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If the electron affinity for an element is a negative number, does it mean that the anion of the element is more stable than the neutral atom? Explain.

Short Answer

Expert verified
Yes, if the electron affinity for an element is a negative number, it means that the anion of the element is more stable than the neutral atom. This is because a negative electron affinity value indicates that energy is released during the formation of the anion, which corresponds to the stabilization of the anionic species.

Step by step solution

01

Understand electron affinity

Electron affinity is the energy change that occurs when an electron is added to a neutral atom to form a negative ion. In other words, it's the amount of energy released (exothermic process) or absorbed (endothermic process) when an electron is added to an atom. Electron affinity is usually expressed in units of kJ/mol.
02

Identify the meaning of negative electron affinity

When an element has a negative electron affinity, it means that energy is released when an electron is added to the neutral atom, making the process exothermic. A negative electron affinity indicates that the negatively charged ion (anion) formed after the addition of an electron is more stable than the neutral atom because it involves a release of energy, which is associated with the formation of more stable species.
03

Explain the relationship between electron affinity and anion stability

An anion is more stable than the neutral atom if its formation is accompanied by the release of energy, resulting in a negative electron affinity value for the element. This is because the electron being added to the atom can stabilize the anion by lowering its overall energy, and this stabilization is achieved through the release of energy (which corresponds to a negative electron affinity value). In conclusion, if an element has a negative electron affinity, it means that the anion of the element is indeed more stable than the neutral atom. The negative electron affinity value indicates that energy is released during the formation of the anion, and this energy release is associated with the stabilization of the anionic species.

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Most popular questions from this chapter

(a) Why is calcium generally more reactive than magnesium? (b) Why is calcium generally less reactive than potassium?

Mercury in the environment can exist in oxidation states \(0,+1\), and \(+2\). One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111), but instead of using ultraviolet light to eject valence electrons, \(\mathrm{X}\) rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury's \(4 f\) orbitals at \(105 \mathrm{eV}\), from an X-ray source that provided \(1253.6 \mathrm{eV}\) of energy. The oxygen on the mineral surface gave emitted electron energies at \(531 \mathrm{eV}\), corresponding to the \(1 s\) orbital of oxygen. Overall the researchers concluded that oxidation states were \(+2\) for \(\mathrm{Hg}\) and \(-2\) for \(\mathrm{O}\). (a) Calculate the wavelength of the \(\mathrm{X}\) rays used in this experiment. (b) Compare the energies of the \(4 f\) electrons in mercury and the \(1 s\) electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground-state electron configurations for \(\mathrm{Hg}^{2+}\) and \(\mathrm{O}^{2-}\); which electrons are the valence electrons in each case? (d) Use Slater's rules to estimate \(Z_{\text {eff }}\) for the \(4 f\) and valence electrons of \(\mathrm{Hg}^{2+}\) and \(\mathrm{O}^{2-}\); assume for this purpose that all the inner electrons with \((n-3)\) or less screen a full \(+1\).

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Discussing this chapter, a classmate says, "An element that commonly forms a cation is a metal." Do you agree or disagree? Explain your answer.

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