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Use Lewis symbols and Lewis structures to diagram the formation of \(\mathrm{PF}_{3}\) from \(\mathrm{P}\) and \(\mathrm{F}\) atoms, showing valence- shell electrons. (a) How many valence electrons does \(P\) have initially? (b) How many valence electrons does each \(F\) have initially? (c) How many valence electrons surround the \(\mathrm{P}\) in the \(\mathrm{PF}_{3}\) molecule? (d) How many valence electrons surround each \(\mathrm{F}\) in the \(\mathrm{PF}_{3}\) molecule? (e) How many bonding pairs of electrons are in the \(\mathrm{PF}_{3}\) molecule?

Short Answer

Expert verified
In the formation of the PF3 molecule, phosphorus (P) initially has 5 valence electrons, while each fluorine (F) atom initially has 7 valence electrons. The P atom in the PF3 molecule is surrounded by 8 valence electrons in its valence shell, and each F atom is surrounded by 8 valence electrons in their valence shell. There are 3 bonding pairs of electrons in the PF3 molecule, one for each P-F bond.

Step by step solution

01

Find the initial valence electrons of P and F atoms

To determine the valence electrons of P and F, we can refer to the periodic table. Phosphorus (P) is in group 15, which means it has 5 valence electrons. Fluorine (F) is in group 17, which means it has 7 valence electrons. (a) Phosphorus (P) initially has 5 valence electrons. (b) Each fluorine (F) atom initially has 7 valence electrons.
02

Represent the atoms in PF3 molecule

In the PF3 molecule, one P atom is bonded to three F atoms. We can represent this as P surrounded by three F atoms: P - F - F - F
03

Arrange the electrons around the P and F atoms

For the P atom, we can use 3 of its 5 valence electrons to form covalent bonds with each of the F atoms. Its final electron pair will be placed on the unoccupied side. F | P - F - F | F For each F atom, one of its 7 valence electrons will be used to form a covalent bond with P while the remaining 6 valence electrons will be placed around F as 3 lone pairs. (c) The P atom in the PF3 molecule is surrounded by 3 single bonds and 1 lone pair of electrons, totaling 8 valence electrons in its valence shell. (d) Each F atom in the PF3 molecule is surrounded by 1 single bond and 3 lone pairs of electrons, totaling 8 valence electrons in their valence shell.
04

Determine the number of bonding pairs of electrons

In PF3, there is one P atom bonded to three F atoms. Each P-F bond is a single bond, which means there is one electron pair involved in each bond. (e) There are 3 bonding pairs of electrons in the PF3 molecule, one for each P-F bond.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the electrons that reside in the outermost shell of an atom; they play a crucial role in chemical bonding and properties. Each element has a characteristic number of valence electrons that can be predicted based on its position in the periodic table. For example, in the case of the \(\mathrm{PF}_{3}\) molecule, phosphorus (P), being in group 15, has five valence electrons, while fluorine (F), in group 17, has seven valence electrons. These valence electrons are responsible for the formation of covalent bonds.

When drawing Lewis structures, it is essential to account for these valence electrons accurately, as they will dictate how atoms bond and interact with each other. They are represented as dots around the element symbol, clearly showing which electrons are available for bonding.
Covalent Bonding
Covalent bonding is a type of chemical bond where atoms share pairs of valence electrons to achieve a more stable electron configuration, often resulting in the fulfillment of the octet rule. In a \(\mathrm{PF}_{3}\) molecule, each fluorine atom needs one more electron to complete its octet, while phosphorus needs three to fill its outer shell.

This sharing of electron pairs leads to the formation of covalent bonds, with the number of shared electrons being depicted as lines between the bonded atoms in Lewis structures. For \(\mathrm{PF}_{3}\), there are three covalent bonds formed between the P atom and each of the F atoms, where electrons are being shared.
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule, which is influenced by the number of electron pairs, both bonding and nonbonding (lone pairs), around the central atom. The \(\mathrm{PF}_{3}\) molecule has a trigonal pyramidal geometry due to the three bonding pairs and one lone pair on the central P atom.

The presence of this lone pair creates a repulsion that slightly distorts the idealized geometry, leading to \(\mathrm{PF}_{3}\) not being perfectly triangular but rather pyramidal. Understanding molecular geometry is crucial as it affects the physical and chemical properties of the compound, including reactivity, polarity, and interactions with other molecules.
Lewis Symbols
Lewis symbols, also known as electron dot symbols, are diagrams that represent the valence electrons of an atom as dots around the symbol of the element. These symbols serve as a simplified way to visualize the electrons available for bonding, and they form a foundation for creating more complex Lewis structures for molecules.

For individual atoms, Lewis symbols show the placement of electrons in pairs or as singles, revealing potential sites for bonding. In a \(\mathrm{PF}_{3}\) molecule, Lewis symbols would initially depict P with five dots representing its valence electrons and F with seven dots each. During the formation of the molecule, these dots are rearranged to reflect shared electron pairs, or bonds, and unshared electrons, or lone pairs.

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Most popular questions from this chapter

Write Lewis structures that obey the octet rule for each of the following, and assign oxidation numbers and formal charges to each atom: (a) \(\mathrm{OCS}\), (b) \(\mathrm{SOCl}_{2}\) ( \(\mathrm{S}\) is the central atom), (c) \(\mathrm{BrO}_{3}^{-}\), (d) \(\mathrm{HClO}_{2}\) (H is bonded to \(\left.\mathrm{O}\right)\).

Which of the following bonds are polar? (a) B-F, (b) \(\mathrm{Cl}-\mathrm{Cl}\), (c) Se-O, (d) H-I. Which is the more electronegative atom in each polar bond?

(a) Consider the lattice energies for the following compounds: \(\mathrm{BeH}_{2}, 3205 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{MgH}_{2}, 2791 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{CaH}_{2}, 2410 \mathrm{~kJ} / \mathrm{mol} ;\) \(\mathrm{SrH}_{2}, 2250 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{BaH}_{2}, 2121 \mathrm{~kJ} / \mathrm{mol}\). Plot lattice energy versus cation radius for these compounds. If you draw a line through your points, is the slope negative or positive? Explain. (b) The lattice energy of \(\mathrm{ZnH}_{2}\) is \(2870 \mathrm{~kJ} / \mathrm{mol}\). Based on the data given in part (a), the radius of the \(\mathrm{Zn}^{2+}\) ion is expected to be closest to that of which group \(2 \mathrm{~A}\) element?

Write the electron configuration for each of the following ions, and determine which ones possess noble-gas configurations: (a) \(\mathrm{Sr}^{2+}\), (b) \(\mathrm{Ti}^{2+}\), (c) \(\mathrm{Se}^{2-}\), (d) \(\mathrm{Ni}^{2+}\), (e) \(\mathrm{Br}^{-}\), (f) \(\mathrm{Mn}^{3+}\).

Draw the dominant Lewis structures for these chlorine-oxygen molecules/ions: \(\mathrm{ClO}, \mathrm{ClO}^{-}, \mathrm{ClO}_{2}^{-}, \mathrm{ClO}_{3}^{-}, \mathrm{ClO}_{4}^{-} .\)Which of these do not obey the octet rule?

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