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Hydrazine \(\left(\mathrm{H}_{2} \mathrm{NNH}_{2}\right),\) hydrogen peroxide \((\mathrm{HOOH}),\) and water \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) all have exceptionally high surface tensions compared with other substances of comparable molecular weights. (a) Draw the Lewis structures for these three compounds. (b) What structural property do these substances have in common, and how might that account for the high surface tensions?

Short Answer

Expert verified
The Lewis structures for hydrazine (Hâ‚‚NNHâ‚‚), hydrogen peroxide (HOOH), and water (Hâ‚‚O) are: Hydrazine: H | N - N | | H H Hydrogen peroxide: H - O - O - H Water: H | O - H All three molecules contain hydrogen bonding due to the presence of highly electronegative atoms (N or O) bonded to hydrogen. This strong intermolecular force leads to high surface tensions.

Step by step solution

01

Draw the Lewis Structure of Hydrazine

To draw the Lewis structure of hydrazine (Hâ‚‚NNHâ‚‚): 1. Calculate the total number of valence electrons: Nitrogen has 5 valence electrons, and Hydrogen has 1 valence electron. So, Hâ‚‚NNHâ‚‚ has (2 * 1) + (2 * 5) = 12 valence electrons. 2. Connect the central atoms (Nitrogens) with single bonds and arrange the remaining atoms. 3. Try distributing the electrons around the atoms to satisfy the octet rule for each atom. The Lewis structure for hydrazine (Hâ‚‚NNHâ‚‚) is: H | N - N | | H H
02

Draw the Lewis Structure of Hydrogen Peroxide

To draw the Lewis structure of hydrogen peroxide (HOOH): 1. Calculate the total number of valence electrons: Oxygen has 6 valence electrons, and Hydrogen has 1 valence electron. So, HOOH has (2 * 6) + (2 * 1) = 14 valence electrons. 2. Connect the central atoms (Oxygens) with single bonds and arrange the remaining atoms. 3. Try distributing the electrons around the atoms to satisfy the octet rule for each atom. The Lewis structure for hydrogen peroxide (HOOH) is: H - O - O - H
03

Draw the Lewis Structure of Water

To draw the Lewis structure of water (Hâ‚‚O): 1. Calculate the total number of valence electrons: Oxygen has 6 valence electrons, and Hydrogen has 1 valence electron. So, Hâ‚‚O has (1 * 6) + (2 * 1) = 8 valence electrons. 2. Arrange the atoms with Oxygen in the middle and Hydrogens around it. 3. Distribute the remaining electrons around the atoms to satisfy the octet rule for each atom. The Lewis structure for water (Hâ‚‚O) is: H | O - H
04

Identify the Structural Property and Explain High Surface Tensions

All three molecules (hydrazine, hydrogen peroxide, and water) contain hydrogen bonding, which is the common structural property. This is due to the presence of highly electronegative atoms (N or O) bonded to hydrogen. Hydrogen bonding is a strong intermolecular force that leads to high surface tensions. The stronger the intermolecular forces, the more energy required to break these interactions, and thus, higher surface tensions are present.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
Lewis structures are diagrams that represent the arrangement of atoms and electrons within a molecule. They are essential for understanding molecular geometry, bonding, and electron distribution.

When drawing a Lewis structure, start by identifying all the valence electrons involved. For each atom, determine the number of valence electrons, which are the electrons available for bonding. Hydrazine (NH2NH2), hydrogen peroxide (HOOH), and water (H2O) are examples where considering the valence electrons help shape their structures.

Steps for drawing a Lewis structure include: - Calculate the total number of valence electrons for the compound. - Arrange atoms with the least electronegative in the center (usually). - Connect atoms using single bonds first and distribute remaining electrons to satisfy the octet rule (8 electrons around each atom, except Hydrogen which needs 2). Understanding Lewis structures helps in predicting how atoms interact and the strength of the molecular bonds.
Surface Tension
Surface tension is a physical property that describes the amount of force needed to stretch or break the surface of a liquid. This occurs because of molecules being attracted to each other, a result of intermolecular forces. High surface tension means that molecules are holding tightly together.

In substances like water, hydrogen peroxide, and hydrazine, hydrogen bonds create strong intermolecular forces, which lead to increased surface tension.

Consider some main points: - Molecules at the surface experience a net inward force, trying to minimize surface area. - Hydrogen bonds are exceptionally strong intermolecular forces, significant in increasing surface tension. Understanding surface tension is crucial in many applications, such as why water forms droplets or why insects can walk on water.
Intermolecular Forces
Intermolecular forces are the attractions between molecules, essential in dictating the physical properties of substances like boiling and melting points. There are several types of intermolecular forces, but hydrogen bonding is particularly noteworthy.

Let's outline some key aspects: - **Hydrogen Bonding:** This occurs in molecules where hydrogen is directly bonded to either nitrogen, oxygen, or fluorine. It is notably strong due to the high electronegativity of these atoms, resulting in a strong dipole. - **Dipole-dipole Interactions:** These happen between two polar molecules, where parts of a molecule are charged due to uneven electron sharing. - **London Dispersion Forces (Van der Waals):** These are weak forces present in all molecules, arising due to temporary dipoles. Understanding these forces explains why hydrazine, hydrogen peroxide, and water have high surface tension. The presence of hydrogen bonding significantly raises the strength of these forces, demanding more energy to overcome them compared to other substances with similar weights.

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Most popular questions from this chapter

Suppose you have two colorless molecular liquids, one boiling at \(-84^{\circ} \mathrm{C},\) the other at \(34^{\circ} \mathrm{C},\) and both at atmospheric pressure. Which of the following statements is correct? For each statement that is not correct, modify the statement so that it is correct. (a) The higher-boiling liquid has greater total intermolecular forces than the lower- boiling liquid. (b) The lower-boiling liquid must consist of nonpolar molecules. (c) The lower- boiling liquid has a lower molecular weight than the higher-boiling liquid. (d) The two liquids have identical vapor pressures at their normal boiling points. (e) At \(-84^{\circ}\) both liquids have vapor pressures of 760 \(\mathrm{mm} \mathrm{Hg}\) .

Describe how a cholesteric liquid crystal phase differs from a nematic phase.

The boiling points, surface tensions, and viscosities of water and several alcohols are as shown below:(a) From ethanol to propanol to \(n\) -butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for this increase? (b) How do you explain the fact that propanol and ethylene glycol have similar molecular weights (60 versus 62 amu), yet the viscosity of ethylene glycol is more than 10 times larger than propanol? (c) How do you explain the fact that water has the highest surface tension but the lowest viscosity?

Butane and 2 -methylpropane, whose space-filling models are shown here, are both nonpolar and have the same molecular formula, \(\mathrm{C}_{4} \mathrm{H}_{10},\) yet butane has the higher boiling point \(\left(-0.5^{\circ} \mathrm{C}\) compared to \(-11.7^{\circ} \mathrm{C}\right) .\) Explain.

If 42.0 \(\mathrm{kJ}\) of heat is added to a \(32.0-\mathrm{g}\) sample of liquid methane under 1 \(\mathrm{atm}\) of pressure at a temperature of \(-170^{\circ} \mathrm{C}\) , what are the final state and temperature of the methane once the system equilibrates? Assume no heat is lost to the surroundings. The normal boiling point of methane is \(-161.5^{\circ} \mathrm{C}\) The specific heats of liquid and gaseous methane are 3.48 and \(2.22 \mathrm{J} / \mathrm{g}-\mathrm{K}\) , respectively. [ Section 11.4\(]\)

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