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A certain orbital of the hydrogen atom has \(n=4\) and \(l=2\). (a) What are the possible values of \(m_{l}\) for this orbital? (b) What are the possible values of \(m_{s}\) for the orbital?

Short Answer

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(a) The possible values of \(m_l\) for this orbital are -2, -1, 0, 1, and 2. (b) The possible values of \(m_s\) for the orbital are +1/2 and -1/2.

Step by step solution

01

(a) Finding possible values of \(m_l\)

The magnetic quantum number \(m_l\) describes the orientation of the orbital in space. It can take on integer values ranging from -l to +l. We are given that l=2 for this orbital, so we need to find the possible values of \(m_l\) within this range. In this case, the possible values of \(m_l\) are -2, -1, 0, 1, and 2.
02

(b) Finding possible values of \(m_s\)

The spin magnetic quantum number \(m_s\) describes the orientation of the electron's spin within the orbital. It can take on two possible values: +1/2 and -1/2. These values correspond to the spin-up and spin-down states of the electron, respectively. Therefore, the possible values of \(m_s\) for this orbital are +1/2 and -1/2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Numbers
When dealing with electrons in atoms, especially hydrogen atoms, quantum numbers are critical as they help define the unique state of an electron. There are four main quantum numbers which describe the energy level, shape, orientation, and spin of the orbital where the electron resides.

1. **Principal Quantum Number ("):** This is the first quantum number and signifies the electron shell or energy level, denoted by "n". For example, if \( n = 4 \), it indicates the electron is in the fourth energy level. The larger the value of \( n \), the farther the electron is from the nucleus and the higher its energy level.2. **Azimuthal Quantum Number (")/Angular Momentum Quantum Number ("):** Represented by "l", this number defines the shape of the orbital. Allowed values of \( l \) range from 0 up to \( n-1 \). For example, with \( l = 0 \) through \( l = 3 \), these correspond to s, p, d, and f orbital shapes, respectively. In our case, \( l = 2 \) describes a "d" orbital.Together, these quantum numbers help paint a more vivid picture of an electron's probable location around a nucleus, aiding in our understanding of atomic interactions.
Magnetic Quantum Number
The magnetic quantum number, denoted as \( m_l \), provides more specific information about the orientation of the orbital in space.

For an electron in an orbital with a given \( l \, ( \text{angular momentum quantum number} ) \), \( m_l \) takes integer values from \( -l \) to \( +l \). Therefore, it essentially describes how an orbital is oriented in the three-dimensional space around the nucleus.

For example, if \( l = 2 \) like in our hydrogen atom problem, the potential values of \( m_l \) can be:
  • \( m_l = -2 \)
  • \( m_l = -1 \)
  • \( m_l = 0 \)
  • \( m_l = +1 \)
  • \( m_l = +2 \)
These different values indicate the different orientations the "d" orbital can have in space. Understanding \( m_l \) is crucial as it helps us comprehend how electron clouds are distributed within magnetic fields or in atomic arrangements.
Spin Magnetic Quantum Number
The spin magnetic quantum number, noted as \( m_s \), is unique among the quantum numbers as it describes the electron's intrinsic spin rather than aspects of the orbital itself.

Electrons are known to have a fundamental property called "spin," which can be thought of as an angular momentum intrinsic to the electron. Despite being tiny point-like particles, electrons behave like tiny bar magnets. Therefore, \( m_s \) defines the orientation of this spin.Possible values for \( m_s \) are:
  • \( +\frac{1}{2} \) (spin-up)
  • \( -\frac{1}{2} \) (spin-down)
These two possible values allow each orbital to hold a maximum of two electrons, each with opposite spins. The spin property is crucial for understanding the Pauli exclusion principle, which dictates that no two electrons in an atom can have identical sets of quantum numbers, and plays a vital role in forming chemical bonds and magnetic properties of materials.

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Most popular questions from this chapter

The visible emission lines observed by Balmer all involved \(n_{\mathrm{f}}=2\). (a) Which of the following is the best explanation of why the lines with \(n_{\mathrm{f}}=3\) are not observed in the visible portion of the spectrum: (i) Transitions to \(n_{\mathrm{f}}=3\) are not allowed to happen, (ii) transitions to \(n_{\mathrm{f}}=3\) emit photons in the infrared portion of the spectrum, (iii) transitions to \(n_{\mathrm{f}}=3\) emit photons in the ultraviolet portion of the spectrum, or (iv) transitions to \(n_{\mathrm{f}}=3\) emit photons that are at exactly the same wavelengths as those to \(n_{\mathrm{f}}=2\). (b) Calculate the wavelengths of the first three lines in the Balmer series-those for which \(n_{\mathrm{i}}=3,4\), and 5 -and identify these lines in the emission spectrum shown in Figure 6.11.

Write the condensed electron configurations for the following atoms, using the appropriate noble-gas core abbreviations: (a) Cs, (b) Ni, (c) \(\mathrm{Se}\), (d) \(\mathrm{Cd}\), (e) \(\mathrm{U}\), (f) \(\mathrm{Pb}\).

(a) What is the frequency of radiation whose wavelength is \(0.86 \mathrm{~nm}\) ? (b) What is the wavelength of radiation that has a frequency of \(6.4 \times 10^{11} \mathrm{~s}^{-1}\) ? (c) Would the radiations in part (a) or part (b) be detected by an X-ray detector? (d) What distance does electromagnetic radiation travel in \(0.38 \mathrm{ps}\) ?

Which of the following represent impossible combinations of \(n\) and \(l\) ? (a) \(1 p\), (b) \(4 s\), (c) \(5 f\), (d) \(2 d\)

The discovery of hafnium, element number 72 , provided a controversial episode in chemistry. G. Urbain, a French chemist, claimed in 1911 to have isolated an element number 72 from a sample of rare earth (elements 58-71) compounds. However, Niels Bohr believed that hafnium was more likely to be found along with zirconium than with the rare earths. D. Coster and G. von Hevesy, working in Bohr's laboratory in Copenhagen, showed in 1922 that element 72 was present in a sample of Norwegian zircon, an ore of zirconium. (The name hafnium comes from the Latin name for Copenhagen, Hafnia). (a) How would you use electron configuration arguments to justify Bohr's prediction? (b) Zirconium, hafnium's neighbor in group \(4 \mathrm{~B}\), can be produced as a metal by reduction of solid \(\mathrm{ZrCl}_{4}\) with molten sodium metal. Write a balanced chemical equation for the reaction. Is this an oxidation-reduction reaction? If yes, what is reduced and what is oxidized? (c) Solid zirconium dioxide, \(\mathrm{ZrO}_{2}\), reacts with chlorine gas in the presence of carbon. The products of the reaction are \(\mathrm{ZrCl}_{4}\) and two gases, \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) in the ratio \(1: 2\). Write a balanced chemical equation for the reaction. Starting with a 55.4-g sample of \(\mathrm{ZrO}_{2}\), calculate the mass of \(\mathrm{ZrCl}_{4}\) formed, assuming that \(\mathrm{ZrO}_{2}\) is the limiting reagent and assuming \(100 \%\) yield. (d) Using their electron configurations, account for the fact that \(\mathrm{Zr}\) and \(\mathrm{Hf}\) form chlorides \(\mathrm{MCl}_{4}\) and oxides \(\mathrm{MO}_{2}\).

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