/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 At ordinary body temperature \(\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At ordinary body temperature \(\left(37^{\circ} \mathrm{C}\right),\) the solubility of \(\mathrm{N}_{2}\) in water at ordinary atmospheric pressure \((1.0 \mathrm{atm})\) is 0.015 \(\mathrm{g} / \mathrm{L} .\) Air is approximately 78 \(\mathrm{mol} \% \mathrm{N}_{2}\) . (a) Calculate the number of moles of \(\mathrm{N}_{2}\) dissolved per liter of blood, assuming blood is a simple aqueous solution. (b) At a depth of 100 \(\mathrm{ft}\) in water, the external pressure is 4.0 atm. What is the solubility of \(\mathrm{N}_{2}\) from air in blood at this pressure? (c) If a scuba diver suddenly surfaces from this depth, how many milliliters of \(\mathrm{N}_{2}\) gas, in the form of tiny bubbles, are released into the bloodstream from each liter of blood?

Short Answer

Expert verified
When a scuba diver suddenly surfaces from a depth of 100 ft, approximately 41 mL of Nâ‚‚ gas (in the form of tiny bubbles) is released into the bloodstream from each liter of blood.

Step by step solution

01

Calculate the moles of Nâ‚‚ dissolved in water

Given the solubility of N₂ in water is 0.015 g/L, we can calculate the number of moles of N₂ dissolved using the formula: Number of moles = mass / molar mass Where the molar mass of N₂ is 28 g/mol. Now we can find the number of moles dissolved in 1 L of water. Number of moles = 0.015 g / 28 g/mol ≈ \(5.36 \times 10^{-4}\) mol #b) Finding the solubility of N₂ from air in blood at a depth of 100 ft and a pressure of 4.0 atm.#
02

Determine the solubility of Nâ‚‚ using Henry's Law

According to Henry's Law, at a constant temperature, the concentration of a dissolved gas is directly proportional to its partial pressure in the gas phase. We can use this relationship to calculate the solubility of N₂ in the blood at 4.0 atm. The formula for Henry's Law is: \(C = k \times P\) Where C is the concentration of the dissolved gas, k is the Henry's Law constant, and P is the partial pressure of the gas. For this problem, the concentration of N₂ is already given as 0.015 g/L at 1.0 atm. We can use this to find the ratio of the concentration of N₂ at 4.0 atm. New concentration = 4.0 * 0.015 g/L ≈ 0.060 g/L Now we just need to calculate the new number of moles dissolved at 4.0 atm. Number of moles = 0.060 g / 28 g/mol ≈ \(2.14 \times 10^{-3}\) mol #c) Finding the amount of N₂ gas released into the bloodstream when a scuba diver suddenly surfaces from a depth of 100 ft.#
03

Determine the difference in the number of moles

Calculate the difference in the number of moles of N₂ between the initial atmospheric pressure of 1.0 atm and the pressure after the scuba diver surfaces, which is 4.0 atm. Difference in moles = moles at 4.0 atm - moles at 1.0 atm = \(2.14 \times 10^{-3}\) mol - \(5.36 \times 10^{-4}\) mol ≈ \(1.61 \times 10^{-3}\) mol
04

