/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 What is the maximum number of el... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the maximum number of electrons in an atom that can have the following quantum numbers? (a) \(n=3, m_{l}=-2 ;\) (b) \(n=4\), \(l=3 ;(\mathrm{c}) n=5, l=3, m_{l}=2,(\mathrm{~d}) n=4, l=1, m_{l}=0\).

Short Answer

Expert verified
The maximum number of electrons for each given set of quantum numbers is as follows: a) 2 electrons b) 14 electrons c) 2 electrons d) 2 electrons

Step by step solution

01

a) \(n=3\), \(m_l=-2\)

The given quantum numbers are \(n=3\) and \(m_l=-2\). Since there are no restrictions on the value of \(l\) and \(m_s\), Possible values of \(l\): \(0, 1, 2\) Possible values of \(m_s\): \(-1/2\), \(1/2\) Thus, the maximum number of electrons for the given values of \(n\) and \(m_l\) is 2.
02

b) \(n=4\), \(l=3\)

The given quantum numbers are \(n=4\) and \(l=3\). For \(l=3\), the possible values of \(m_l\) are \(-3, -2, -1, 0, 1, 2, 3\). Each of these \(m_l\) values can have two \(m_s\) values, namely \(-1/2\) and \(1/2\). Thus, the maximum number of electrons for the given values of \(n\) and \(l\) is \(7 \times 2 = 14\).
03

c) \(n=5\), \(l=3\), \(m_l=2\)

The given quantum numbers are \(n=5\), \(l=3\), and \(m_l=2\). Since \(m_l\) and \(l\) are specified, there is no freedom to choose other values. The only remaining quantum number is \(m_s\), which can be either \(-1/2\) or \(1/2\). Thus, the maximum number of electrons for the given values of \(n\), \(l\), and \(m_l\) is 2.
04

d) \(n=4\), \(l=1\), \(m_l=0\)

The given quantum numbers are \(n=4\), \(l=1\), and \(m_l=0\). Since both \(l\) and \(m_l\) have specified values, there is no freedom to choose other values. The only remaining quantum number is \(m_s\), which can be either \(-1/2\) or \(1/2\). Thus, the maximum number of electrons for the given values of \(n\), \(l\), and \(m_l\) is 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Orbitals
Understanding atomic orbitals is fundamental in exploring the arrangement of electrons within atoms. Orbitals are regions within an atom where there is a high probability of finding an electron. Each orbital corresponds to specific energy levels denoted by the quantum number 'n'.

For any value of the principal quantum number, 'n', there are 'n^2' orbitals. For instance, if 'n=3', there are 3^2, that is 9 orbitals in total. These orbitals are further categorized based on the angular quantum number 'l', which ranges from 0 to 'n-1' and designates the shape of the orbital, commonly known as 's', 'p', 'd', or 'f'.

The magnetic quantum number 'm_l', another crucial aspect, determines the orientation of the orbital in space and takes on values from '-l' to '+l', including zero. Therefore, for an orbital where 'n=3' and 'l=2' (a 'd' orbital), 'm_l' can be -2, -1, 0, 1, or 2, each orientation hosting up to 2 electrons due to electron spin—described by the spin quantum number 'm_s', which can be either -1/2 or +1/2.
Electron Configuration
Electron configuration outlines how electrons are distributed among the atomic orbitals in an atom. It follows the Pauli Exclusion Principle, which states that no two electrons can have the identical set of four quantum numbers. As a result, each electron in an atom has a unique 'address' consisting of 'n', 'l', 'm_l', and 'm_s'.

The arrangement of electrons starts with the lowest energy level, gradually filling up to higher levels—a process described by the Aufbau principle. Notably, the sublevels within a principal energy level can be of different energies, with 's' being the lowest, followed by 'p', then 'd', and 'f' respectively.

When looking at quantum numbers to determine the maximum number of electrons, for example in the case of 'n=4, l=3', this implies an 'f' orbital at the fourth energy level. Since 'l=3', the values of 'm_l' range from -3 to +3, making a total of 7 possible orientations, each capable of holding 2 electrons accounting for spins, resulting in a maximum of 14 electrons for this condition.
Quantum Mechanical Model
The quantum mechanical model of the atom presents a sophisticated framework for understanding atomic and subatomic behaviors. It portrays electrons not as particles in fixed orbits but as wave-like entities in orbitals with calculated probabilities of their presence at any given point.

This model is defined by the set of four quantum numbers: principal (n), angular momentum (l), magnetic (m_l), and spin (m_s), each detailing different characteristics and restrictions for electron placement within the atom. Together, they give an electron its unique state and help chemists predict chemical and physical properties of elements.

In exercises asking for the maximum number of electrons with specific quantum numbers, we apply all these principles. For example, given 'n=5, l=3, m_l=2', it specifies a single 'f' orbital at the fifth energy level, with a fixed orientation. With only two possible spin states, the maximum number of electrons here is restricted to just 2, reflecting the exclusivity and specificity imparted by quantum numbers in the realm of quantum mechanics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The first 25 years of the twentieth century were momentous for the rapid pace of change in scientists' understanding of the nature of matter. (a) How did Rutherford's experiments on the scattering of \(\alpha\) particles by a gold foil set the stage for Bohr's theory of the hydrogen atom? (b) In what ways is de Broglie's hypothesis, as it applies to electrons, consistent with J. J. Thomson's conclusion that the electron has mass? In what sense is it consistent with proposals preceding Thomson's work that the cathode rays are a wave phenomenon?

If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing orange-yellow. The light is emitted because sodium ions in the pickle become excited; their return to the ground state results in light emission. (a) The wavelength of this emitted light is \(589 \mathrm{~nm}\). Calculate its frequency. (b) What is the energy of \(0.10 \mathrm{~mol}\) of these photons? (c) Calculate the energy gap between the excited and ground states for the sodium ion. (d) If you soaked the pickle for a long time in a different salt solution, such as strontium chloride, would you still observe \(589-\mathrm{nm}\) light emission?

In the experiment shown schematically below, a beam of neutral atoms is passed through a magnetic field. Atoms that have unpaired electrons are deflected in different directions in the magnetic field depending on the value of the electron spin quantum number. In the experiment illustrated, we envision that a beam of hydrogen atoms splits into two beams. (a) What is the significance of the observation that the single beam splits into two beams? (b) What do you think would happen if the strength of the magnet were increased? (c) What do you think would happen if the beam of hydrogen atoms were replaced with a beam of helium atoms? Why? (d) The relevant experiment was first performed by Otto Stern and Walter Gerlach in 1921 . They used a beam of Ag atoms in the experiment. By considering the electron configuration of a silver atom, explain why the single beam splits into two beams.

Using the periodic table as a guide, write the condensed electron configuration and determine the number of unpaired electrons for the ground state of (a) \(\mathrm{Br}\), (b) Ga, (c) Hf, (d) Sb, (e) Bi, (f) Sg.

Microwave ovens use microwave radiation to heat food. The energy of the microwaves is absorbed by water molecules in food and then transferred to other components of the food. (a) Suppose that the microwave radiation has a wavelength of \(11.2 \mathrm{~cm}\). How many photons are required to heat \(200 \mathrm{~mL}\) of coffee from 23 to \(60^{\circ} \mathrm{C}\) ? (b) Suppose the microwave's power is \(900 \mathrm{~W}\) ( 1 watt \(=1\) joule-second). How long would you have to heat the coffee in part (a)?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.