/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Pure acetic acid, known as glaci... [FREE SOLUTION] | 91影视

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Chapter 4: Problem 77

Pure acetic acid, known as glacial acetic acid, is a liquid with a density of \(1.049 \mathrm{~g} / \mathrm{mL}\) at \(25^{\circ} \mathrm{C}\). Calculate the molarity of a solution of acetic acid made by dissolving \(20.00 \mathrm{~mL}\) of glacial acetic acid at \(25^{\circ} \mathrm{C}\) in enough water to make \(250.0 \mathrm{~mL}\) of solution.

Short Answer

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= 20.98 g #tag_title# Step 2: Calculate the moles of acetic acid#tag_content# Now, we can calculate the number of moles of acetic acid using the formula moles = mass / molar mass. Molar mass of acetic acid (CH鈧僀OOH) = 12.01 (C) + 4.03 (H) + 16.00 (O) 脳 2 = 60.05 g/mol Moles of acetic acid = (20.98 g) / (60.05 g/mol) = 0.349 moles #tag_title# Step 3: Calculate the molarity#tag_content# Finally, we can calculate the molarity using the formula molarity = moles / volume (in L). Volume of the solution = 250.0 mL = 0.250 L Molarity of the acetic acid solution = (0.349 moles) / (0.250 L) = 1.396 mol/L So, the molarity of the acetic acid solution is approximately \(1.396 \mathrm{~mol/L}\).

Step by step solution

01

Calculate the mass of acetic acid

We know the volume and density of the acetic acid, so we can calculate the mass using the formula mass = volume 脳 density. Density of glacial acetic acid = 1.049 g/mL Volume of glacial acetic acid = 20.00 mL Mass of acetic acid = (1.049 g/mL) 脳 (20.00 mL)

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