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Which member in each pair has the stronger intermolecular dispersion forces? (a) Br_ or \(\mathrm{O}_{2},\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH},(\mathbf{c}) \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Clor}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCl}\)

Short Answer

Expert verified
In summary, the molecules with stronger intermolecular dispersion forces for each pair are: (a) Br₂, (b) CH₃CH₂CH₂CH₂CH₂SH, and (c) CH₃CH₂CH₂Cl.

Step by step solution

01

Pair (a): Brâ‚‚ and Oâ‚‚

In this pair, we have Brâ‚‚ (Bromine) and Oâ‚‚ (Oxygen) molecules. Brâ‚‚ is a larger molecule with more electrons (70 electrons) compared to the Oâ‚‚ molecule (16 electrons). As the dispersion forces are dependent on the size of the molecule and the number of electrons, Bromine (Brâ‚‚) has stronger intermolecular dispersion forces than Oxygen (Oâ‚‚).
02

Pair (b): CH₃CH₂CH₂CH₂SH and CH₃CH₂CH₂CH₂CH₂SH

In this case, we are comparing two organic molecules: 1. CH₃CH₂CH₂CH₂SH (4 carbons and 1 sulfur atom) 2. CH₃CH₂CH₂CH₂CH₂SH (5 carbons and 1 sulfur atom) The first molecule has a total of 34 electrons, while the second molecule has 42 electrons. The second molecule, CH₃CH₂CH₂CH₂CH₂SH, has more electrons and is larger than the first molecule. Therefore, the second molecule has stronger intermolecular dispersion forces.
03

Pair (c): CH₃CH₂CH₂Cl and (CH₃)₂CHCl

In this pair, we have to compare: 1. CH₃CH₂CH₂Cl (3 carbons and 1 chlorine atom) 2. (CH₃)₂CHCl (3 carbons and 1 chlorine atom) Both molecules have the same number of atoms and electrons (26 electrons each). However, their structure differs. In the first molecule, the chlorine atom is attached to a carbon with two neighboring carbons, while in the second molecule, the chlorine atom is attached to a carbon with two methyl (CH₃) groups attached. The second molecule has a more branched structure, which can lead to weaker dispersion forces due to a reduced surface area. Therefore, CH₃CH₂CH₂Cl has slightly stronger intermolecular dispersion forces than (CH₃)₂CHCl.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Br2 vs O2 Molecules
When comparing bromine ( Brâ‚‚) and oxygen ( Oâ‚‚) molecules, it's crucial to understand the impact of electron count on intermolecular dispersion forces. Dispersion forces, also known as London dispersion forces, are a type of van der Waals force. These are the weakest intermolecular forces but significantly influence how molecules interact and how substances behave. Brâ‚‚ and Oâ‚‚ both exist as diatomic molecules but differ greatly in their electron count. Brâ‚‚, with its 70 electrons, is a much larger molecule electron-wise compared to Oâ‚‚, which has only 32 electrons in total. The greater the number of electrons, the more readily temporary dipoles can form, giving rise to stronger dispersion forces.
  • Brâ‚‚ - Large size, 70 electrons
  • Oâ‚‚ - Smaller size, 32 electrons
The large number of electrons in Brâ‚‚ results in greater moments of instantaneous polarization across the molecule. Consequently, Brâ‚‚ exhibits stronger intermolecular dispersion forces than Oâ‚‚.
Organic Molecule Comparison
When determining which organic molecules possess stronger dispersion forces, we often look at molecular size and the number of electrons. For example, in organic compounds like CH₃CH₂CH₂CH₂SH and CH₃CH₂CH₂CH₂CH₂SH, the difference in carbon chain length and electron count is crucial.
  • CH₃CHâ‚‚CHâ‚‚CHâ‚‚SH - 4 carbon atoms, 1 sulfur, 34 electrons
  • CH₃CHâ‚‚CHâ‚‚CHâ‚‚CHâ‚‚SH - 5 carbon atoms, 1 sulfur, 42 electrons
The presence of more electrons in the longer carbon chain of CH₃CH₂CH₂CH₂CH₂SH enhances the dispersion forces due to greater transient polarizability. Simply put, more electrons allow more significant temporary dipole interactions between molecules, thus leading to stronger dispersion forces. Hence, the molecule with the longer carbon chain, in this case, CH₃CH₂CH₂CH₂CH₂SH, demonstrates stronger dispersion forces.
Molecular Structure and Dispersion Forces
The structure of organic molecules directly affects their ability to interact via dispersion forces. Consider the comparison between CH₃CH₂CH₂Cl and (CH₃)₂CHCl. These molecules possess the same number of electrons but differ structurally, influencing their intermolecular interactions.
  • CH₃CHâ‚‚CHâ‚‚Cl - Straight chain structure
  • (CH₃)â‚‚CHCl - Branched structure
The linearity or branching of a molecule affects its surface area and, therefore, the strength of its dispersion forces. Molecules with a straight chain configuration, like CH₃CH₂CH₂Cl, have a greater surface area. This allows for closer contact and interaction between molecules, resulting in stronger dispersion forces. On the other hand, branched molecules like (CH₃)₂CHCl, have a smaller contact area, reducing the efficiency of dispersion interactions. Therefore, despite having the same electron count, CH₃CH₂CH₂Cl exhibits slightly stronger intermolecular dispersion forces due to its more extended structure.

