease in the partial pressure of Nâ‚‚Hâ‚„ is given as: \(\frac{dP_{\mathrm{N}_{2} \mathrm{H}_{4}}}{dt} = -74 \, \mathrm{torr/h}\)
05

Use stoichiometry to find the rate of change of NH₃ partial pressure

From the balanced reaction, we can see the stoichiometric ratios of the reactants and products: 1 mol N₂H₄ : 1 mol H₂ : 2 mol NH₃ Now, we can find the rate of change in the partial pressure of NH₃: \(\frac{dP_{\mathrm{NH}_{3}}}{dt} = 2 \times \frac{dP_{\mathrm{N}_{2} \mathrm{H}_{4}}}{dt}\)
06

Calculate the rate of change of NH₃ partial pressure

Substitute the given rate of decrease in the partial pressure of N₂H₄ into the equation from step 2: \(\frac{dP_{\mathrm{NH}_{3}}}{dt} = 2 \times (-74 \, \mathrm{torr/h}) = -148 \, \mathrm{torr/h}\) So, the rate of change of NH₃ partial pressure is -148 torr/h.
07

Calculate the rate of change of total pressure in the vessel

Since one mole of reactants produces one mole of products, there is no change in the total pressure in the vessel. Therefore, the rate of change of the total pressure in the vessel is: \(\frac{dP_{\mathrm{total}}}{dt} = 0 \, \mathrm{torr/h}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Stoichiometry
Understanding reaction stoichiometry is pivotal for analyzing most chemical reactions, including the calculation of reaction rates. Stoichiometry involves the quantitative relationship between the amounts of reactants and products in a chemical reaction. It's anchored in the balanced chemical equation which provides the mole ratios of the substances involved.

Consider the combustion of ethylene given in the exercise. The balanced equation, \(\mathrm{C}_{2}\mathrm{H}_{4}(g)+3\mathrm{O}_{2}(g) \longrightarrow 2\mathrm{CO}_{2}(g)+2\mathrm{ H}_{2}\mathrm{O}(g)\),indicates that 1 mole of ethylene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water. These ratios are used to determine how changes in the concentration of one species will affect the concentration of others. For example, if the concentration of ethylene decreases, the concentrations of carbon dioxide and water will increase, which can be expressed with specific rate relationships based on stoichiometry.
Ethylene Combustion
Ethylene combustion is a chemical reaction where ethylene (\(\mathrm{C}_{2}\mathrm{H}_{4}\)) reacts with oxygen (\(\mathrm{O}_{2}\)) to form carbon dioxide (\(\mathrm{CO}_{2}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)). This process is an example of a combustion reaction, a type of exothermic reaction that releases energy, mainly in the form of heat and sometimes light.

In such reactions, it's crucial to monitor the rate at which the reactants are consumed and the products are formed, which not only affects the energy release but also the control of the reaction process. The reaction rate can be manipulated by various factors such as concentration, temperature, and presence of a catalyst. For instance, as the exercise states, the rate at which the concentration of ethylene decreases is -0.036 M/s, which can be used to calculate the rate of formation of the products using the stoichiometry of the balanced equation.
Rate of Reaction
The rate of a reaction refers to the speed at which reactants are converted into products. This rate can be expressed in terms of the change in concentration of a reactant or product over a certain time period. In the exercise, the rate of ethylene concentration decrease is given, and using the stoichiometric coefficients from the balanced equation, the rates of formation for carbon dioxide and water can be deduced.

For a reaction like ethylene combustion, the rate will determine the amount of heat and light energy produced per unit of time, which is essential for safety and efficiency in industrial processes. Understanding the factors that influence the reaction rate, which include the nature of the reactants, surface area, temperature, concentration, and presence of catalysts, is fundamental for controlling and optimizing chemical reactions.
Partial Pressure Changes
In gas-phase reactions, partial pressure is a measure of the pressure contributed by a specific gas in a mixture of gases. Modification in partial pressure reflects changes in gas concentration. When chemical reactions occur in a closed system, like the decomposition of hydrazine (\(\mathrm{N}_{2}\mathrm{H}_{4}\)), as described in the exercise, the rates of partial pressure changes for each gas can be calculated.

