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Write the electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Co}^{2+}\), (b) \(\mathrm{Sn}^{2+}\), (c) \(\mathrm{Zr}^{4+}\), (d) \(\mathrm{Ag}^{+}\), (e) \(\mathrm{S}^{2-}\).

Short Answer

Expert verified
The electron configurations for the given ions are: a) \(\mathrm{Co}^{2+}\): [Ar]3d鈦 b) \(\mathrm{Sn}^{2+}\): [Kr]4d鹿0 c) \(\mathrm{Zr}^{4+}\): [Kr] d) \(\mathrm{Ag}^{+}\): [Kr]4d鹿0 e) \(\mathrm{S}^{2-}\): [Ne]3s虏3p鈦 = [Ar] The ions with noble-gas configurations are \(\mathrm{Zr}^{4+}\) and \(\mathrm{S}^{2-}\).

Step by step solution

01

Write down the ground-state electron configurations for each atom.

First, we need to know the electron configurations of the neutral atoms. The configuration can be found from the periodic table. a) Co (Cobalt, atomic number 27): [Ar]4s虏3d鈦 b) Sn (Tin, atomic number 50): [Kr]5s虏4d鹿0 c) Zr (Zirconium, atomic number 40): [Kr]5s虏4d虏 d) Ag (Silver, atomic number 47): [Kr]5s鹿4d鹿0 e) S (Sulfur, atomic number 16): [Ne]3s虏3p鈦
02

Determine the electron configurations for the ions.

Now that we have the neutral atom configurations, we can remove or add electrons according to the ion charge. a) \(\mathrm{Co}^{2+}\): Remove 2 electrons, prioritize the 4s shell: [Ar]4s鈦3d鈦 = [Ar]3d鈦 b) \(\mathrm{Sn}^{2+}\): Remove 2 electrons, prioritize the 5s shell: [Kr]5s鈦4d鹿0 = [Kr]4d鹿0 c) \(\mathrm{Zr}^{4+}\): Remove 4 electrons, prioritize the 5s and 4d shells: [Kr]5s鈦4d鈦 = [Kr] d) \(\mathrm{Ag}^{+}\): Remove 1 electron, prioritize the 5s shell: [Kr]5s鈦4d鹿0 = [Kr]4d鹿0 e) \(\mathrm{S}^{2-}\): Add 2 electrons to the 3p shell: [Ne]3s虏3p鈦
03

Identify ions with noble-gas configurations.

