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Fill in the blank with the appropriate numbers for both electrons and bonds (considering that single bonds are counted as one, double bonds as two, and triple bonds as three). (a) Fluorine has valence electrons and makes bond(s) in compounds. (b) Oxygen has valence electrons and makes bond(s) in compounds. (c) Nitrogen has valence electrons and makes bond(s) in compounds. (d) Carbon has valence electrons and makes bond \((s)\) in compounds.

Short Answer

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(a) Fluorine has 7 valence electrons and makes 1 bond in compounds. (b) Oxygen has 6 valence electrons and makes 2 bonds in compounds. (c) Nitrogen has 5 valence electrons and makes 3 bonds in compounds. (d) Carbon has 4 valence electrons and makes 4 bonds in compounds.

Step by step solution

01

(a) Fluorine

: Fluorine is in group 17 of the periodic table and has 7 valence electrons. It needs 1 additional electron to fulfil the octet rule completely. Therefore, it forms one single bond in compounds. (a) Fluorine has 7 valence electrons and makes 1 bond in compounds.
02

(b) Oxygen

: Oxygen is in group 16 of the periodic table and has 6 valence electrons. It needs 2 additional electrons to fulfil the octet rule completely. Therefore, it forms two single bonds or one double bond in compounds. (b) Oxygen has 6 valence electrons and makes 2 bonds in compounds.
03

(c) Nitrogen

: Nitrogen is in group 15 of the periodic table and has 5 valence electrons. It needs 3 additional electrons to fulfil the octet rule completely. Therefore, it forms three single bonds, one single bond and one double bond, or one triple bond in compounds. (c) Nitrogen has 5 valence electrons and makes 3 bonds in compounds.
04

(d) Carbon

: Carbon is in group 14 of the periodic table and has 4 valence electrons. It needs 4 additional electrons to fulfil the octet rule completely. Therefore, it forms four single bonds, two single bonds and one double bond, or two double bonds in compounds. (d) Carbon has 4 valence electrons and makes 4 bonds in compounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octet Rule
The Octet Rule is a fundamental principle in chemistry that helps us understand how atoms form chemical bonds. According to this rule, atoms tend to form bonds in a way that they end up with eight valence electrons. Having a full outer shell of electrons makes them more stable and less reactive. The Octet Rule mainly applies to main-group elements, especially those in the second row of the periodic table, such as carbon, nitrogen, oxygen, and fluorine. Atoms can achieve a full octet through several types of bonds:
  • By gaining electrons, like non-metals do, to become more like noble gases.
  • By losing electrons, like metals do, to attain a noble gas structure.
  • By sharing electrons with other atoms, forming covalent bonds.
Understanding the Octet Rule is vital when predicting the types and number of bonds an atom can form in a molecule. For instance, carbon with four valence electrons forms four bonds to achieve an octet.
Chemical Bonds
Chemical bonds are the forces holding atoms together in molecules. These bonds form when atoms share or transfer valence electrons in order to achieve stability, often through the Octet Rule. There are several primary types of chemical bonds:
  • Covalent Bonds: These occur when two atoms share one or more pairs of valence electrons. Types include single, double, and triple bonds. For example: Oxygen forms a double bond in Oâ‚‚ molecules.
  • Ionic Bonds: Formed when one atom transfers electrons to another, typically between metals and non-metals, resulting in attracted charged ions.
  • Metallic Bonds: These are formed between metal atoms when they share a "sea" of electrons that provides structural cohesion.
Each bond type has distinct properties and plays a different role in the structure of compounds. Understanding how atoms bond is crucial for predicting molecular shapes, reactivity, and properties.
Periodic Table Groups
The Periodic Table is structured into groups that help predict the behavior of elements, including their valence electron count and bonding patterns. Groups, or families, are vertical columns in the table and are numbered from 1 to 18. Elements in the same group have similar chemical properties because they have the same number of valence electrons. This repetitive pattern, known as periodicity, is fundamental for understanding chemical reactions:
  • Group 1 (Alkali Metals): These have 1 valence electron, making them highly reactive and eager to lose this electron to achieve an octet.
  • Group 17 (Halogens): With 7 valence electrons, these elements need just one more electron to complete their octet and often form single covalent bonds.
  • Group 18 (Noble Gases): Known for having a full set of valence electrons, making them generally unreactive, a term often called "inert."
Understanding the periodic table groups aids in predicting how different elements will interact in experiments and helps in forming chemical compounds.

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Most popular questions from this chapter

Energy is required to remove two electrons from Ca to form \(\mathrm{Ca}^{2+}\), and energy is required to add two electrons to \(\mathrm{O}\) to form \(\mathrm{O}^{2-}\). Yet \(\mathrm{CaO}\) is stable relative to the free elements. Which statement is the best explanation? (a) The lattice energy of \(\mathrm{CaO}\) is large enough to overcome these processes. (b) \(\mathrm{CaO}\) is a covalent compound, and these processes are irrelevant. (c) CaO has a higher molar mass than either Ca or \(\mathrm{O}\). (d) The enthalpy of formation of \(\mathrm{CaO}\) is small. (e) \(\mathrm{CaO}\) is stable to atmospheric conditions.

(a) Describe the molecule xenon trioxide, \(\mathrm{XeO}_{3}\), using four possible Lewis structures, one each with zero, one, two, or three Xe-O double bonds. (b) Do any of these resonance structures satisfy the octet rule for every atom in the molecule? (c) Do any of the four Lewis structures have multiple resonance structures? If so, how many resonance structures do you find? (d) Which of the Lewis structures in (a) yields the most favorable formal charges for the molecule?

Which of the following bonds are polar? (a) B-F, (b) \(\mathrm{Cl}-\mathrm{Cl}\), (c) Se-O, (d) H-I. Which is the more electronegative atom in each polar bond?

Illustrated are four ions - \(A, B, X\), and \(Y-\) showing their relative ionic radii. The ions shown in red carry positive charges: a \(2+\) charge for A and a \(1+\) charge for B. Ions shown in blue carry negative charges: a \(1-\) charge for \(X\) and a \(2-\) charge for \(Y\). (a) Which combinations of these ions produce ionic compounds where there is a \(1: 1\) ratio of cations and anions? (b) Among the combinations in part (a), which leads to the ionic compound having the largest lattice energy? [Section 8.2]

For each of these Lewis symbols, indicate the group in the periodic table in which the element \(X\) belongs: [Section 8.1] (a) \(\dot{X}\) (b) \(\mathrm{X}\) (c) \(\dot{X} \cdot\)

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