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Most popular questions from this chapter

Which member in each pair has the greater dispersion forces? (a) \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{H}_{2} \mathrm{S},(\mathbf{b}) \mathrm{CO}_{2}\) or \(\mathrm{CO},(\mathbf{c}) \operatorname{siH}_{4}\) or \(\mathrm{GeH}_{4}\) .

If 42.0 \(\mathrm{kJ}\) of heat is added to a \(32.0-\mathrm{g}\) sample of liquid methane under 1 \(\mathrm{atm}\) of pressure at a temperature of \(-170^{\circ} \mathrm{C}\) , what are the final state and temperature of the methane once the system equilibrates? Assume no heat is lost to the surroundings. The normal boiling point of methane is \(-161.5^{\circ} \mathrm{C}\) The specific heats of liquid and gaseous methane are 3.48 and \(2.22 \mathrm{J} / \mathrm{g}-\mathrm{K}\) , respectively. [ Section 11.4\(]\)

You are high up in the mountains and boil water to make some tea. However, when you drink your tea, it is not as hot as it should be. You try again and again, but the water is just not hot enough to make a hot cup of tea. Which is the best explanation for this result? (a) High in the mountains, it is probably very dry, and so the water is rapidly evaporating from your cup and cooling it. (b) High in the mountains, it is probably very windy, and so the water is rapidly evaporating from your cup and cooling it. (c) High in the mountains, the air pressure is significantly less than 1 atm, so the boiling point of water is much lower than at sea level. (d) High in the mountains, the air pressure is significantly less than 1 atm, so the boiling point of water is much higher than at sea level.

Which type of intermolecular force accounts for each of these differences? (a) \(\mathrm{CH}_{3} \mathrm{OH}\) boils at \(65^{\circ} \mathrm{C} ; \mathrm{CH}_{3} \mathrm{SH}\) boils at \(6^{\circ} \mathrm{C} .(\mathbf{b}) \mathrm{Xe}\) is a liquid at atmospheric pressure and \(120 \mathrm{K},\)whereas Ar is a gas under the same conditions. (c) Kr, atomic weight 84 amu, boils at \(120.9 \mathrm{K},\) whereas \(\mathrm{Cl}_{2},\) molecular weight about 71 amu, boils at 238 \(\mathrm{K}\) . (d) Acetone boils at \(56^{\circ} \mathrm{C},\) whereas 2 -methylpropane boils at \(-12^{\circ} \mathrm{C}\) .

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