/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 (a) What is the relationship bet... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) What is the relationship between the wavelength and the frequency of radiant energy? (b) Ozone in the upper atmosphere absorbs energy in the \(210-230-\mathrm{nm}\) range of the spectrum. In what region of the electromagnetic spectrum does this radiation occur?

Short Answer

Expert verified
(a) The relationship between wavelength (\(\lambda\)) and frequency (\(\nu\)) of radiant energy is inversely proportional, given by the formula \(\nu = \frac{c}{\lambda}\) or \(\lambda = \frac{c}{\nu}\), where \(c\) is the speed of light in a vacuum (\(3.00 \times 10^8 \mathrm{m/s}\)). (b) The wavelength range \(210-230 \mathrm{nm}\) falls under the ultraviolet region of the electromagnetic spectrum, as it is between \(400 \mathrm{nm}\) and \(10 \mathrm{nm}\).

Step by step solution

01

Part (a): Relationship between wavelength and frequency

The relationship between wavelength (\(\lambda\)) and frequency (\(\nu\)) of radiant energy (electromagnetic waves) is given by the following formula: \[ c = \lambda \nu \] where `c` is the speed of light in a vacuum, approximately equal to \(3.00 \times 10^8 \mathrm{m/s}\). To express the relationship between the wavelength and frequency, you can rearrange the equation as follows: \[ \nu = \frac{c}{\lambda} \] or \[ \lambda = \frac{c}{\nu} \] This relationship shows that as the wavelength increases, the frequency decreases, and vice versa. They are inversely proportional.
02

Part (b): Region of the electromagnetic spectrum

The electromagnetic spectrum is divided into various regions, based on the wavelength or frequency of the radiation. Given the wavelength range \(210-230 \mathrm{nm}\), we want to determine the region it falls under in the electromagnetic spectrum. Below are the regions and their respective wavelength ranges: 1. Radio waves: \(\lambda > 1 \mathrm{m}\) 2. Microwaves: \(1 \mathrm{m} > \lambda > 1 \mathrm{mm}\) 3. Infrared: \(1 \mathrm{mm} > \lambda > 700 \mathrm{nm}\) 4. Visible light: \(700 \mathrm{nm} > \lambda > 400 \mathrm{nm}\) 5. Ultraviolet: \(400 \mathrm{nm} > \lambda > 10 \mathrm{nm}\) 6. X-rays: \(10 \mathrm{nm} > \lambda > 0.01 \mathrm{nm}\) 7. Gamma rays: \(\lambda < 0.01 \mathrm{nm}\) The given wavelength range of \(210-230 \mathrm{nm}\) falls under the ultraviolet region of the electromagnetic spectrum, as it is between \(400 \mathrm{nm}\) and \(10 \mathrm{nm}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each of the following sets of quantum numbers for the hydrogen atom are valid. If a set is not valid, indicate which of the quantum numbers has a value that is not valid: (a) \(n=4, l=1, m_{l}=2, m_{s}=-\frac{1}{2}\) (b) \(n=4, l=3, m_{l}=-3, m_{s}=+\frac{1}{2}\) (c) \(n=3, l=2, m_{l}=-1, m_{s}=+\frac{1}{2}\) (d) \(n=5, l=0, m_{l}=0, m_{s}=0\) (e) \(n=2, l=2, m_{l}=1, m_{s}=+\frac{1}{2}\)

(a) Consider the following three statements: (i) A hydrogen atom in the \(n=3\) state can emit light at only two specific wavelengths, (ii) a hydrogen atom in the \(n=2\) state is at a lower energy than the \(n=1\) state, and (iii) the energy of an emitted photon equals the energy difference of the two states involved in the emission. Which of these statements is or are true? (b) Does a hydrogen atom "expand" or "contract" as it moves from its ground state to an excited state?

The electron microscope has been widely used to obtain highly magnified images of biological and other types of materials. When an electron is accelerated through a particular potential field, it attains a speed of \(9.47 \times 10^{6} \mathrm{~m} / \mathrm{s}\). What is the characteristic wavelength of this electron? Is the wavelength comparable to the size of atoms?

Calculate the uncertainty in the position of (a) an electron moving at a speed of \((3.00 \pm 0.01) \times 10^{5} \mathrm{~m} / \mathrm{s},(\mathbf{b})\) a neutron moving at this same speed. (The masses of an electron and a neutron are given in the table of fundamental constants in the inside cover of the text.) (c) Based on your answers to parts (a) and (b), which can we know with greater precision, the position of the electron or of the neutron?

Consider a transition of the electron in the hydrogen atom from \(n=4\) to \(n=9\). (a) Is \(\Delta E\) for this process positive or negative? (b) Determine the wavelength of light that is associated with this transition. Will the light be absorbed or emitted? (c) In which portion of the electromagnetic spectrum is the light in part (b)?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.