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Moseley established the concept of atomic number by studying X rays emitted by the elements. The \(X\) rays emitted by some of the elements have the following wavelengths: $$ \begin{array}{lc} \hline \text { Element } & \text { Wavelength } \\ \hline \mathrm{Ne} & 14.610 \\ \mathrm{Ca} & 3.358 \\ \mathrm{Zn} & 1.435 \\ \mathrm{Zr} & 0.786 \\ \mathrm{Sn} & 0.491 \\ \hline \end{array} $$ (a) Calculate the frequency, \(\nu\), of the \(\mathrm{X}\) rays emitted by each of the elements, in Hz. (b) Plot the square root of \(\nu\) versus the atomic number of the element. What do you observe about the plot? (c) Explain how the plot in part (b) allowed Moseley to predict the existence of undiscovered elements. (d) Use the result from part (b) to predict the \(\mathrm{X}\)-ray wavelength emitted by iron. (e) A particular element emits X rays with a wavelength of \(0.980 \AA\). What element do you think it is?

Short Answer

Expert verified
The relationship between the square root of frequency and the atomic number of the elements is linear. Moseley used this linear relationship to predict the existence of undiscovered elements by identifying gaps in the sequence. By analyzing the given data, we can predict the X-ray wavelength emitted by iron and identify an element based on its X-ray wavelength.

Step by step solution

01

Calculate the frequency of X-rays

First, we need to calculate the frequency of X-rays emitted by each element. The formula to convert wavelength to frequency is given by: \(ν = \dfrac{c}{λ}\), where \(ν\) is the frequency, \(c\) is the speed of light (\(3.0 \times 10^8 m/s\)), and \(λ\) is the wavelength of the X-ray. Now, for each element, we can calculate the frequency using the given wavelength.
02

Calculate the square root of frequency

After finding the frequency for each element, we have to calculate the square root of these frequencies. Using a calculator, find the square root of each calculated frequency.
03

Plot the relationship

Create a graph, with the atomic number of the elements on the x-axis and the square root of the frequency on the y-axis. Plot the values of the square root of frequency for each element and analyze the relationship.
04

Analyze the relationship

Observe the plotted graph to analyze the relationship between the square root of frequency and the atomic number. You will notice that as the atomic number increases, the square root of frequency also increases.
05

Explain the plot

The plot in part (b) shows a linear relationship between the square root of frequency and the atomic number of the elements. Moseley was able to predict the existence of undiscovered elements because if there were a missing element in the sequence, there would be a gap in the plot. By analyzing the plot, Moseley was able to predict where undiscovered elements would fit in the sequence.
06

Predict an X-ray wavelength

In part (d), we are asked to predict the X-ray wavelength emitted by iron. First, find the atomic number of iron (which is 26). Now, use the relationship between the square root of frequency and the atomic number derived from the plot to predict the square root of the frequency for iron. Next, to find the frequency of iron, square the value obtained for the square root of frequency. Finally, use the formula \(λ = \dfrac{c}{ν}\) to calculate the wavelength of X-ray emission for iron.
07

