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Write electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Cd}^{2+}\), (b) \(\mathrm{P}^{3-}\), (c) \(\mathrm{Zr}^{4+}\), (d) \(\mathrm{Ru}^{3+}\), (e) \(\mathrm{As}^{3-}\), (f) \(\mathrm{Ag}^{+}\).

Short Answer

Expert verified
The ions with noble-gas configurations are: (a) \(\mathrm{Cd}^{2+}\): [Kr]4d鹿鈦 (b) \(\mathrm{P}^{3-}\): [Ne] (c) \(\mathrm{Zr}^{4+}\): [Kr]4d虏 (e) \(\mathrm{As}^{3-}\): [Kr] (f) \(\mathrm{Ag}^{+}\): [Kr]4d鹿鈦

Step by step solution

01

Identify Atomic Number and Number of Electrons in Each Ion

First, we must find the atomic number of each given element from the periodic table and calculate the number of electrons for each ion based on their charge: (a) Cadmium (Cd), Atomic Number = 48, Electrons in Cd2+ ion = 48 - 2 = 46 (b) Phosphorus (P), Atomic Number = 15, Electrons in P3- ion = 15 + 3 =18 (c) Zirconium (Zr), Atomic Number = 40, Electrons in Zr4+ ion = 40 - 4 = 36 (d) Ruthenium (Ru), Atomic Number = 44, Electrons in Ru3+ ion = 44 - 3 = 41 (e) Arsenic (As), Atomic Number = 33, Electrons in As3- ion = 33 + 3 = 36 (f) Silver (Ag), Atomic Number = 47, Electrons in Ag+ ion = 47 - 1 = 46
02

Write Electron Configurations Using the Aufbau Principle

Using the Aufbau Principle, we will write electron configurations for each ion: (a) Cd2+: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 (b) P3-: 1s虏 2s虏 2p鈦 3s虏 3p鈦 (c) Zr4+: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d虏 (d) Ru3+: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s鹿 4d鈦 (e) As3-: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 (f) Ag+: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s鹿 4d鹿鈦
03

Compare with Electron Configurations of Noble Gases

Finally, let's compare the electron configurations of each ion with the electron configurations of noble gases to determine which ions have noble-gas configurations: (a) Cd2+: [Kr]4d鹿鈦 (Kr stands for Krypton, a noble gas) (b) P3-: [Ne] (c) Zr4+: [Kr]4d虏 (d) Ru3+: Does not match any noble gas electron configuration (e) As3-: [Kr] (f) Ag+: [Kr]4d鹿鈦
04

Conclusion

The ions with noble-gas configurations are: (a) \(\mathrm{Cd}^{2+}\) (b) \(\mathrm{P}^{3-}\) (c) \(\mathrm{Zr}^{4+}\) (e) \(\mathrm{As}^{3-}\) (f) \(\mathrm{Ag}^{+}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Ions
When discussing atoms, ions are a fundamental concept. An ion is simply an atom that has lost or gained electrons, which results in a net charge. There are two types of ions: cations and anions. Cations are positively charged ions that form when an atom loses one or more electrons. For instance,
  • Cadmium ion Cd\(^{2+}\) results when Cadmium loses two electrons.
  • Silver ion Ag\(^{+}\) is formed by losing one electron.
Anions, on the other hand, are negatively charged ions formed when an atom gains electrons. Examples include:
  • Phosphorus ion P\(^{3-}\), which gains three electrons.
  • Arsenic ion As\(^{3-}\), also gaining three electrons.
Understanding how atoms become ions is crucial, as it helps explain their electronic configurations and reactions. By calculating the difference between the protons and electrons, we determine the ionic charge of each atom.
Noble-Gas Configurations
Noble-gas configurations refer to the electron configuration that corresponds to that of a noble gas. Noble gases are elements in Group 18 of the periodic table, well known for their stability. This stability arises because their outermost electron shell is full. Atoms frequently gain, lose, or share electrons in chemical reactions to achieve this same stability.
  • For example, Cd\(^{2+}\) with its electron configuration \([Kr] 4d^{10}\) matches that of Krypton, a noble gas.
  • Similarly, P\(^{3-}\) has the configuration of Neon, \([Ne]\).
  • Conversely, Ru\(^{3+}\) does not achieve any noble-gas configuration, indicating it doesn't achieve the same stable electron shell.
When an ion matches the electron configuration of a noble gas, it achieves lower energy and increased stability. This is why such configurations are often the 'goal' of ion formation in atoms.
Exploring the Periodic Table
The periodic table is a powerful tool that organizes all known elements based on their atomic number, electron configurations, and recurring chemical properties.
  • The elements are arranged into periods (rows) and groups (columns).
  • The recurring pattern of electron configurations shapes the layout of the table.
  • Noble gases located in Group 18 play a crucial role in understanding the stability of electron configurations.
To write electron configurations, like those of ions in the exercise, we refer to this table, following the order set by the Aufbau principle. This principle dictates how electrons populate atomic orbitals, sequentially filling lower energy levels before moving to higher ones. Electrons fill orbitals in a specific order, typically observed as:
  • 1s, 2s, 2p,
  • 3s, 3p, 4s, 3d, 4p,
  • 5s, 4d, 5p, etc.
By understanding the periodic table, one can predict the electron configurations of ions and whether they will share configurations with noble gases. This insight allows chemists to foresee the reactivity and bonding habits of various elements.

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Most popular questions from this chapter

Using Lewis symbols and Lewis structures, diagram the formation of \(\mathrm{SiCl}_{4}\) from \(\mathrm{Si}\) and \(\mathrm{Cl}\) atoms, showing valence-shell electrons. (a) How many valence electrons does \(\mathrm{Si}\) have initially? (b) How many valence electrons does each \(\mathrm{Cl}\) have initially? (c) How many valence electrons surround the Si in the \(\mathrm{SiCl}_{4}\) molecule? (d) How many valence electrons surround each \(\mathrm{Cl}\) in the \(\mathrm{SiCl}_{4}\) molecule? (e) How many bonding pairs of electrons are in the \(\mathrm{SiCl}_{4}\) molecule?

(a) True or false: An element's number of valence electrons is the same as its atomic number. (b) How many valence electrons does a nitrogen atom possess? (c) An atom has the electron configuration \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}\). How many valence electrons does the atom have?

An ionic substance of formula MX has a lattice energy of \(6 \times 10^{3} \mathrm{~kJ} / \mathrm{mol}\). Is the charge on the ion M likely to be \(1+, 2+\), or \(3+\) ? Explain.

(a) Determine the formal charge on the chlorine atom in the hypochlorite ion, \(\mathrm{ClO}^{-}\), and the perchlorate ion, \(\mathrm{ClO}_{4}^{-}\), using resonance structures where the \(\mathrm{Cl}\) atom has an octet. (b) What are the oxidation numbers of chlorine in \(\mathrm{ClO}^{-}\)and in \(\mathrm{ClO}_{4}^{-}\)? (c) Perchlorate is a much stronger oxidizing agent than hypochlorite. Suggest an explanation.

By referring only to the periodic table, select (a) the most electronegative element in group \(6 A ;(b)\) the least electronegative element in the group \(\mathrm{Al}, \mathrm{Si}, \mathrm{P}\); (c) the most electronegative element in the group Ga, \(\mathrm{P}, \mathrm{Cl}, \mathrm{Na}\) (d) the element in the group \(\mathrm{K}, \mathrm{C}, \mathrm{Zn}, \mathrm{F}\) that is most likely to form an ionic compound with Ba.

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