Now we can compare the ion configurations to the electron configuration of the nearest noble gases. a) \(\mathrm{Co}^{2+}\): [Ar]3d鈦 - not a noble gas configuration b) \(\mathrm{Sn}^{2+}\): [Kr]4d鹿0 - not a noble gas configuration c) \(\mathrm{Zr}^{4+}\): [Kr] - noble gas configuration d) \(\mathrm{Ag}^{+}\): [Kr]4d鹿0 - not a noble gas configuration e) \(\mathrm{S}^{2-}\): [Ne]3s虏3p鈦 = [Ar] - noble gas configuration The ions with noble gas configurations are \(\mathrm{Zr}^{4+}\) and \(\mathrm{S}^{2-}\), as they have electron configurations similar to noble gases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Noble Gas Configuration
The noble gas configuration is a way of writing the electron configuration of an element that highlights the similarity to the electron arrangement of a noble gas. Noble gases, such as helium (He), neon (Ne), and argon (Ar), are found in group 18 of the periodic table and are known for their full outer electron shells, making them highly stable.
Using the noble gas notation, electron configurations start by noting the noble gas that precedes the element on the periodic table in brackets. This concise form allows us to focus on the valence electrons, which play a significant role in chemical reactions.
For example, sulfur's electron configuration is [Ne]3s虏3p鈦. When it gains two electrons to form ext{S}^{2-}, it has the same electronic configuration as argon, a noble gas, thus achieving a stable noble gas configuration. This stability is a common goal in chemical reactions and ion formation.
Ions
Ions are atoms or molecules that have gained or lost one or more electrons, giving them a net electrical charge. This process can result in either positive ions (cations) or negative ions (anions).
When an atom loses electrons and forms a cation, it has more protons than electrons, which results in a positive charge. Common examples include ext{Na}^{+} and ext{Ca}^{2+}.
Conversely, when an atom gains electrons and forms an anion, it gains a negative charge due to having more electrons than protons. Examples of anions include ext{Cl}^{-} and ext{O}^{2-}.
The formation of ions is a crucial concept in chemistry, as it explains the behavior of elements during chemical reactions. Ions are important in many natural processes and technological applications, such as the conduction of electricity in solutions and biological functions.
Electron Removal and Addition
Electron removal and addition are essential processes in forming ions. In electron removal, electrons are taken away from their shells, typically starting from the outermost shell, to form positively charged ions (cations).
For instance, when cobalt loses two electrons to form ext{Co}^{2+}, the electrons are removed mainly from the 4s shell, resulting in the electron configuration [Ar]3d鈦.
In contrast, electron addition involves adding electrons to an atom's outer shells, leading to negatively charged ions (anions).
Sulfur gaining two electrons to become ext{S}^{2-} is an example, and its electron configuration changes from [Ne]3s虏3p鈦 to a stable noble gas configuration [Ne]3s虏3p鈦.
These changes in electron configurations explain the stability achieved by elements when they reach configurations similar to noble gases, often the motivation behind ion formation.
Atomic Structure
Understanding atomic structure is fundamental to grasping the behavior of elements and their ions. Atoms consist of a nucleus containing protons and neutrons, surrounded by electrons in various shells or energy levels.
The number of protons defines the element and is always equal to the atomic number. Electrons are arranged in shells around the nucleus, following rules that dictate the maximum number of electrons each shell can hold.
Electrons fill lower energy (inner) shells first before occupying higher energy (outer) shells. The arrangement of electrons is depicted in the electron configuration, which influences how elements interact with each other.
In ion formation, electron configurations change but the nucleus remains unaffected, ensuring the identity of the element is retained. This behavior is crucial for understanding chemical reactions, bonding, and other properties of matter.

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Most popular questions from this chapter

Discussing this chapter, a classmate says, "Since elements that form cations are metals and elements that form anions are nonmetals, elements that do not form ions are metalloids." Do you agree or disagree? Explain your answer.

Although the electron affinity of bromine is a negative quantity, it is positive for Kr. Use the electron configurations of the two elements to explain the difference.

Note from the following table that there is a significant increase in atomic radius upon moving from \(\mathrm{Y}\) to La whereas the radii of \(\mathrm{Zr}\) to \(\mathrm{Hf}\) are the same. Suggest an explanation for this effect. $$ \begin{array}{llll} \hline & {\text { Atomic Radii (脜) }} \\ \hline \mathrm{Sc} & 1.70 & \mathrm{Ti} & 1.60 \\ \mathrm{Y} & 1.90 & \mathrm{Zr} & 1.75 \\ \mathrm{La} & 2.07 & \text { Hf } & 1.75 \\ \hline \end{array} $$

Discussing this chapter, a classmate says, "An element that commonly forms a cation is a metal." Do you agree or disagree? Explain your answer.

(a) Which ion is smaller, \(\mathrm{Co}^{3+}\) or \(\mathrm{Co}^{4+}\) ? (b) In a lithium-ion battery that is discharging to power a device, for every \(\mathrm{Li}^{+}\)that inserts into the lithium cobalt oxide electrode, \(\mathrm{a} \mathrm{Co}^{4+}\) ion must be reduced to \(\mathrm{Co}^{3+}\) ion to balance charge. Using the \(C R C\) Handbook of Chemistry and Physics or other standard reference, find the ionic radii of \(\mathrm{Li}^{+}, \mathrm{Co}^{3+}\), and \(\mathrm{Co}^{4+}\). Order these ions from smallest to largest. (c) Will the lithium cobalt electrode expand or contract as lithium ions are inserted? (d) Lithium is not nearly as abundant as sodium. If sodium ion batteries were developed that function as lithium ion ones, do you think "sodium cobalt oxide" would still work as the electrode material? Explain. (e) If you don't think cobalt would work as the redox-active partner ion in the sodium version of the electrode, suggest an alternative metal ion and explain your reasoning.

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