Identify the element

In part (e), we are given the X-ray wavelength for a particular element (0.980 Angstroms). First, convert the wavelength to meters. Then, using the formula \(ν = \dfrac{c}{λ}\), calculate the frequency for the given wavelength. Next, find the square root of the frequency and use the relationship between the square root of frequency and the atomic number found in the plot to predict the atomic number of the element. Lastly, identify the element corresponding to the predicted atomic number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The atomic number is a fundamental concept in chemistry and physics, representing the number of protons found in the nucleus of an atom. It is a unique identifier for elements, differentiating one element from another. Moseley, through his pioneering work on X-ray spectroscopy, established the theoretical and empirical significance of the atomic number.
  • Each element has a unique atomic number, denoting the number of protons and thus positively charged units in its core.
  • This number also directly influences the elemental properties, solidsation state, and chemical behavior.
  • Moseley's Law demonstrated that the square root of the frequency of X-ray emissions from an element is directly proportional to its atomic number.
Thus, the atomic number has become crucial in arranging elements in the periodic table. Before Moseley’s work, elements were primarily ordered by atomic weight, which led to inconsistencies.
X-ray Spectroscopy
X-ray spectroscopy is a technique used to study the properties of elements through the analysis of their X-ray emissions. This method played a vital role in Moseley’s discoveries.
  • When elements are hit with high energy, they emit X-rays at characteristic wavelengths.
  • X-ray spectroscopy measures these wavelengths to determine an element’s specific structure and characteristics.
  • Moseley noted that the emitted X-ray frequency from each element varied systematically with the atomic number.
This technique provided a new way to study the inner structure of atoms, leading to more precise and accurate predictions of new elements. Moseley's findings also further validated the utility of the atomic number beyond ordering elements.
Frequency Calculation
Frequency calculation is essential for understanding X-ray emissions according to Moseley's Law. This calculation involves converting the measured wavelength of X-rays into frequency, using the well-known equation:
\[ν = \dfrac{c}{λ}\]where:
  • \(ν\) = frequency of the X-rays
  • \(c\) = speed of light, approximately \(3.0 \times 10^8\) meters per second
  • \(λ\) = wavelength of the emitted X-ray
This calculation is a crucial step as understanding the frequency helps in visualizing the relationship seen in Moseley’s plot of square root frequency versus atomic number. This mathematical process assists in determining elemental properties and inferences about undiscovered elements.
Undiscovered Elements Prediction
Moseley’s Law significantly contributed to the prediction of undiscovered elements. By using the relationship between X-ray frequency and atomic number, gaps in the periodic table were identified.
  • Plotting the atomic number against the square root of frequency showed a linear relationship.
  • This clear and consistent relationship suggested the presence of known anomalies, predicting where elements should exist yet had not been discovered.
  • If there was a missing or unexpected gap, Moseley could hypothesize that an unknown element filled this space.
Moseley’s work allowed chemists and physicists to refine the periodic table, driving the search for new elements, and enhancing our understanding of atomic structure.

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Most popular questions from this chapter

(a) What is the trend in first ionization energies as one proceeds down the group 7A elements? Explain how this trend relates to the variation in atomic radii. (b) What is the trend in first ionization energies as one moves across the fourth period from \(\mathrm{K}\) to \(\mathrm{Kr}\) ? How does this trend compare with the trend in atomic radii?

Some ions do not have a corresponding neutral atom that has the same electron configuration. For each of the following ions, identify the neutral atom that has the same number of electrons and determine if this atom has the same electron configuration. If such an atom does not exist, explain why. (a) \(\mathrm{Cl}^{-}\), (b) \(\mathrm{Sc}^{3+}\), (c) \(\mathrm{Fe}^{2+}\), (d) \(\mathrm{Zn}^{2+}\), (e) \(\mathrm{Sn}^{4+}\).

Consider the following equation: $$ \mathrm{Ca}^{+}(g)+\mathrm{e}^{-} \longrightarrow \mathrm{Ca}(g) $$ Which of the following statements are true? (i) The energy change for this process is the electron affinity of the \(\mathrm{Ca}^{+}\)ion. (ii) The energy change for this process is the negative of the first ionization energy of the Ca atom. (iii) The energy change for this process is the negative of the electron affinity of the \(\mathrm{Ca}\) atom.

Consider the \(\mathrm{A}_{2} \mathrm{X}_{4}\) molecule depicted here, where \(\mathrm{A}\) and \(\mathrm{X}\) are elements. The A-A bond length in this molecule is \(d_{1}\), and the four \(\mathrm{A}-\mathrm{X}\) bond lengths are each \(d_{2}\). (a) In terms of \(d_{1}\) and \(d_{2}\), how could you define the bonding atomic radii of atoms \(\mathrm{A}\) and \(\mathrm{X}\) ? (b) In terms of \(d_{1}\) and \(d_{2}\), what would you predict for the \(\mathrm{X}-\mathrm{X}\) bond length of an \(\mathrm{X}_{2}\) molecule? [Section 7.3]

Elements in group 7A in the periodic table are called the halogens; elements in group \(6 \mathrm{~A}\) are called the chalcogens. (a) What is the most common oxidation state of the chalcogens compared to the halogens? (b) For each of the following periodic properties, state whether the halogens or the chalcogens have larger values: atomic radii, ionic radii of the most common oxidation state, first ionization energy, second ionization energy.

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