Convert the difference in moles to milliliters of Nâ‚‚ gas

To find the volume of N₂ gas released, we will use the Ideal Gas Law. For this problem, we can assume the temperature stays constant at body temperature (310 K). The Ideal Gas Law is given by: \(PV = nRT\) Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin. We are given the difference in moles of N₂ gas released (\(1.61 \times 10^{-3}\) mol), and we know the pressure at the surface is 1.0 atm. With this information, we can solve for the volume V. V = (nRT) / P = \((1.61 \times 10^{-3}\) mol * 0.0821 L atm/mol K * 310 K) / 1.0 atm = 0.041 L Since there are 1000 mL in 1 L, we can convert this volume to mL. V = 0.041 L * 1000 mL/L ≈ 41 mL So, when a scuba diver suddenly surfaces from a depth of 100 ft, approximately 41 mL of N₂ gas (in the form of tiny bubbles) is released into the bloodstream from each liter of blood.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility
Solubility refers to the ability of a substance to dissolve in a solvent. In the context of gases like nitrogen (\(\mathrm{N}_2\)) in liquids such as water or blood, solubility tells us how much of the gas can dissolve under given conditions.
One important factor affecting solubility is temperature. Generally, the solubility of gases decreases as the temperature increases. This means that, at higher temperatures, less gas can dissolve in a liquid.
Furthermore, pressure also plays a crucial role in the solubility of gases. According to Henry's Law, the concentration of a dissolved gas in a liquid is directly proportional to the partial pressure of that gas above the liquid.
  • Thus, when pressure increases, more gas dissolves into the liquid until a new equilibrium is reached.
  • Conversely, a decrease in pressure results in gas coming out of the solution, potentially creating bubbles, which is what happens when a scuba diver surfaces too quickly.
Therefore, understanding solubility is indispensable for applications in fields like medicine, where knowing how gases behave in blood is vital for safe diving practices and medical treatments.
In the exercise provided, nitrogen's solubility is measured as 0.015 g/L at body temperature and 1 atm, which is used as a baseline to explore how solubility changes with pressure when diving.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry and physics that describes the state of an ideal gas. This equation is written as:\[ PV = nRT \]where:
  • \(P\) is the pressure of the gas,
  • \(V\) is the volume,
  • \(n\) is the number of moles of the gas,
  • \(R\) is the universal gas constant (0.0821 L atm/mol K), and
  • \(T\) is the temperature in Kelvin.
The Ideal Gas Law helps us predict how a gas will behave under varying conditions of pressure, volume, and temperature.
While no real gas perfectly follows this law due to intermolecular forces and volume occupied by gas particles, it provides a very close approximation for many gases under a range of conditions.
In the context of the scuba diving scenario, the Ideal Gas Law helps calculate the volume of nitrogen gas released into the diver's bloodstream when surfacing. It takes into account changes in pressure and temperature that occur during the dive.
Partial Pressure
Partial pressure is the pressure exerted by a single type of gas in a mixture of gases. It is a crucial concept when discussing the behavior of gases dissolved in liquids, as seen with nitrogen in blood.
Each gas in a mixture exerts a pressure independently of other gases. This contributes to the total pressure of the gas mixture, an idea encapsulated in Dalton's Law of Partial Pressures.
  • In the air, nitrogen has a partial pressure because it makes up a certain percentage (about 78%) of the atmosphere.
  • Underwater, the total pressure increases due to the weight of the water above, thus increasing the partial pressures of each gas, including nitrogen.
This concept is important in diving, as it explains why more nitrogen dissolves in the blood at higher pressures experienced at \(100 \mathrm{ft}\) depths. Divers must manage this dissolved nitrogen to avoid decompression sickness, also known as "the bends," which occurs if nitrogen comes out of solution too rapidly as they return to the surface.
In solving the exercise, partial pressures are crucial for understanding how nitrogen's solubility changes with increased depth and pressure.
Molar Mass
Molar mass is the mass of one mole of a substance, usually expressed in grams per mole (g/mol). It is an essential concept for converting between mass and moles in chemical calculations.
  • For nitrogen gas (\(\mathrm{N}_2\)), its molar mass is 28 g/mol, as each molecule consists of two nitrogen atoms, each with an atomic mass of 14 g/mol.
Knowing the molar mass allows us to calculate how many moles are present in a given mass of nitrogen. This conversion is used in the textbook problem to determine the moles of nitrogen that dissolve in blood at different pressures.
The number of moles is crucial for using the Ideal Gas Law and Henry's Law, both of which depend on the mole quantity of the gas.
In problems involving gases in solution, molar mass serves as a bridge between mass and moles, helping us apply relevant gas laws to understand behavior, particularly when calculating solubility and responding to pressure changes in scenarios like scuba diving.
Overall, grasping molar mass is essential for making accurate predictions about gas behavior and solubility as demonstrated in the exercise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The presence of the radioactive gas radon (Rn) in well water presents a possible health hazard in parts of the United States. (a) Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at \(30^{\circ} \mathrm{C}\) is \(7.27 \times 10^{-3} \mathrm{M},\) what is the Henry's law constant for radon in water at this temperature? (b) A sample consisting of various gases contains \(3.5 \times 10^{-6}\) mole fraction of radon. This gas at a total pressure of 32 atm is shaken with water at \(30^{\circ} \mathrm{C} .\) Calculate the molar concentration of radon in the water.

You make a solution of a nonvolatile solute with a liquid solvent. Indicate if each of the following statements is true or false. (a) The freezing point of the solution is unchanged by addition of the solvent. (b) The solid that forms as the solution freezes is nearly pure solute. (c) The freezing point of the solution is independent of the concentration of the solute. ( \(\mathbf{d}\) ) The boiling point of the solution increases in proportion to the concentration of the solute. (e) At any temperature, the vapor pressure of the solvent over the solution is lower than what it would be for the pure solvent.

Seawater contains 34 g of salts for every liter of solution. Assuming that the solute consists entirely of \(\mathrm{NaCl}\) (in fact, over 90\(\%\) of the salt is indeed NaCl), calculate the osmotic pressure of seawater at \(20^{\circ} \mathrm{C}\) .

\(\mathrm{KBr}\) is relatively soluble in water, yet its enthalpy of solution is \(+19.8 \mathrm{kJ} / \mathrm{mol} .\) Which of the following statements provides the best explanation for this behavior? (a) Potassium salts are always soluble in water. (b) The entropy of mixing must be unfavorable. (c) The enthalpy of mixing must be small compared to the enthalpies for breaking up water-water interactions and K-Brionic interactions. (d) KBr has a high molar mass compared to other salts like NaCl.

Lauryl alcohol is obtained from coconut oil and is used to make detergents. A solution of 5.00 g of lauryl alcohol in 0.100 kg of benzene freezes at \(4.1^{\circ} \mathrm{C} .\) What is the molar mass of lauryl alcohol from this data?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.