The exercise showcases how stoichiometry dictates the change in partial pressure of ammonia (\(\mathrm{NH}_{3}\)) based on the change in partial pressure of hydrazine. Due to the stoichiometric relationship, a 74 torr/h decrease in hydrazine results in a 148 torr/h increase of ammonia. Nonetheless, since the reaction does not result in a net change in the amount of gas (molecules are neither created nor destroyed, only rearranged), the total pressure in the vessel remains unchanged, demonstrating another essential aspect of chemical reactions: conservation of mass in a closed system.

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Most popular questions from this chapter

The following mechanism has been proposed for the gasphase reaction of chloroform (CHCl_ ) and chlorine:$$\begin{array}{l}{\text { Step } 1 : \mathrm{Cl}_{2}(g) \frac{k_{1}}{k_{-1}} 2 \mathrm{Cl}(g) \text { (fast) }} \\\ {\text { Step } 2 : \mathrm{Cl}(g)+\mathrm{CHCl}_{3}(g) \stackrel{k_{2}}{\longrightarrow} \mathrm{HCl}(g)+\mathrm{CCl}_{3}(g) \text { (slow) }}\end{array}$$ $$ { Step } \quad3 : \quad \mathrm{Cl}(g)+\mathrm{CCl}_{3}(g) \stackrel{k_{3}}{\longrightarrow} \mathrm{CCl}_{4} \quad(\text { fast })$$ (a) What is the overall reaction? (b) What are the intermedi- ates in the mechanism? (c) What is the molecularity of each of the elementary reactions? (d) What is the rate-determining step? (e) What is the rate law predicted by this mechanism? (Hint: The overall reaction order is not an integer.)

Which of the following linear plots do you expect for a reaction \(A \longrightarrow\) products if the kinetics are (a) zero order, (b) first order, or (c) second order? [Section 14.4\(]\)

The reaction between ethyl bromide \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)\) and hydroxide ion in ethyl alcohol at 330 \(\mathrm{K}\) , \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{Br}^{-}(a l c)\) is first order each in ethyl bromide and hydroxide ion. When \(\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right]\) is 0.0477 \(\mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]\) is \(0.100 \mathrm{M},\) the rate of disappearance of ethyl bromide is \(1.7 \times 10^{-7} \mathrm{M} / \mathrm{s}\) (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) How would the rate of disappearance of ethyl bromide change if the solution were diluted by adding an equal volume of pure ethyl alcohol to the solution?

For the elementary process \(\mathrm{N}_{2} \mathrm{O}_{5}(g) \longrightarrow \mathrm{NO}_{2}(g)+\mathrm{NO}_{3}(g)\) the activation energy \(\left(E_{a}\right)\) and overall \(\Delta E\) are 154 \(\mathrm{kJ} / \mathrm{mol}\) and 136 \(\mathrm{kJ} / \mathrm{mol}\) , respectively. (a) Sketch the energy profile for this reaction, and label \(E_{a}\) and \(\Delta E\) . (b) What is the activation energy for the reverse reaction?

Platinum nanoparticles of diameter \(\sim 2 \mathrm{nm}\) are important catalysts in carbon monoxide oxidation to carbondioxide. Platinum crystallizes in a face-centered cubic arrangement with an edge length of 3.924 A. (a) Estimate how many platinum atoms would fit into a 2.0 -nm sphere; the volume of a sphere is \((4 / 3) \pi r^{3} .\) Recall that \(1 \hat{\mathrm{A}}=1 \times 10^{-10} \mathrm{m}\) and \(1 \mathrm{nm}=1 \times 10^{-9} \mathrm{m} .\) (b) Estimate how many platinum atoms are on the surface of a \(2.0-\mathrm{nm}\) Pt sphere, using the surface area of a sphere \(\left(4 \pi r^{2}\right)\) and assuming that the "footprint" of one Pt atom can be estimated from its atomic diameter of 2.8 A. (c) Using your results from (a) and (b), calculate the percentage of Pt atoms that are on the surface of a 2.0 -nm nanoparticle. (d) Repeat these calculations for a 5.0 -nm platinum nanoparticle. (e) Which size of nanoparticle would you expect to be more catalytically active and why?

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