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(a) What is the difference between a localized \(\pi\) bond and a delocalized one? (b) How can you determine whether a molecule or ion will exhibit delocalized \(\pi\) bonding? (c) Is the \(\pi\) bond in \(\mathrm{NO}_{2}{ }^{-}\)localized or delocalized?

Short Answer

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(a) A localized π bond has electrons confined between two atoms, while a delocalized π bond has electrons spread across more than two atoms, often in resonance structures. (b) To determine delocalized π bonding, look for resonance structures where lone pairs, π bonds, or positive charges are distributed among multiple atoms. (c) The π bond in NO2- is delocalized due to its resonance structures involving delocalized electron distribution.

Step by step solution

01

(Step 1: Understanding Localized and Delocalized π Bonds)

In a localized π bond, the electrons are confined between two atoms, like in a typical carbon-carbon double bond. However, in a delocalized π bond, the electrons are spread across more than two atoms, which often happens in resonance structures.
02

(Step 2: Determining if a molecule or ion exhibits delocalized π bonding)

To determine if a molecule or ion exhibits delocalized π bonding, look for resonance structures where lone pairs, π bonds, or positive charges can be distributed among multiple atoms in the molecule.
03

(Step 3: Analyzing the NO2- ion)

The NO2- ion has the chemical structure: O=N-O with one lone pair on the negatively charged O atom. There are resonance structures for this ion, where the lone pair on the O atom can form a π bond with the N atom, creating a double bond, and the initial double bond between N and the second O atom becomes a single bond.
04

(Step 4: Determining if the π bond in NO2- ion is localized or delocalized)

Since the NO2- ion has resonance structures where the π bond is involved in the delocalized electron distribution, the π bond in the NO2- ion is considered delocalized.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Localized π Bond
If you've ever seen molecules with double or triple bonds, you're already familiar with π (pi) bonds. These bonds form when parallel orbitals overlap and share electrons. In a localized π bond, the electrons are shared directly between just two atoms. Think of it as a specific 'address' for electrons; they're only hanging out there. This is the standard in many organic compounds where double bonds don't interact with each other or with lone electron pairs.

A prime example is ethylene (C2H4), where a localized π bond exists between the two carbon atoms, with no ability for those electrons to wander off to neighboring atoms.
Resonance Structures
Imagine if electrons could have multiple homes, shifting between them like a family with vacation homes. That's what happens in resonance structures. For molecules that have this property, we can draw different structures, called resonance forms, to show different ways electrons are distributed. These are like snapshots of all the possible places where the electrons could be at any moment in time.

It's essential to realize that electrons don't actually flip back and forth between these structures. Instead, the true form of the molecule is a hybrid, a blend of all the possible resonance forms. A famous case is benzene, where electrons in π bonds are delocalized over six carbon atoms instead of being localized between two.
Electron Distribution
The way electrons are spread out in a molecule can tell us a lot about its reactivity and properties. Electron distribution is about understanding where in a molecule electrons prefer to spend their time. In molecules with localized π bonds, the electron distribution is predictable and tied to specific atom pairs. However, when π bonds are delocalized, electron distribution becomes more spread out among several atoms.

This distribution affects the molecule's color, reactivity, and even stability. Delocalized electrons can lower a molecule's energy, making it more stable, as they roam and enjoy the space in their molecular 'neighborhood'. Analyzing electron distribution is key in predicting how a molecule will interact with others and how it behaves under different conditions.
Chemical Bonding
At the heart of chemistry lies chemical bonding, the force that holds atoms together in molecules. There are several types of chemical bonds - ionic, covalent, metallic, and more. π bonds are a type of covalent bond formed by the side-by-side overlap of atomic orbitals. Understanding the different types of chemical bonds and how they form is fundamental to grasping how atoms combine to make molecules with various shapes and functions.

Everything from the water we drink to the medicines we take relies on chemical bonding. Whether bonds are localized, contributing to a molecule's rigid structure, or delocalized, providing flexibility and stability, they are crucial in determining the properties and behavior of the substances around us.

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Most popular questions from this chapter

What are the electron-domain and molecular geometries of a molecule that has the following electron domains on its central atom? (a) Three bonding domains and no nonbonding domains, (b) three bonding domains and one nonbonding domain, (c) two bonding domains and two nonbonding domains.

The Lewis structure for allene is Make a sketch of the structure of this molecule that is analogous to Figure 9.25. In addition, answer the following three questions: (a) Is the molecule planar? (b) Does it have a nonzero dipole moment? (c) Would the bonding in allene be described as delocalized? Explain.

Draw the Lewis structure for each of the following molecules or ions, and predict their electron-domain and molecular geometries: (a) \(\mathrm{AsF}_{3}\), (b) \(\mathrm{CH}_{3}^{+}\), (c) \(\mathrm{BrF}_{3}\), (d) \(\mathrm{ClO}_{3}^{-}\), (e) \(\mathrm{XeF}_{2}\), (f) \(\mathrm{BrO}_{2}^{-}\).

The \(\mathrm{O}-\mathrm{H}\) bond lengths in the water molecule \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) are \(0.96 \AA\), and the \(\mathrm{H}-\mathrm{O}-\mathrm{H}\) angle is \(104.5^{\circ}\). The dipole moment of the water molecule is \(1.85\) D. (a) In what directions do the bond dipoles of the \(\mathrm{O}-\mathrm{H}\) bonds point? In what direction does the dipole moment vector of the water molecule point? (b) Calculate the magnitude of the bond dipole of the \(\mathrm{O}-\mathrm{H}\) bonds. (Note: You will need to use vector addition to do this.) (c) Compare your answer from part (b) to the dipole moments of the hydrogen halides (Table 8.3). Is your answer in accord with the relative electronegativity of oxygen?

In which of these molecules or ions does the presence of nonbonding electron pairs produce an effect on molecular shape? (a) \(\mathrm{SiH}_{4}\), (b) \(\mathrm{PF}_{3}\), (c) \(\mathrm{HBr}\), (d) \(\mathrm{HCN}\), (e) \(\mathrm{SO}_{2}\).

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